3 HARD SAT Math Questions & How to Solve Them
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- Опубліковано 20 лип 2024
- Struggling with hard SAT math problems? In this video, I'll break down the three hardest SAT math questions and show you step-by-step solutions to solve them with confidence.
Solve these challenging problems with us and boost your test prep! Whether you're prepping for your June SAT, or just need some extra help with SAT math, this video is perfect for you. Improve your studying techniques and ace your test with our easy-to-follow explanations and tips.
If you're taking the Digital SAT this year, let's help you get ready and score a 1400, 1500, or even a perfect 1600 on the SAT!
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T I M E S T A M P S
00:00 3 HARD MATH QUESTIONS ON THE DIGITAL SAT
02:32 HARDEST PROBLEM 1
04:48 HARDEST PROBLEM 2
06:43 HARDEST PROBLEM 3
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✨ 3 Hard Math Questions on the DSAT
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Name: Laura
Where did you study - University of Notre Dame
What did you major in - Psychology & Mathematics
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![[August SAT Math] These 3 Questions were JUST added](http://i.ytimg.com/vi/37YoPXLGAk4/mqdefault.jpg)
for the second question, i used c/a as the formula for the product of the solutions of a quadratic equation, ab/57 = kab, everything cancels and simplifies real nicely and you end up with k = 1/57
Love this!! ❤️
This was really helpful. Good job.
👍helpful
Wonderful scholar!
I tought scalar learning this.
Thanks for the video. In the third question, the underlying concept is that Sin(180 - theta) = sin(theta). That is why, the Sine of the reference angle that you mentioned in your solution is equal to sq.root 3 divided by two --> the given value of Sine for the given angle (theta) in the question.
Btw for the first one you can just use a table on Desmos and do exponential regression 👍
Thanks for posting the "unit circle" question. My students have been saying that's been appearing, but I wasn't sure exactly how.
For the third question, your diagraming is technically wrong because the radius of the circle is 1 and your diagonal was 2. A better way to teach it is using the unit circle.
Hard is a relative term. 1) b < 5, so only the negative possibility makes sense. Note: had the difference in y-values been the product of consecutive integers, the quadratic would factor ; 2) trivial by Vieta's formulas; 3) trivial from unit circle trig values.
Hey ,
Can you make a video on June Expected questions and Predictions ?
i also want that
2nd question you can do it by using product of solution=c/a (constant/coefficent of x^2).
consequently,you'll get kab=ab/57 ... cancel out ab from both side you'll get k=1/57
this is a much easier appproach
For the 1st question: What if we follow this approach: we substitute the given points and add the two equations while multiplying the first equation by -1. We'll have something like this: (a^{2n} - a^n - 125 = 0), and then we assume that (a^n = x). Solving for (x), we get (x^2 - x - 125 = 0). Then (a^n = x) will be one of these two values: 11.692 or -10.692. If we take the first value and substitute it into the equation:(5 = a^n + b), we find that (b = -6.692).
there's 2 ways of using simultaneous equations, either elimination OR substitution, she used subtitution but you use elimination, its best practice to use substitution esp considering theres a quadratic involved, I see what you did and that's what I initially did, but I felt as thought it would look messy so I did subtitution, however your method should work tho
For question 1: Why can't I divide the second equation 130=a^2n + b by the first equation 5=a^n + b? Wouldn't this give me 26 = a^n + 1 and 25 = a^n which allows me to plug back in and solve for b?
i did that and apparently and I got different values of B for each equation
Why was question 3 in quadrant 2? how we know which quadrant to work in?
How does rounding works?, for example, for the first example that you showed, can I just write 6.69? Or how many 'significant figures' must the answer have? (if it's not detailed by the question)
Sorry, it should be -6.69
Are these seriously considered hard problems?? The solutions are pretty straightforward and I can recall that we were solving problems like that as common homework, when I was in high school!
sat can for university it tenology
Why is preptly not free....
In the third question, wasn’t the angle given in the first quarter?
No,the angle is greater than 90 therefore the theta lies in 2nd quadrant
@@user-nu1mc7hu1r CAST diagram, cosine is negative in the 2nd quadrant, so if cos(60) = 1/2, cos(120) = -1/2 as 120 is in the 2nd quadrant where only sine is positive
Is there any chance to get derivatives on Math?
Absolutely not
When will your june course drop
Predictions coming Wednesday!
how are these hard??
search up "A level further maths past papers" and do those questions if you want "hard", alternatively search up "MAT past papers" which are similar in style to the SAT