jeff i want u to know that i have my statics final tomorrow and you have carried me thru this course thus far. i have a good A rn and only need about an 80 to keep it on this final. and i have u to thank for that. u are amazing at what u do and i could never be more grateful for this online course. i love you man
The corner is the only part of the box still touching the floor, since the box is tipping over. Since the middle of the box isn't touching the floor it doesn't experience a normal force.
Could you decide which of the first two cases is more likely to occur by comparing the two max forces of friction? and could you decide beween cases 3 and 4 by comparing the moments of the friction forces?
I forgot to tell tip for friction problem Always write Fs( friction force) in coefficient × normal like 👉 .5 ×N For example two many forces are acting you Don't know any force this will help if you find normal you have fs if you find fs mean you have normal as well it helps when drawing FBD
Dr thanks alot I done 52 problem now I am at 53 and so far if you give wieght I can tell you tipping force and slipping force or if you give me cofficient I can tell you angle of slipping so far,
If u take sum of the vertical force ans is 54 but if you find vertical force by moment its 48.6 why ? Why? Length 18 ,Wieght 54# vertical suport after 10ft man push horizontally from 1 side( no other force acting)
Professor Hanson, thank you for a fine explanation of Friction Slipping Tipping Problem. From taking Engineering Physics One many years ago, I am very familiar with these classic mechanics problems.
Your videos are excellent! My only comment is that on the top stack tipping, the force should have been 900#. I think you forgot to divide by the 0.5 in front of P. Of course, this just drives home the point you are making even more!
Each case solves a very different problem, the one with the smallest force is the answer to the problem that you are solving. So in the first case, we were assuming that NO MATTER WHAT, that whole stack was going to slide before any of the other possibilities would happen and solved for the force that that would take. The force that it would take in the first case (105N) becomes completely irrelevant as soon as one of your cases has a smaller number because the case with the smallest force required will happen first and make the rest of the cases impossible. So basically in that first case, we are assuming that the ground friction will slip before the box-to-box friction so we don't even have to worry about the box-to-box friction. Hope that makes sense!
jeff i want u to know that i have my statics final tomorrow and you have carried me thru this course thus far. i have a good A rn and only need about an 80 to keep it on this final. and i have u to thank for that. u are amazing at what u do and i could never be more grateful for this online course. i love you man
mine is in an hour ive been binging his videos
Ahahaha "WHAT DOES THE BOX WEIGH?"
Suddenly i'm seeing a fox with a box going "FOO FOO CHOO FOOO FOO FOO CHOO!"
how you make things looks so easy??!!! i have a static exam tomorrow, living on ur videos hahaha
YOU ARE THE BEST ENGINEERING PROFESSOR IN THE WORLD!
“What does the box weigh”😂
I’m so glad I found this channel!!
Wonderful Statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
thank you so so much for making this so easily digestible
You are a living legend!
So the location of the center of mass on the y-axis has no bearing on these cases? Does that only come into play after the object has started to tip?
why do you take the normal force at the corner by the moment?
The corner is the only part of the box still touching the floor, since the box is tipping over. Since the middle of the box isn't touching the floor it doesn't experience a normal force.
you are amazing i love you so much, you make everything seem so interesting and fun and love your jokes.
I like you dude! Just reviewing stuff for fun and ran across your awesome video! Thanks for being cool.
What if a box is top heavy or bottom heavy? How do you model the moment it tips then?
Could you decide which of the first two cases is more likely to occur by comparing the two max forces of friction? and could you decide beween cases 3 and 4 by comparing the moments of the friction forces?
ok, dumb question, but I got confused when he was finding the moment around point c, which corner did he declare as point c?
chettan pwoliyaa!!
Amazing lesson
I forgot to tell tip for friction problem
Always write Fs( friction force) in coefficient × normal like
👉 .5 ×N
For example two many forces are acting you Don't know any force this will help if you find normal you have fs if you find fs mean you have normal as well it helps when drawing FBD
I love the way you explain its make me repeat it again thank you now i understand it and the information still in my mind😁😁
loved this one a lot
+10. Great video Jeff. Thanks
Dr thanks alot I done 52 problem now I am at 53 and so far if you give wieght I can tell you tipping force and slipping force or if you give me cofficient I can tell you angle of slipping so far,
If u take sum of the vertical force ans is 54 but if you find vertical force by moment its 48.6 why ? Why?
Length 18 ,Wieght 54# vertical suport after 10ft man push horizontally from 1 side( no other force acting)
Isn’t it possible for the top box to tip on its left corner?
That situation is the same as pushing the boxes and they fall at you when you touch them. There is no external force that pushes the boxes ccw.
thank you, wish me luck on my statics exam😅
u r my god
Moment is more reliable then sum forces vertical sum of forces horizontal
i love you
step 1 : don't show up to class for 80% of the semester
step 2 : binge watch all videos the night before your final
step 3 : ace the class😎
I mean idk yet about step 3 I still need to take the test
“That’s never gonna happen is it?” *circles it as the answer*
I love the verse at the end!!
Dr my advice for students solve all problems in the book every problem is different and you will face same problems in real life
Professor Hanson, thank you for a fine explanation of Friction Slipping Tipping Problem. From taking Engineering Physics One many years ago, I am very familiar with these classic mechanics problems.
Your videos are excellent! My only comment is that on the top stack tipping, the force should have been 900#. I think you forgot to divide by the 0.5 in front of P. Of course, this just drives home the point you are making even more!
No,it is 90. You just need to divide with 5 not 0.5
Why didn't you use the friction between the two boxes in the first case?
Each case solves a very different problem, the one with the smallest force is the answer to the problem that you are solving. So in the first case, we were assuming that NO MATTER WHAT, that whole stack was going to slide before any of the other possibilities would happen and solved for the force that that would take. The force that it would take in the first case (105N) becomes completely irrelevant as soon as one of your cases has a smaller number because the case with the smallest force required will happen first and make the rest of the cases impossible. So basically in that first case, we are assuming that the ground friction will slip before the box-to-box friction so we don't even have to worry about the box-to-box friction. Hope that makes sense!
Can anyone say me the best UA-cam channel for physics
This useful .
I done first section of chapter now watching second section video
G.O.A.T
you would be a great dad
sir can you please increase the sound of your videos
frictitious :D
In india we learned this in middle school. The west is falling behind
Ok.