Finding the Limiting Reactant, Part 1

[@mdusmanbro]

I thank God for introducing this worthy channel in my life...

[@BensChemVideos]

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[@nitishupadhyay3972]

Great content

[@sara2t]

shouldnt the answer be 0.17 mols of Chlorine? Since 0.11 * 3 and divided by 2 = 0.165 mols, THEN round to the amount of sig figs which is 2 so the answer should be 0.17 mols