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Hello, may I know why the calculation of vertical component of 35 kN is 5/29？
hello, let me help you answer your question, 5/√29 is from the trigonometric funtion which is sin (θ). in trigonometric function, sin (θ) = opposite (y)/Hypotenuse(r). in this case the y = 5 and the r =√29. hope it helps.
Hello, may I know why the calculation of vertical component of 35 kN is 5/29？
hello, let me help you answer your question, 5/√29 is from the trigonometric funtion which is sin (θ). in trigonometric function, sin (θ) = opposite (y)/Hypotenuse(r). in this case the y = 5 and the r =√29. hope it helps.