Given right triangle ABC, as you right triangle. Side a=6, b=8 and c= 10 Find the six trigonometric ratios of the given right triangle sin∅ = 6/10 cos∅ = 8/10 tan∅ = 6/8 csc∅ = 5/3 sec∅ = 5/4 cot∅ = 4/3
Given right triangle ABC, C as your right triangle. Side a= 6, b= 8, and c= 10. Find the six trigonometric ratios of the given right triangle. sin= 3/5 cos= 4/5 tan= 3/4 csc= 5/3 sec= 5/4 cot= 4/3
Given right triangle ABC, C as your right triangls. Side A = 6 ; Side B = 8 ; Side C = 10 • A N S W E R S • sinθ = 3/5 cosθ = 4/5 tanθ = 3/4 cscθ = 5/3 secθ = 5/4 cotθ = 4/3
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. Sin= 6/10 or 3/5 Cos=8/10 or 4/5 Tan=6/8 or 3/4 Csc=10/6 or 5/3 Sec=10/8 or 5/4 Cot=8/6 or 4/3
Given right triangle ABC , C as your right triangle. Side a=6 , b=8 and c=10. Find the six trigonometric ratios of the given right triangle. sin = 3/5 cos = 4/5 tan = 3/4 csc = 5/3 sec = 5/4 cot = 4/3
Sin ø =3/5. Csc ø =5/3 = 1 2/3 Cos ø =4/5 Sec ø =5/4 = 1 1/4 Tan ø =3/4. Cot ø =4/3 = 1 1/3 Hello Sir, ngayon ku lang tlga naintindhan po lahat. Pa correct po kung tama po ba sagot ko lalo na Csc ø, Sec ø & Cot ø? Wait ko po sir para macorrect ko po. LET Takers po ako this coming March 2023. Thank you so much Sir :)
Hello, sir. Thank you for this tutorial, btw may Correction lang po, baliktad po ang COSECANT ( 5:50 ). It should be hypotenuse/opposite since reciprocal siya ng SINE.
@@MathTeacherGon Apply trigonometric ratios To solve right triangle given the length of the hypotenuse and the length of only one leg. Meron kapo bang topic neto sir?
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. sinθ = 3/5 cosθ = 4/5 tanθ = 3/4 cscθ = 5/3 secθ = 5/4 cotθ = 4/3
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. sinθ = 6/10 or 3/5 cscθ = 5/3 cosθ = 8/10 or 4/5 secθ = 5/4 tanθ = 6/8 or 3/4 cotθ = 4/3 Thank you po sir! 💕
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. sinθ = 6/10 or 3/5 cosθ = 8/10 or 4/5 tanθ = 6/8 or 3/4 cscθ = 10/6 or 5/3 secθ = 10/8 or 5/4 cotθ = 8/6 or 4/3
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. sine∅ = 6/10 cosine∅ = 8/10 tangent∅ = 6/8 cosecant∅ = 10/6 secant∅ = 10/8 cotangent∅ = 8/6 simplified: sine∅ = 3/5 cosine∅ = 4/5 tangent∅ = 3/4 cosecant∅ = 5/3 secant∅ = 5/4 cotangent∅ = 4/3 thank you po sir.
sir ask q lng po wat if may degrees na nasa loob po ng triangle sa magkabilang dulo po yung sa taas an sa baba ng right pero may no. lang po sa labas like this in ur example...i cocompute pa po ba yun?
hi po sir, paano po kung given yung cos A = 12/13 tas find the six trigonometric functions of B daw po. Yung value po ba ng adjacent is 12 at hypotenuse ay 13? Need pa po ba hanapin yung value ng Opposite side to answer angle B 😄
@@MathTeacherGon if the question states figure x and y on a triangle and support the answer with Pythagoras... Then it also states Hence Sin= Cos= Tan= Cosec= Sec= Cot= Do I still apply the same knowledge I'm getting from this video? 💯Trigonometry is interesting
and how about po sa example yung opp. and hyp. ay may . exm. 1.4 like ganun po same po sa isang triangle may dalawa or isang may . i cocompute po ba yun?
