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Hi liew, this is for the single line to ground faults correct? It goes back and relates to the equations themselves. The three branches needs to be summed together and that's why it's in series for 1 LG faults.
How does the solution know that it's only the phase A that is faulted (phase A current = nonzero). How does the math change if say, it was a line-to-ground fault on phase B or C instead?
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Can you please elaborate how the fault current on the HV Side is reflected only on the A and C lines? Thank you
you have literally saved me from failing a course called Electrical Power Systems by Sisir Kumar Nayak
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Your videos are amazing. Question, how would one draw the positive sequence network if there are two voltage sources? Do we represent both sources?
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An incredible amount of time and effort is needed to develop high-quality video tutorials. Each video takes approximately 10 hours to complete which includes learning the concept ourselves, brainstorming creative ways to teach and explain the concepts, writing the script, audio recording, video recording, and editing. This is why Hundreds-of-Thousands of people have watched, liked, subscribed, and left positive comments.
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Dear GenPAC, thank you for the great video. Could you please further elaborate why the 3 component networks should be in series and not parallel?
Hi liew, this is for the single line to ground faults correct? It goes back and relates to the equations themselves. The three branches needs to be summed together and that's why it's in series for 1 LG faults.
Can you also explain why L-L-G fault are branches are paralleled with 3xZf?
To find the base current, Why do we use 13.8kV ? Isn't it 115KV
Can you please elaborate how the fault current on the HV Side is reflected only on the A and C lines? Thank you
How does the solution know that it's only the phase A that is faulted (phase A current = nonzero). How does the math change if say, it was a line-to-ground fault on phase B or C instead?
Great
THANK
Can I contact you sir
Your 2nd term in the I B phase formula is wrong. It should be a x Ia2
Hey Brandon, You are right. The formula will be I(b) = Ia(0) + a^2 * Ia(1) + a*Ia(2).
Can you please elaborate how the fault current on the HV Side is reflected only on the A and C lines? Thank you
Can you please elaborate how the fault current on the HV Side is reflected only on the A and C lines? Thank you
Can you please elaborate how the fault current on the HV Side is reflected only on the A and C lines? Thank you