Calculus I - Limits - Finding Limits Algebraically - Piecewise Functions 1

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  • Опубліковано 20 січ 2025

КОМЕНТАРІ • 91

  • @ritzbitz8249
    @ritzbitz8249 11 років тому +3

    Thank you so much. Words cannot explain how relieved I am that I got this concept (finally!) my teacher took 50 minute and couldn't do it, and you did in less then 10 minutes from. You're great! I am definitely subscribing & learning calc from you!

  • @stefan--
    @stefan-- 8 років тому +1

    Thanks so much, idk who the hell would dislike this, it was clear and concise

  • @taejiminie5248
    @taejiminie5248 7 років тому +1

    i was stuck on my calc hw because my teacher didn't go over this, but you made it clear now. thanks!

  • @GFX_by_Gurpreet
    @GFX_by_Gurpreet 3 роки тому

    you teach better than my maths teacher , thanks a lot !!!!!!!!!!!

  • @MillerHighLifez420
    @MillerHighLifez420 5 років тому +2

    you saved me as well . Huge thanks for putting it in Layman's terms

  • @tanveerahmad8455
    @tanveerahmad8455 3 роки тому

    when i watched this video .I easily solves question ..
    i am very very Thank full of You

  • @guitarheo3
    @guitarheo3 11 років тому

    This video helped me get through my homework. Thanks!

  • @TheInfiniteLooper
    @TheInfiniteLooper  11 років тому

    Depends on what x approaches. If x approaches a value where the function splits apart, then you have to use one-sided limits. Two-sided limits won't work directly because the left side and right side will be different functions. (If you know that the two-sided limit exists and you're allowed to use that fact, then yes, that would be the answer.)
    But if you have something like in part d, with x approaching a value where the function doesn't split, then you can treat it like a two-sided limit.

  • @joiseau
    @joiseau 11 років тому

    High quality video.
    Thank you for your time and effort.

  • @4dv4rch3r
    @4dv4rch3r 11 років тому

    Thanks! this is a lot faster than finding the limit from the graph

  • @ziadkhan9555
    @ziadkhan9555 5 років тому +1

    dude thank you so much man. PreCalc final in two days

  • @TheInfiniteLooper
    @TheInfiniteLooper  11 років тому +2

    The -9 in part d? Nowhere. It's just the number I randomly chose to use in that example.

  • @gabbyphan2971
    @gabbyphan2971 4 роки тому

    How do i solve if the two-sided limit exists?

  • @kylefelecio4197
    @kylefelecio4197 8 років тому +1

    thank you lord math tutorials are born!

  • @TheInfiniteLooper
    @TheInfiniteLooper  11 років тому

    I know. Looks like those should be "less than or equal to" in your F(x).
    Always look for the piece that's "just next to" the value x approaches. So if you want, e.g., the limit of F(x) as x approaches 2 from the right, just look at is the piece where F(x) = x+4, because this is the piece that is immediately to the right of x=2. There are other pieces, but since x goes to 2 from the right, then the piece where F(x) = x+4 is the last piece x is on before it would actually reach the value x=2.

  • @micadecaprio442
    @micadecaprio442 10 років тому +2

    This was extremely helpful!! thanks so much!

  • @hadeerrashad5486
    @hadeerrashad5486 7 років тому

    God bless u for making this excellent video!

  • @hotlikethis1333
    @hotlikethis1333 11 років тому

    What if the two sided limit does exist? Is it just that answer or is there more work needed to be done?

  • @lanfred619
    @lanfred619 9 років тому

    mid terms tmrow and u saved my life
    ty :)

  • @math1932
    @math1932 10 років тому +10

    nice and clear

  • @Moxormog
    @Moxormog 11 років тому

    Dont stop making videos please!

  • @targettoad691
    @targettoad691 8 років тому

    what do you do if your given a piecewise function, but your limit is infinity?

  • @vfgrfbgrb
    @vfgrfbgrb 8 років тому

    Can you see it as if negative side smaller that positive it makes less than

  • @sarahwilbur3814
    @sarahwilbur3814 6 років тому

    I know this is old but...THANK YOU!!! I finally understand!!!!!

