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so sir, if you say when an object is displaced upwards in respect of the gravitational force acting downwards on the object, then how is it possible to have work done by the object is positive as we know that value of g is negative in upward direction so explain why work is done on a certain height is positive?
because if we take this two-component on vertical as displacement and another as the gravitational force as on the horizontal axis then angle made by the body is 180 degree so according to the formula of work done is Fs.cos (theta) 180 degree is -1 so value of g will also be negative and if multiply whole formula then it will be positive work done as both the negative signs will be multiplied and become positive hence the statement for why work is done on a certain height will also be positive.
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sir it have been taught to me that this term work is path dependent and one will have look at forces at different points as material object passes through them...So my thought is that your explanation at (video time)8:00 is not complete unless u specify that force field in which object is moving is conservative field and work is independent of path b/w any two points.
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sir it have been taught to me that this term work is path dependent and one will have look at forces at different points as material object passes through them...So my thought is that your explanation at (video time)8:00 is not complete unless u specify that force field in which object is moving is conservative field and work is independent of path b/w any two points.
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have got my concepts cleared after seeing most of his videos
Harkrit S. Nagpal dai
My concepts are being cleared by your explanation .thank you☺️☺️☺️☺️☺️☺️
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Thank u so much sir ..
ur videos help me a lot
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please higher your volume a little , otherwise it was good , keep it up!!!!!!!!!!
Really
Hm
this guy is very good
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so sir, if you say when an object is displaced upwards in respect of the gravitational force acting downwards on the object, then how is it possible to have work done by the object is positive as we know that value of g is negative in upward direction so explain why work is done on a certain height is positive?
because if we take this two-component on vertical as displacement and another as the gravitational force as on the horizontal axis then angle made by the body is 180 degree so according to the formula of work done is Fs.cos (theta) 180 degree is -1 so value of g will also be negative and if multiply whole formula then it will be positive work done as both the negative signs will be multiplied and become positive hence the statement for why work is done on a certain height will also be positive.
Sir please upload physics and chemistry of class 11 and 12 . Your classes are excellent .
makhaan maar ke pada ta hai ye banda love it :)
Thanks for the vedios👍👍👍👍👍👍👍👍👍👍🌝🌝🌝🌝😊😊😊☺☺☺☺☺☺☺😊😊😊🌝🌝🌝🌝☺☺☺👍👍👍☺
Thank u sir
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Very nice explanation…I understood everything you said.Thank you so much 👌👍🏻
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very helpful tysm!!!!☺☺
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Can I dubbed all physics videos in good Hindi and bangla, many peoples they don't understand English so I want to help them
Is it use ful for mains and advance jee
👍👍👍👍👍👍
sir i need conceptual verification, if u could help me..
Your explanation is very clear and nice.
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1 meter...👌
Better explanation than school teachers
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please make a video on surface tension, capillarity, viscosity and bernoulli's theorem.
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sir it have been taught to me that this term work is path dependent and one will have look at forces at different points as material object passes through them...So my thought is that your explanation at (video time)8:00 is not complete unless u specify that force field in which object is moving is conservative field and work is independent of path b/w any two points.
Thanks you so much sir
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Hey u teach good
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you must have done M.A in english
Very good 👍
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Why isn't this vedio popular
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Hii sir
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What is force
Sir give me answer please
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@@DeltaStep can you understand Hindi language??
Noon
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Test
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Please higher up volume
Super explanation but your hand writing is too worst
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sir it have been taught to me that this term work is path dependent and one will have look at forces at different points as material object passes through them...So my thought is that your explanation at (video time)8:00 is not complete unless u specify that force field in which object is moving is conservative field and work is independent of path b/w any two points.
Sir please upload physics and chemistry of class 11 and 12 . Your classes are excellent .
Tq very much sir
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Thanks sir
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