Hello Sir. Thank you for the video. However i think your solution is WRONG based on what I have learnt in the classroom and also verifying here from wiki (en.wikipedia.org/wiki/Modified_AMI_code). From what I have learnt, the rule is thus. You replace the 4 consecutive 0's with a sequence of the form A00V. "A" is called the DC equalization symbol. It is either +1,0 or -1. You choose the one which would render the sum of the pulses preceding (positive and negative pulses) inclusive of the A to be zero. So if the sum of pulses up till before A is +1 then A is -1. Similarly sum = -1 then A = 1 and sum = 0 then A = 0. So of course for the next substitution of the HDB bits you don't need to try to find the sum again from the start because your previous DC equalization bit(A) already rendered the sum to zero so you start summing the pulses from the first pulse after the previous DC bit(A).
Please site a reference. The wikipedia article has apparently changed, and even in the said article there are contributors who indicated that there may be an error in the examples (see talk section of the article). Also, the wikipedia article doesn't talk about the term "DC equalization bit".
@@abdallahbukhari4382 yeah I see the wiki article apparently is not there any longer. I wrote my response based on what I was taught in the classroom and the article was an additional reference but Unfortunately I can't go back to that right now. Good luck searching and learning.!
Nice explanation. But I saw it in 2x speed still the video seemed to be slow paced.... It would be good if u explain with good speed too.... Otherwise, it was great!
Hello Sir. Thank you for the video. However i think your solution is WRONG based on what I have learnt in the classroom and also verifying here from wiki (en.wikipedia.org/wiki/Modified_AMI_code).
From what I have learnt, the rule is thus. You replace the 4 consecutive 0's with a sequence of the form A00V. "A" is called the DC equalization symbol. It is either +1,0 or -1. You choose the one which would render the sum of the pulses preceding (positive and negative pulses) inclusive of the A to be zero. So if the sum of pulses up till before A is +1 then A is -1. Similarly sum = -1 then A = 1 and sum = 0 then A = 0. So of course for the next substitution of the HDB bits you don't need to try to find the sum again from the start because your previous DC equalization bit(A) already rendered the sum to zero so you start summing the pulses from the first pulse after the previous DC bit(A).
Thanks a ton for pointing this out and verifying. I'll pin this post and sure it will help the community. Cheers!!
It's correct since the rule of scrambling is always the same; the only difference is in the initial condition for the parity.
That means the explanation in the video is wrong?
Please site a reference. The wikipedia article has apparently changed, and even in the said article there are contributors who indicated that there may be an error in the examples (see talk section of the article). Also, the wikipedia article doesn't talk about the term "DC equalization bit".
@@abdallahbukhari4382 yeah I see the wiki article apparently is not there any longer. I wrote my response based on what I was taught in the classroom and the article was an additional reference but Unfortunately I can't go back to that right now. Good luck searching and learning.!
the best explanation i've ever watched
Appreciate that :)
Nice detailed explanation. Love this. Thank you :)
Perfect example, Thank you so much
Explained well ... Thank you ...
good explanation,sir.Thanks for the tutorial.
Super
the best explanation Thanks
Explained really well
nice explanation . Thankyou
THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
thanks for the video!
thanks
Nice explanation. But I saw it in 2x speed still the video seemed to be slow paced.... It would be good if u explain with good speed too.... Otherwise, it was great!
speed is not important. understanding the concept is important. rushing things will lead you nowhere.
bitte nich bisschen langsamer zeichenn, sonst kann mannicht nachvollziehen was du gemacht hast. kuss
🤔🤔🤔 That's wrong...
This is wrong sir.
Thanks for the feedback.Please make required alteration in a comment for the community. I'll pin that comment.
Sir i have a question if 1 polarity depends upon previous one's then after violation y it goes downward
Its wrong solution