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I'm a bit confused, at one instance you have the positive sequence current I_A(1) = 8367 A @ -90 deg. But later you have the same quantity = 8367 A @ 0 deg.? and then back to -90 deg. Which one is it? Can't wait for the next video! Love these.
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At 5:22 why use the 13.8 kV to find I_base when we have selected 115 kV as V_base? And at 10:00 isn't the per unit +sequence current -j6.667p.u ? why use +j6.667p.u ? I suppose this is a rookie error as the result is 2,00005 p.u ....while with the -j6.667p.u the result is 0.00005
We used the 13.8Kv b/c we are determining the fault current on the LV or 13.8KV side of the transformer. If wanted to find the same fault current on the HV or 115kV side, then we will use 115kV in the base current calcs. We actually determine the fault current on the HV side later in this series :) Yes at @10:00 the per unit + sequence should be -j6.667pu (i forgot the minus sign) -- this gives us the same result. V_A^((1) )=1∠0°-(j0.15)*(-j6.667)=0pu Thanks,
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Love all your videos. One question though, at 7:44, why does the angle of IA1 change by -90 degrees for phase B and C? Shouldn't the "a" operator be the only thing changing the angles because this is a symmetrical fault? I would have thought they'd just be off by 120 degrees of each other.
Hi, first of all, thank you for your lessons, they have been very helpful. So, as some people already pointed out, you used V_Base the same as V_Fault, shouldn't it be the same V_Base = 115kV? You could change the V_Base at your will, but the I_A = -j6,6667 pu was already calculated using the V_base= 115kV, if it were to change the V_base to 13.8kV, shouldnt we recalculate IA? And again, thank you very much for your effort, from the multiple courses/classes i've seen on youtube, yours has been the most intuitive and simple approaching this complex subject.
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Excellent Videos... They are extremely helpful! I have a question at 10:40. It is stated previously that the -ve and zero sequence voltage values for Va are also 0 for a balanced system. But when the equations are evaluated, you use 1 angle 0 for the -ve and zero sequence Va values in equations Vb and Vc. Should it not be 0 angle 0 for the -ve and zero sequence Va values?
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Sir, why is the calculation of Base current = S_base / (sqrt 3 * V_fault)? Shouldn’t it be S_base / (sqrt 3 * V_base)? And u mentioned that the selected base voltage is 115kV as it is the generator bus voltage. Thanks.
Thank you for your positive feedback, its really encouraging for us :) We've a course for you which covers a variety of Power System concepts with detailed explanation and we're offering free 30-Days trial. You can have a look at it here: bit.ly/PSEVlog
In calculating the base current the units considered for power is in MVA and that for voltage is in KVA , Hence it seems the base current unit should be in KA rather than A , Kindly advise on the same .
Hi Thoppil, Yes you are right. The answer should be in kA, but here the provided answer is given directly after making all the conversion. You can verify the answer with the below mentioned calculation: Ibase = 30 MVA / √3*13.8kV Ibase = 30,000 kVA / √3*13.8kV (1 MVA= 1000 kVA) Ibase = 1255 Amp Thanks, GeneralPAC by AllumiaX
Hope you realize there are no generators rated voltage 115 kV and rated power 600 MVA. Also for phase current Ib there should be a*inverse_component instead of a^2*inverse_inverse component.
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7:25 why the IA value is 8367
Hey, you are right. It is a typo there. Thanks for sharing.
Thanks for high efforts
finding the voltage at 13.8 bus you need to take the value of current with negative sign
Hi Noman,
Thanks for your encouraging remarks, it boosts us to bring you more value via our content.
Thank you for pointing this out. We have noted your concern and will make the required changes. We appreciate your help in this regard.
GPAC Team
I'm a bit confused, at one instance you have the positive sequence current I_A(1) = 8367 A @ -90 deg. But later you have the same quantity = 8367 A @ 0 deg.? and then back to -90 deg. Which one is it?
Can't wait for the next video! Love these.
At instant 7:27 The value of Ia(1) is equal to 8367 angle -90 degrees and not 8367 angle 0 degrees.
@@Generalpac Ok great thanks.
Support us by becoming our patron at patreon.com/generalpac ....Why?
An incredible amount of time and effort is needed to develop high-quality video tutorials. Each video takes approximately 10 hours to complete which includes learning the concept ourselves, brainstorming creative ways to teach and explain the concepts, writing the script, audio recording, video recording, and editing. This is why Hundreds-of-Thousands of people have watched, liked, subscribed, and left positive comments.