  • @zenithjoyamadeo6870
    @zenithjoyamadeo6870 3 роки тому

    Sir can I message you I really need help. For my test

  • @Dpfpv1
    @Dpfpv1 11 років тому

    'so the function is discontinues at x=6 right?

  • @breezytravelss
    @breezytravelss 5 років тому

    Thanks man!!! It was really helpful.

  • @TheInfiniteLooper
    @TheInfiniteLooper  11 років тому

    The function is discontinuous at x=6 but I didn't mention it in the video since I didn't start talking about continuity until a later video.

  • @bigman99991000
    @bigman99991000 9 років тому +9

    never had any pre calculus dayz Just calculus.

  • @iliketunarolls
    @iliketunarolls 5 років тому

    I have a question, if anyone could pls answer huhu if the -9 from letter d was coming from the right instead of left, would u still use the same equation?? Coz if it's coming from the right of - 9, wont there be numbers >6?? Thank u in advance:)

    • @TheInfiniteLooper
      @TheInfiniteLooper  5 років тому

      There are numbers > 6, but with limits we only care about what is happening "really really close" to the limit point. As x gets closer and closer to -9, x will eventually become less than 6, so we don't care what happens when x > 6. When x is "really really close" to -9 we will be on the piece where f(x) is x+2.

  • @hollychristine2623
    @hollychristine2623 10 років тому +2

    You, are awesome. Thank you!!!

  • @shat104
    @shat104 12 років тому

    omg thank you sooo much. you are a God send

  • @ngoctham8676
    @ngoctham8676 3 роки тому

    The video sound is pretty good, beyond my imagination

  • @L490sr
    @L490sr 6 років тому

    i dont get it, in the limits we dont use equality because the x approaches not exactly equal, so how come we used the "less or equal to six"

    • @TheInfiniteLooper
      @TheInfiniteLooper  6 років тому

      I just used "less than or equal" since that's the type of inequality used in the piecewise function definition. It's true that x is never actually equal to 6. If you want, you can replace the logic in the explanation with just plain "less than" and it'll still work. More generally though, if x is always less than 6 and is never equal to 6, it's still correct to say "x is less than or equal to 6."

    • @L490sr
      @L490sr 6 років тому

      ooh alright,, thank you for the explanation 👍🏽

  • @amri6873
    @amri6873 4 роки тому

    thank you so muchhhh!!! saved me 😭😆

  • @kevinmccann3376
    @kevinmccann3376 10 років тому

    very helpful...you're the man

  • @vai570
    @vai570 8 років тому

    Thanks! Helped me a lot.

  • @TheInfiniteLooper
    @TheInfiniteLooper  12 років тому +1

    Thanks, glad to help.

  • @ashurfim
    @ashurfim 8 років тому

    short and simple. thanks a lot.

  • @AmaanKhan-xw8hw
    @AmaanKhan-xw8hw 3 роки тому

    What if x tends 0

  • @kyliet22
    @kyliet22 8 років тому +2

    great video...just confused where you got the -9 from

    • @TheCtenoMan007
      @TheCtenoMan007 8 років тому +3

      It's just an additional example.

    • @TheInfiniteLooper
      @TheInfiniteLooper  7 років тому

      Thanks. Yes, it doesn't come from anywhere, it's just the number I chose to use for that example. It's like asking where f came from - it's just what I chose to use.

  • @TheInfiniteLooper
    @TheInfiniteLooper  12 років тому

    And you. Glad to help.

  • @Viietsu
    @Viietsu 2 роки тому

    This was so helpful

  • @chatoalan24
    @chatoalan24 11 років тому +1

    Wait...where'd you pull -9 from?

  • @TheInfiniteLooper
    @TheInfiniteLooper  11 років тому

    Also want to mention again (it's covered in an earlier video) that when x approaches a value in a limit, x never actually equals that value. It just keeps getting closer and closer, but never actually hits the value. That's why I said "would actually reach the value" and not "reaches the value" in the comment above. Just a small detail worth pointing out again
    Anyway, can do some examples like that in a separate video.

  • @nicklousgrant4623
    @nicklousgrant4623 10 років тому

    Awesome video helped alot!!!!1

  • @СашаУмаров-щ4п
    @СашаУмаров-щ4п 2 роки тому

    Character In the video It's great, I like it a lot $$

  • @faithisabel25
    @faithisabel25 8 років тому

    Thank you for posting this video :-)

  • @binx21m
    @binx21m 12 років тому

    .You're a god!

