Thank you so much // you are the best one who simplify frame assignment . I hope to make more tutorials about inverse kinematics, it has a perfect knowledge.
Thank you so much for these videos which helped me too much in my exam. Just watching your videos I could completed my exam and got good grade! I love you so much. Muchas gracias!
there u go mate you have earned a subscriber i just want to dwelve deep intpo this topc so apart from this play list do u have another playlist that deals with advanvced concepts like the next level after this
I assume you mean left or right. Mathematically, even if you make it left it would still be fine because x2 would definitely be facing right (towards the link), i.e. facing the common normal. So the only difference then would be a 180 degrees in the link parameters table for alpha of 2nd link. But a 180 switch on consecutive joints which are intersecting makes no impact to the overall transformation matrix. So same result at the end.
Hi , Thanks for the video but I had one doubt , The transformation matrix you used is different from the transformation matrix used in the book, which is : A = c(theta) -s(theta)c(alpha) c(theta)c(alpha) ac(theta) s(theta) c(theta)c(alpha) -c(theta)s(alpha) as(theta) 0 s(alpha) c(alpha) d 0 0 0 1 Can you please explain
When finding the normal x direction in an interaction of axis, after drawing the plans, what determine the direction exactly? I’m just a bit confused on that part. It is the shading ?
By convention you can take the positive x-axis along the link (if there is a link in that direction) otherwise, you can use the right hand rule for that joint (where the planes intersect) ; and the positive x-axis would point away from the direction of rotation. This is just a convention, but you can define any direction normal to the plane as the positive x-axis, however, if you did that, the values you would calculate later on would be different. I hope this answers your question, if not, do get back to me. Thanks and all the best.
hola profe, queria preguntarle como se acomodaria la tabla DH si hubiera una articulacion rotacional auxiliar, en otras palabras simples uniones donde no va un actuador, estan ahi solo para apoyar en el movimiento, un ejemplo seria el robot que escribe la hora, saludos
BRO, after having seen your past vids as well, PLEASE(!!!), for the love of god, understand that one axis CANNOT define one plane!!! You are randomly drawing planes and are very wrong! Read the comments, some of them actually point to what you are doing wrong!!!! If you only answer to positive comments you won’t improve your tutorials.
Oh, and not only that, but the intersection of 2 planes is a line, NOT a plane! A perpendicular to a line can have an infinite directions, it is not determined, or however it is called when you know exactly how it is defined.
i usually don't comment on videos but the way you have tought the frame assignment is so good!!!!!!!! thank you so much sir
Thank you so much // you are the best one who simplify frame assignment .
I hope to make more tutorials about inverse kinematics, it has a perfect knowledge.
Thank you so much for these videos which helped me too much in my exam. Just watching your videos I could completed my exam and got good grade! I love you so much. Muchas gracias!
Brother, thank you so much. You cleared a lot of my misunderstandings, love from Pakistan ❤
Great video, thank you very much for sharing.
Hi, Great Video. I have a doubt,
I think the x3 shud be along ze as z2 and z3 are parallel and common perp shud be x3, right?
thank you. you helped me for my final exam
Please make videos on inverse kinematics!! this was really helpful
awesome content
I love you man truly
very good explanation
This is great!
there u go mate you have earned a subscriber i just want to dwelve deep intpo this topc so apart from this play list do u have another playlist that deals with advanvced concepts like the next level after this
Great Work Dude
Thanks for the helpful videos! Quick question, does this course cover Reversed Kinematics? I couldn't find anything about it.
x3 is supposed to intersect with Z2 and Z3
so it should have been in the same sirection as Ze according to what i know
well done
What a great job you done. Thankfull to you bro For all your efforts to make it easy pissy.
6:12 how did we decide on the direction of the x1 axis. The normal could point inwards to the plane too.
I assume you mean left or right. Mathematically, even if you make it left it would still be fine because x2 would definitely be facing right (towards the link), i.e. facing the common normal.
So the only difference then would be a 180 degrees in the link parameters table for alpha of 2nd link.
But a 180 switch on consecutive joints which are intersecting makes no impact to the overall transformation matrix. So same result at the end.
We need more video about roboticssss!!!
thank you so much chams, but you should have chosen a simpler example in this video
Hi , Thanks for the video but I had one doubt ,
The transformation matrix you used is different from the transformation matrix used in the book, which is :
A = c(theta) -s(theta)c(alpha) c(theta)c(alpha) ac(theta)
s(theta) c(theta)c(alpha) -c(theta)s(alpha) as(theta)
0 s(alpha) c(alpha) d
0 0 0 1
Can you please explain
Could you multiply and get the Jacobian please.
on axis 2-3 ai-1 value is zero because we measure along xi not xi-1 that means zero ...along x2 = l3 but along x3 =0
Thank you
I can't thank you enough for teaching me this while my professor refuses to make lecture recordings 🥲
If the robot is not placed in the centre of the world plane (position of base robot is not at 0,0,0); do we start frame 0 at the centre world frame?
When finding the normal x direction in an interaction of axis, after drawing the plans, what determine the direction exactly? I’m just a bit confused on that part. It is the shading ?
By convention you can take the positive x-axis along the link (if there is a link in that direction) otherwise, you can use the right hand rule for that joint (where the planes intersect) ; and the positive x-axis would point away from the direction of rotation. This is just a convention, but you can define any direction normal to the plane as the positive x-axis, however, if you did that, the values you would calculate later on would be different. I hope this answers your question, if not, do get back to me. Thanks and all the best.
I have the same doubt and alpha rotation values confused me man.
In your robotics playlists.. what is tiktok video doing?
hola profe, queria preguntarle como se acomodaria la tabla DH si hubiera una articulacion rotacional auxiliar, en otras palabras simples uniones donde no va un actuador, estan ahi solo para apoyar en el movimiento, un ejemplo seria el robot que escribe la hora, saludos
buenos dias
@@baradenreddi3508 saludos
Could u do more example mate
how a distance be (-), you wrote -L2
Is it possible.
How do we assign the end effector (tool) frame?
I love you
Hi how can I contact with you
sorry but the last makes the whole problem confusing of DH Table 16:33
BRO, after having seen your past vids as well, PLEASE(!!!), for the love of god, understand that one axis CANNOT define one plane!!! You are randomly drawing planes and are very wrong! Read the comments, some of them actually point to what you are doing wrong!!!! If you only answer to positive comments you won’t improve your tutorials.
Oh, and not only that, but the intersection of 2 planes is a line, NOT a plane! A perpendicular to a line can have an infinite directions, it is not determined, or however it is called when you know exactly how it is defined.
A normal vector defines a plane because all vectors on the plane are perpendicular to this vector.