Sir pede nyo po ba gawin yung katulad ng first triangle then yung adjacent po may number and yung sa part po na may symbol na theta may degree tapos hahanapin po yung a.
Given right triangle ABC, C as your right triangle.
Side a = 6, b = 8 and c = 10.
Find the six trigonometric ratios of the given right triangle.
Given right triangle ABC, as you right triangle.
Side a=6, b=8 and c= 10
Find the six trigonometric ratios of the given right triangle
sin∅ = 6/10
cos∅ = 8/10
tan∅ = 6/8
csc∅ = 5/3
sec∅ = 5/4
cot∅ = 4/3
Given right triangle ABC, C as your right triangle.
Side a= 6, b= 8, and c= 10.
Find the six trigonometric ratios of the given right triangle.
sin= 3/5
cos= 4/5
tan= 3/4
csc= 5/3
sec= 5/4
cot= 4/3
Given right triangle ABC, C as your right triangls.
Side A = 6 ; Side B = 8 ; Side C = 10
• A N S W E R S •
sinθ = 3/5
cosθ = 4/5
tanθ = 3/4
cscθ = 5/3
secθ = 5/4
cotθ = 4/3
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10.
Find the six trigonometric ratios of the given right triangle.
Sin= 6/10 or 3/5
Cos=8/10 or 4/5
Tan=6/8 or 3/4
Csc=10/6 or 5/3
Sec=10/8 or 5/4
Cot=8/6 or 4/3
Given right triangle ABC , C as your right triangle.
Side a=6 , b=8 and c=10.
Find the six trigonometric ratios of the given right triangle.
sin = 3/5
cos = 4/5
tan = 3/4
csc = 5/3
sec = 5/4
cot = 4/3
Thanks sir, im getting sick of modules that are giving confusing and unsimplified information.
Oww ..btw welcome .
Right? Me too
Side A= 6, B= 8, and C= 10
sinØ = 6/10
sinØ = 3/5
cosØ = 8/10
cosØ = 4/5
tanØ = 10/8
tanØ = 5/4
cscØ = 10/6
cscØ = 5/3
secØ = 10/8
secØ = 5/4
cotØ = 8/6
cotØ = 4/3
Sin ø =3/5. Csc ø =5/3 = 1 2/3
Cos ø =4/5 Sec ø =5/4 = 1 1/4
Tan ø =3/4. Cot ø =4/3 = 1 1/3
Hello Sir, ngayon ku lang tlga naintindhan po lahat. Pa correct po kung tama po ba sagot ko lalo na Csc ø, Sec ø & Cot ø? Wait ko po sir para macorrect ko po. LET Takers po ako this coming March 2023. Thank you so much Sir :)
Hello, sir. Thank you for this tutorial, btw may Correction lang po, baliktad po ang COSECANT ( 5:50 ). It should be hypotenuse/opposite since reciprocal siya ng SINE.
Finally thank you po sir, hindi na po ako mahirapan sa math
welcome po. keep on learning
Thanks sir. You are good at explaining it and I can understand it so easily keep up the good work Sir 👍👏
wow..thank you
@@MathTeacherGon Apply trigonometric ratios To solve right triangle given the length of the hypotenuse and the length of only one leg. Meron kapo bang topic neto sir?
Given right triangle ABC, C as your right triangle.
Side a = 6, b = 8 and c = 10.
Find the six trigonometric ratios of the given right triangle.
sinθ = 3/5
cosθ = 4/5
tanθ = 3/4
cscθ = 5/3
secθ = 5/4
cotθ = 4/3
Hello po sir. Di po ba dapat baliktad yung ratio ng cosecant? Hyp/opp dapat?
Opo yun po ang correction dyan..
