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Brilliant video. But, Shouldn't the -ve and zero sequence currents be at a phase of +90 degrees if they are j currents? That way the A phase current will equal zero.
Very helpful videos, thank you so much. Would you please post a video on why the symmetrical components circuits are connected in such a way for asymmetrical faults. Best regards.
Thanks for the videos. I'm still confused how the math ends up working such that the solution knows the un-faulted phase is A (phase current = 0). If the un-faulted phase is B instead (A + C line to ground fault), how would the math change?
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Good day sir. In your step 6 for computing phase currents, why is that when i computed the phase current written in to your video, the Ia(phase) is not zero, and the Ib(phase) and the Ic(phase) are equal in magnitude but differ in direction. PS i really love your video here in fault analysis. Thank you
This a great video, very clear and concise. In this example, if we change the LL fault to A-B not B-C, how would you calculate the Ia(+)? Seeking your valuable advice. Thank you.
Also it would be nice to calculate the neutral current as well since the LLG fault is solidly grounded, the earth current would be large. Eagerly await for your reply. Thanks.
Hi, In double line to ground fault, the direction of the current of negative and zero sequence current is opposite of positive sequence current. That's why while solving negative and zero sequence current using current divider rule with reference to positive sequence current we used a negative sign. Hope you find it useful. Regards, GeneralPAC by AllumiaX
Small mistakes calculating negative and zero sequence currents. Using these you will get the same final answer as in the video. Negative sequence, Iaf2 = 2391 < 90 Zero sequence, Iaf0 = 3586< 90
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YEAR-END SALE: Up to 95% OFF: bit.ly/power-systems-courses
As 2023 comes to an end, it's time to take a breather and reflect on your journey this year. This isn't just about recognizing your wins and bumps in the road-it's also an opportunity to identify areas for growth, particularly in your learning goals. Lucky for you, our BIG END-OF-YEAR SALE is here to support you in achieving Your goals!
Brilliant video. But, Shouldn't the -ve and zero sequence currents be at a phase of +90 degrees if they are j currents? That way the A phase current will equal zero.
Very helpful videos, thank you so much.
Would you please post a video on why the symmetrical components circuits are connected in such a way for asymmetrical faults.
Best regards.
Thanks for the videos. I'm still confused how the math ends up working such that the solution knows the un-faulted phase is A (phase current = 0). If the un-faulted phase is B instead (A + C line to ground fault), how would the math change?
Signup to our 𝗣𝗼𝘄𝗲𝗿 𝗦𝘆𝘀𝘁𝗲𝗺 𝗙𝘂𝗻𝗱𝗮𝗺𝗲𝗻𝘁𝗮𝗹𝘀 𝗣𝗮𝗰𝗸 and 𝗦𝗔𝗩𝗘 $𝟭𝟭𝟬𝟬 𝗨𝗦𝗗. This pack includes our four top selling Fundamental Courses. This offer is valid till July 4th, 2022. Only first 50 members will be able to avail it. Hurry up before it's too late: bit.ly/Fundamentals-Pack
Support us by becoming our patron at patreon.com/generalpac ....Why?
An incredible amount of time and effort is needed to develop high-quality video tutorials. Each video takes approximately 10 hours to complete which includes learning the concept ourselves, brainstorming creative ways to teach and explain the concepts, writing the script, audio recording, video recording, and editing. This is why Hundreds-of-Thousands of people have watched, liked, subscribed, and left positive comments.
🎁 Enter the Thanksgiving Power System Pack Giveaway with your email! 🍀 One lucky winner will receive the Power System Fundamental Pack on November 23rd, and ALL participants get a FREE top-selling course. 📚
Sign in: bit.ly/thanksgiving-day-2023
98% OFF | EARLYBIRDS DISCOUNT
Sign up for our newly launched courses at 98% OFF. New video releases will be scheduled on a monthly basis. Grab this opportunity before it ends. bit.ly/earlybirds-discount
Good day sir. In your step 6 for computing phase currents, why is that when i computed the phase current written in to your video, the Ia(phase) is not zero, and the Ib(phase) and the Ic(phase) are equal in magnitude but differ in direction.
PS i really love your video here in fault analysis. Thank you
Hahaha okay i see sir. I forgot to include the negative sign in solving current divisions of negative and zero sequence hahahaa thanks again
This a great video, very clear and concise. In this example, if we change the LL fault to A-B not B-C, how would you calculate the Ia(+)? Seeking your valuable advice. Thank you.
Also it would be nice to calculate the neutral current as well since the LLG fault is solidly grounded, the earth current would be large. Eagerly await for your reply. Thanks.
If I(n) = Ib+Ic, In=10759.33∠90° is this right?
Why do we add a negative sign to calculate the negative sequence?
Hi, In double line to ground fault, the direction of the current of negative and zero sequence current is opposite of positive sequence current. That's why while solving negative and zero sequence current using current divider rule with reference to positive sequence current we used a negative sign.
Hope you find it useful.
Regards,
GeneralPAC by AllumiaX
Small mistakes calculating negative and zero sequence currents. Using these you will get the same final answer as in the video.
Negative sequence, Iaf2 = 2391 < 90
Zero sequence, Iaf0 = 3586< 90
please fix your 1 and 2.They are so look alike each other.
Hey Semih, your suggestion is noted. You might also be interested in our "Power Systems Engineering Vlog" series. Signup now and get 30 days FREE Trial: bit.ly/PSEVlog
Now I see y u dint get many views for your lecture
what did u see?