I want to take this opportunity to thank you for the priceless advice during my 5 months GMAT journey through this UA-cam channel. I did my GMAT yesterday, 4th April in Nairobi, Kenya & hit my target.
Hello Tiffany, thank you so much for this session! 1 clarification- at 25.50, why are we taking the formula for equil. traingle as 1/2 bh and not root 3/4 a square. Just to clarify if this is 'coz we see that the sides' measurments are different? That threw me a little. Thank you.
Exactly! all we know about the shape is that its diagonals bisect each other, its a parallelogram and all it angles are 90 degrees and both squares and rectangles have these properties. It can be either of them. correct answer has to be E.
Thanks for your question! A parallelogram is a four-sided figure with opposite sides parallel. This includes squares, rectangles, rhombuses, etc. Statement 1 simply provides a rule indicating that the figure is a parallelogram, so it could be a rectangle, a square, or even more importantly, a rhombus. Statement 2 narrows this down and indicates that the shape must have all angles equal to 90 degrees. This rules out rhombus as an option, indicating that the shape must be a rectangle or a square, as you point out. However, squares are a special subset of a rectangles, so either way - the question is answered when you combine both statements. Yes, the shape is a rectangle.
In the first problem, you mentioned that the second statement is not sufficient because it could be a square. I think you meant that it could still be a rhombus?
Hi, DmitryFarber was supposed to conduct a prep hour session. I got to know it from the GMAT club but missed the session, so could you please upload the session? Thanks!
Hello Arthus. Can you provide more information about why you believe this is false? It looks like Jeffrey Vollmer answered one of your questions on this topic.
I want to take this opportunity to thank you for the priceless advice during my 5 months GMAT journey through this UA-cam channel. I did my GMAT yesterday, 4th April in Nairobi, Kenya & hit my target.
So happy to hear this - Congratulations! 🎉
@@manhattanprepgmat6791 Thank you so much!!!
Thank you Ma’am. I’ll come back to this page for co-ordinate geometry.
Hello Tiffany, thank you so much for this session! 1 clarification- at 25.50, why are we taking the formula for equil. traingle as 1/2 bh and not root 3/4 a square. Just to clarify if this is 'coz we see that the sides' measurments are different? That threw me a little. Thank you.
In question 1 why does statement 1 prove that its a parrelelogram? Can't it also just be a square. So the answer will be E?
Exactly! all we know about the shape is that its diagonals bisect each other, its a parallelogram and all it angles are 90 degrees and both squares and rectangles have these properties. It can be either of them. correct answer has to be E.
The answer is C because a square is a special kind of rectangle, all squares are rectangles but not all rectangle are squares.
@@camilleblandin53 that's the answer E because a parallelogram isn't the same thing than a quadrilateral
Thanks for your question! A parallelogram is a four-sided figure with opposite sides parallel. This includes squares, rectangles, rhombuses, etc. Statement 1 simply provides a rule indicating that the figure is a parallelogram, so it could be a rectangle, a square, or even more importantly, a rhombus. Statement 2 narrows this down and indicates that the shape must have all angles equal to 90 degrees. This rules out rhombus as an option, indicating that the shape must be a rectangle or a square, as you point out. However, squares are a special subset of a rectangles, so either way - the question is answered when you combine both statements. Yes, the shape is a rectangle.
@@manhattanprepgmat6791 I do not understand why statement 1 told us that it is a parrallelogram...
In the first problem, you mentioned that the second statement is not sufficient because it could be a square. I think you meant that it could still be a rhombus?
Hi, DmitryFarber was supposed to conduct a prep hour session. I got to know it from the GMAT club but missed the session, so could you please upload the session? Thanks!
Hi! Here is the recording of Dmitry's most recent Free Prep Hour: ua-cam.com/video/dBiJxeUD9xE/v-deo.html
The answer you gave for the first question is false ... tell me if i'm wrong
Square is also a rectangle. The instructor is wrong.
Hello Arthus. Can you provide more information about why you believe this is false? It looks like Jeffrey Vollmer answered one of your questions on this topic.
@@tiffanyberkebile2043 Because a square fulfills all the properties of a rectangle?
take the shape : A(1,0) B(0,0) C(0,3) D(1,1) , verify statment A and B but isn't a rectangle ...
The diagonals in your shape would not bisect one another, so the shape does not verify Statement 1.
"Bisect" means to cut something perfectly in half.