THANK YOU SIR IT REALLY HELPS ME ALOT!!💕💕
Welcome po...😊😊😊
Given right triangle ABC, C as your right triangle.
Side a = 6, b = 8 and c = 10.
Find the six trigonometric ratios of the given right triangle.
sinθ = 6/10 or 3/5 cscθ = 5/3
cosθ = 8/10 or 4/5 secθ = 5/4
tanθ = 6/8 or 3/4 cotθ = 4/3
Thank you po sir! 💕
Given right triangle ABC, C as your right triangle.
Side a = 6, b = 8 and c = 10.
sinθ = 6/10 or 3/5
cosθ = 8/10 or 4/5
tanθ = 6/8 or 3/4
cscθ = 10/6 or 5/3
secθ = 10/8 or 5/4
cotθ = 8/6 or 4/3
Thank you, Teacher Gon! Marami akong natutuhan dahil po sayo.
Welcome.. please share this video to your friends.
Thank you so much po, sir Gonzaga!!
whooa... welcome...😊
U r so a great teacher tnx
Given right triangle ABC, C as your right triangle.
Side a = 6, b = 8 and c = 10.
Find the six trigonometric ratios of the given right triangle.
sine∅ = 6/10
cosine∅ = 8/10
tangent∅ = 6/8
cosecant∅ = 10/6
secant∅ = 10/8
cotangent∅ = 8/6
simplified:
sine∅ = 3/5
cosine∅ = 4/5
tangent∅ = 3/4
cosecant∅ = 5/3
secant∅ = 5/4
cotangent∅ = 4/3
thank you po sir.
can you only use the 6 trigonometric ratios on a right triangle po ba sir? or can we also use these functions sa non-right angled triangles po?
Excellent learning teacher Gon 😊😊
Thank you po sir! ^^
sin θ = 6/10
cos θ = 8/10
tan θ = 6/8
csc θ = 10/6
sec θ = 10/8
cot θ = 8/6
Thank you so much, sir!
welcome po
thank you sir!
Welcome po...
thank you so much sir!!!!
Oww... Welcome...😊😊❤️🇵🇭
thank you...how can I go about solving an equestion where theta greater or equal to360°
As for my understanding there couldn't be a theta or angle that is greater than or equal to 360° because a triangle is only equivalent to 180°
For example meron kang given angle na 390°, same lang sya ng 30°
390°-360°=30°
thank you so much Sir!
Welcome po...❤️
Helpful Sir! As always
thank you so much po magagamit ko to sa exam bukas
how to identify the different sides of the right triangle without reference angle
Thank u po sir!
Welcome 😊😊😊
Thankyou so much sir
Welcome po...
Done watching. Thank you po, Sir! (Galileo)
Thank you po sir❤.
Yeyyy thanks a lot sirrr
Hi guyz, pwede ko bang malaman kung saang school kayo nagaaral.😊
Hello sir!
Visayas State University sir♥️
Apec schools
@@itsjuswahsckrs anong course kinuha mo buddy?
Grade 11 palang po ako ngayon pasukan pero lilipat nako hehe
Thank you Sir!
Thankyou so much sir
Welcome
Thank God, finally i understand something in math 😂
wow..thanks for the appreciation...😊🤗
thank you po sir godbless po💜
Welcome po…
Thanks sir this was interesting session 👍
Thanks po!
Thank you din po..
sir ask q lng po wat if may degrees na nasa loob po ng triangle sa magkabilang dulo po yung sa taas an sa baba ng right pero may no. lang po sa labas like this in ur example...i cocompute pa po ba yun?
Sir thank you po
Answer ko po
Sine=6/10
Cosine=8/10
Tangent=6/8
Cosecant=10/6
Secant=10/8
Contangent=8/6
Thank you Louie
sir gon, baliktad po dapat ung sa cosecant. correct me if im wrong po. god bless!