  • @wayoramos7
    @wayoramos7 11 років тому

    This video doesn't take into account that there might be more than two functions that you might be able to plug in.
    For example
    F(x)=
    {-x-2, -infinity < x

  • @TheInfiniteLooper
    @TheInfiniteLooper  12 років тому +2

    Haha, thanks, glad to help.

  • @Islamictalks.123
    @Islamictalks.123 7 років тому

    excellent 😍

  • @abdelrahmankhater9564
    @abdelrahmankhater9564 Рік тому

    Thank you so much

  • @pancake4691
    @pancake4691 3 роки тому

    thank you so much!!

  • @halaahmed4354
    @halaahmed4354 5 років тому

    Wonderful

  • @atadbitnefarious1387
    @atadbitnefarious1387 8 років тому +1

    looks like im passing my first test of the semester tomorow... hopefully lol

  • @ZeroKnigh00
    @ZeroKnigh00 8 років тому

    Thank you.

  • @reubenwilliammpembe667
    @reubenwilliammpembe667 7 років тому

    thank you Sir

  • @hansouled4466
    @hansouled4466 6 років тому

    Ty

  • @gilliandavidson7022
    @gilliandavidson7022 7 років тому

    Bless up.

  • @youssefabdelhady4624
    @youssefabdelhady4624 10 років тому

    that was amazing thanks! saved my ass for my midterm!

  • @johnp4871
    @johnp4871 8 років тому

    thank you!

  • @DRanchers
    @DRanchers 8 років тому

    Wow thank you!!!!

  • @Isteshhad
    @Isteshhad 12 років тому

    God bless you -333

  • @TheGaBoDrUm
    @TheGaBoDrUm 6 років тому

    thanks a lot

  • @conniequintana3955
    @conniequintana3955 7 років тому

    If only my math teacher could explain things like this... or even explain things at all 🙄🙄

  • @VeronicaKoroma
    @VeronicaKoroma 11 років тому

    this video is sooooooooooo....................... helpful. tank U4 posting it.

  • @ericasquicciarini5093
    @ericasquicciarini5093 10 років тому

    Thanks!!!!

  • @ranarashid7483
    @ranarashid7483 5 років тому

    Nice

  • @barronbarron1410
    @barronbarron1410 8 років тому

    nice!

  • @Rav123123
    @Rav123123 10 років тому

    Thanks

  • @Hanz2989
    @Hanz2989 8 років тому

    awesome

  • @ibrahimalslmany
    @ibrahimalslmany 8 років тому

    a lot of thanks :

  • @SuperGonzales94
    @SuperGonzales94 9 років тому

    Thanks bruh

  • @immaweirdone13
    @immaweirdone13 8 років тому

    thank

  • @yonasamente3386
    @yonasamente3386 2 роки тому

    I think you have made a mistake whan you do B.
    Because x is greater than 6 that means not equal to 6

    • @TheInfiniteLooper
      @TheInfiniteLooper  2 роки тому

      It's true that x is not equal to 6 but that doesn't matter. Part b is the limit from the right-hand side only. Therefore we evaluate the limit using the branch where x is greater than 6. It is actually incorrect to use the other branch precisely because x is greater than 6.

  • @khadziandimathivha7950
    @khadziandimathivha7950 3 роки тому

    salute

  • @mustafabayar8521
    @mustafabayar8521 11 років тому

    ثانكسسسسسس

  • @dylanquinones-mattei2157
    @dylanquinones-mattei2157 8 років тому

    RIP Headphone users holy crap

    • @gartyqam
      @gartyqam 6 років тому

      Dylan Quinones-Mattei
      shutcho dylan matty headass up

  • @markb3205
    @markb3205 3 роки тому

    He filming with his microwave

  • @Halfdrunkhero
    @Halfdrunkhero 8 років тому

    Wow this helped a lot. Thank you.

  • @GiangTran-kc1vt
    @GiangTran-kc1vt 3 роки тому

    The video sound is pretty good, beyond my imagination

  • @is5941
    @is5941 3 роки тому

    thank you!