At 5:22 why use the 13.8 kV to find I_base when we have selected 115 kV as V_base? And at 10:00 isn't the per unit +sequence current -j6.667p.u ? why use +j6.667p.u ? I suppose this is a rookie error as the result is 2,00005 p.u ....while with the -j6.667p.u the result is 0.00005
We used the 13.8Kv b/c we are determining the fault current on the LV or 13.8KV side of the transformer. If wanted to find the same fault current on the HV or 115kV side, then we will use 115kV in the base current calcs. We actually determine the fault current on the HV side later in this series :)
Yes at @10:00 the per unit + sequence should be -j6.667pu (i forgot the minus sign) -- this gives us the same result.
V_A^((1) )=1∠0°-(j0.15)*(-j6.667)=0pu
Thanks,
@@Generalpac Thank you for answering! Your work is top class really! I managed to grasp these fundamental concepts easily! I wish you the best
At 7:26, the angle should have been -90 degrees....
We are very anxious for new videos...we are studying from Brazil...please carry on!
Watch part 3b, 3c-1, and 3c-2 here: www.patreon.com/generalpac/posts?tag=fault%20anlaysis If you are not a patron, you are missing out! Only our patrons get access to the latest GPAC Video Tutorials. That will help us to carry on =)
Love all your videos. One question though, at 7:44, why does the angle of IA1 change by -90 degrees for phase B and C? Shouldn't the "a" operator be the only thing changing the angles because this is a symmetrical fault? I would have thought they'd just be off by 120 degrees of each other.
Your tutorials are awesome.
Hi, first of all, thank you for your lessons, they have been very helpful.
So, as some people already pointed out, you used V_Base the same as V_Fault, shouldn't it be the same V_Base = 115kV? You could change the V_Base at your will, but the I_A = -j6,6667 pu was already calculated using the V_base= 115kV, if it were to change the V_base to 13.8kV, shouldnt we recalculate IA?
And again, thank you very much for your effort, from the multiple courses/classes i've seen on youtube, yours has been the most intuitive and simple approaching this complex subject.
🎁 Enter the Thanksgiving Power System Pack Giveaway with your email! 🍀 One lucky winner will receive the Power System Fundamental Pack on November 23rd, and ALL participants get a FREE top-selling course. 📚
Sign in: bit.ly/thanksgiving-day-2023
Very good sir but can you help me how to calculate or measure positive ,negative and zero sequence impedance please make one video about this topic.
Excellent Videos... They are extremely helpful! I have a question at 10:40. It is stated previously that the -ve and zero sequence voltage values for Va are also 0 for a balanced system. But when the equations are evaluated, you use 1 angle 0 for the -ve and zero sequence Va values in equations Vb and Vc. Should it not be 0 angle 0 for the -ve and zero sequence Va values?
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Sir, why is the calculation of Base current = S_base / (sqrt 3 * V_fault)?
Shouldn’t it be S_base / (sqrt 3 * V_base)?
And u mentioned that the selected base voltage is 115kV as it is the generator bus voltage.
Thanks.
We used the 13.8Kv in the base calcs because we want to find the fualt current on the 13.8kV or LV side of the transformer.
@@Generalpac So which does this mean that we are going to use 115kV if the fault was happed in the HV side?
Very good video, thank you so much for sharing and excellent explanation . I love this video.
Thank you for your positive feedback, its really encouraging for us :) We've a course for you which covers a variety of Power System concepts with detailed explanation and we're offering free 30-Days trial. You can have a look at it here: bit.ly/PSEVlog
Excellent stuff, can’t wait until till the next video!!
Thanks 🙏
You're welcome!
it is really useful video, eager to watch the next video.
In calculating the base current the units considered for power is in MVA and that for voltage is in KVA , Hence it seems the base current unit should be in KA rather than A , Kindly advise on the same .
Hi Thoppil, Yes you are right. The answer should be in kA, but here the provided answer is given directly after making all the conversion.
You can verify the answer with the below mentioned calculation:
Ibase = 30 MVA / √3*13.8kV
Ibase = 30,000 kVA / √3*13.8kV (1 MVA= 1000 kVA)
Ibase = 1255 Amp
Thanks,
GeneralPAC by AllumiaX
Thankyou very much sir, it was nicely explained by you. Waiting for next videos to come in fault analysis.
When you calculate the base current why did you but voltage =13.8Kv , instead of 115Kv Which is the Voltage base you used in the previous video?
I had the exact same question but I guess he never answered your question
Thank you very much sir
Please can you upload Part 3b
Hope you realize there are no generators rated voltage 115 kV and rated power 600 MVA.
Also for phase current Ib there should be a*inverse_component instead of a^2*inverse_inverse component.
This is more of an academic / intellectual exercise per the book example. Definitely not "real world application" as you suggested
@@Generalpac Of course if you switch base voltages to be more realistic, the calculation is the same in p.u. system. That is the beauty of it..
Awesome sir very helpful
Thank you
Sir may we all students have a wahatsapp study group under ur guidance please sir make a group