Thank you po sir❤
Welcome cherry.
hi po sir, paano po kung given yung cos A = 12/13 tas find the six trigonometric functions of B daw po. Yung value po ba ng adjacent is 12 at hypotenuse ay 13? Need pa po ba hanapin yung value ng Opposite side to answer angle B 😄
Yes po.. you need to find the hypotenuse para maging cosB
Pls is opp/hyp the covenant
Thank you a lot
Welcome...😊😊😊❤️
@@MathTeacherGon if the question states figure x and y on a triangle and support the answer with Pythagoras... Then it also states
Hence
Sin=
Cos=
Tan=
Cosec=
Sec=
Cot=
Do I still apply the same knowledge I'm getting from this video? 💯Trigonometry is interesting
Thank you po sir
Wow..welcome po..
and how about po sa example yung opp. and hyp. ay may . exm. 1.4 like ganun po same po sa isang triangle may dalawa or isang may . i cocompute po ba yun?
is the cosecant really still opp./hypo. or is it hypo./opp.?
Sorry thats an error.. hyp/opp..
oh i see, thank you sir :DD
Thank you po
Welcome po...😊
Sin∅=3/5 Csc∅=5/3
Cos∅=4/5 Sec∅=5/4
Tan∅=3/4 Cot∅=4/3
Thank you po sir
sir what if ang given is cot and u have to solve for the other 5?
Sin ø =6/10. Csc ø =5/3
Cos ø =8/10. Sec ø =5/4
Tan ø =6/10. Cot ø =4/3
Thank you po sir 😁
salamat po sir👍
Thank you, Sir! (Galileo) ♡♡♡
wow..nanuod..😊
CHO or COH? Alin po yung tama?
Ayon pinalitan na,okay na po
CHO.typographical error
Sir paano po kapag adjacent ang hinahanap if hypotenuse lang ang meron?
Salamat po
Paano makuha hypotenuse and adjacent my 35 opposite kasi Ako and teta 30°
thank u po sir
Answer kopo
sinθ = 6/10
cosθ = 8/10
tanθ = 6/8
cscθ = 10/6
secθ = 10/8
cotθ = 8/6
Lowest term mo ito nak.
3/5
4/5
3/4
5/3
5/4
4/3
Eto po sir
Mag PowerPoint presentation ka po sana para mas makita po ng maayos :)
I love you sir
thankkkk you for the love ..
paano po kunin ung sin 20°?
Sir, the ratio of cosecant theta is hypotenuse/opposite....... But you wrote riverse 😅
Paano ba kunin ang angle
Sir Sana sa susunod Tagalog nalang hehe
Okie dokie... Halos lahat po ng videos natin ganun..
Pno po ung basic concepts and terms
Sir pede nyo po ba gawin yung katulad ng first triangle then yung adjacent po may number and yung sa part po na may symbol na theta may degree tapos hahanapin po yung
a.
Sige po gagawa po ako bukas tutukan mo po sa channel ko po
Thankyouu sirr aabangan ko po yann✋
Pero try mo n din yung videos sa playlist ko...ng Trigonometry baka nandun din hinahanap mo po
Yes sir pero yan po kase last item nahihirapan po ako,pero thankyou den po dahil nasagutan ko yung mga naunang item dahil din sa mga vids mo po❤️
I'm still waiting sir😭
I don't got it 😶
Done po
Welcome po
exam tom sana maka 40+/50 D:
Keep it up.
@@MathTeacherGon good news sir 48/50
@@pheo1299 WOW CONGRATS
ang cosecant po sir baliktad po
thank you po
sine∅ = 6/10
cosine∅ = 8/10
tangent∅ = 6/8
cosecant∅ = 10/6
secant∅ = 10/8
cotangent∅ = 8/6
simplified:
sine∅ = 3/5
cosine∅ = 4/5
tangent∅ = 3/4
cosecant∅ = 5/3
secant∅ = 5/4
cotangent∅ = 4/3
thank you po sir!
Welcome Yra...
Thank you po sir
Welcome po..
Done po
Welcome po.
Thank you po sir
Welcome po