^=read as to the power *=read as square root As per question (1/x)+*{(1+x)/x}=5 *{(1+x)/x}={5-(1/x)} *{(1+x)/x}={(5x-1)/x} Take the square (1+x)/x ={25x^2+1-10x}/x^2 So, (1+x)={25x^2-10x+1}/x X(1+x)=25x^2-10x+1 X+x^2=25x^2-10x+1 (25x^2-x^2)-10x-x+1=0 24x^2-11x+1=0 24x^2-8x-3x+1=0 8x(3x-1)-1(3x-1)=0 (3x-1)(8x-1)=0 3x-1=0, or 8x-1 =0 3x=1, 8x=1 X=(1/3), or x=(1/8)
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@@gilvanyguedes5658
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The square root of 9 is either +3 or =3. Therefore 1/8 could also be the value of X
@@arioncr7228
Kindly check with the given equation to be sure okay. Thank you
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@@MrMackxl65
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Please make a video of this question 16×10^4÷{3×10^-2) thanks
@@bobmanueltonye4462
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FRUMOASA EXPLICATIE!
Vezi min. 3:20
x----- = ------
@@dumitrudraghia5289
Oh! Thank a lot Sir 🙏
^=read as to the power
*=read as square root
As per question
(1/x)+*{(1+x)/x}=5
*{(1+x)/x}={5-(1/x)}
*{(1+x)/x}={(5x-1)/x}
Take the square
(1+x)/x ={25x^2+1-10x}/x^2
So,
(1+x)={25x^2-10x+1}/x
X(1+x)=25x^2-10x+1
X+x^2=25x^2-10x+1
(25x^2-x^2)-10x-x+1=0
24x^2-11x+1=0
24x^2-8x-3x+1=0
8x(3x-1)-1(3x-1)=0
(3x-1)(8x-1)=0
3x-1=0, or 8x-1 =0
3x=1, 8x=1
X=(1/3), or x=(1/8)
@@ManojkantSamal
Great work. Just do a check to know the actual value of x okay. Thanks