Catalytic efficiency (kcat/km) and turn over number of enzyme
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- Опубліковано 16 сер 2024
- This lecture explains about the catalytic efficiency and turnover number of enzyme and it also explains how to calculate enzyme catalytic efficiency and turnover number. Catalytic efficiency calculation is really important to understand how an enzyme functions along with the turnover number that says many information about the efficiency of the enzyme and the affinity of the enzyme in binding substrate.
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Thank you for watching this biochemistry lecture on catalytic efficiency and turnover number of enzyme reactions.
A 1% (w/v) solution of a sugar polymer is digested by an enzyme (20ug, MW = 200,000). The rate of monomer sugar (MW = 400) liberated was determined to have a maximal initial velocity of 100 mg formed/ min. The turnover number (min -1) will be:
thank you soooooooooooooooooo much... You are my angel in Biochemistry.... Brrrrrrrrravo gentleman!!!!!!!!!!!!!!!!!!!
Thank you so much for appreciating my efforts
thank you sir
You're welcome
Sir, I'm watching your videos since you started making them and your work is always awesome!
You've a great ability to define any difficult topic in a very easy and lucid way....
Love you, for your work!
+Atahar Mahmood glad to hear that. Please subscribe and share
Subscribed already.
Thank you so much sir for making us understand the Kcat/Km relation at variable substrate concentration and variable Km in a much easier way.But if you will describe the above relation theoretically in a detail way ,I will be very thankful to you.
love you bro, could not understand this since many yrz
Thank you. Glad you liked my lecture
You are the best ...
I once listen ur video and simply wrote in exam without any book and I get 80% ..
U are great sir!!!!
Thank you for watching the lecture
thank you so much Sir it was really really helpful
You're welcome
thank you so much sir... now I know how to calculate km and Vmax
Thank u so much sir🙏😊..it was worth listening 😊
You're welcome. Glad to hear that you're getting benefit from my lectures
@@shomusbiologyofficial just replying girls 😄 🤣 😂 😆
Great job. Perfect science teacher.
Sir how to calculate Kcat from catalytic experiment?
A solution of 1%(w/v) starch at ph 6.7 is digested by 15ug of amylase (mol wt 152,000). The rate of maltose(mol wt=342) had a maximal initial velocity of 8.5 mg formed per min. What is the turnover number...?
Can you please calculate this..?
greetings sir . we thanks you for your teaching. please I have a question to ask.
please can u make a video on the differences between the Michaelis menten approach and the Brigg Haldane approach of enzyme kinetics. I can't really see a difference btw this two approaches
Thankyou so much sir . Please answer my question sir i will be very thankful to you , "will high affinity of enzymes for substrate means Initial Velocity is high "
is this right or not ?
Yes
@@shomusbiologyofficial right sir
Thank u so much sir
You're welcome
Bro saying something else and writing something else at few point which one i should follow?
Cuánto de Km y Kd se necesita para tener el 99% de actividad enzimática?
what is the importance of saturation in turnover number
thanks for the videos sir... yes i have already subscribed your channel
Sir it would be of great help if you can discuss part -C csir net ls previous years questions ....
Q_ If an enzyme breaks 3 Lac moles of substrate in a second. What will be its turnover numbers? Plzzz reply
Its good one.
+Ishani Deka thank you. Glad you liked my lectures
great
can i ask any question
Derry
Sir your other videos are useful
But I find this video is waste of time
Why?
waste of time....