Nice Algebra simplification।। find value of a and b।। maths olympiad question @mathscuriosity494
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- Опубліковано 15 вер 2024
- Nice Algebra simplification।। find value of a and b।। maths olympiad question @mathscuriosity494
If, a²-b²=49 then find the value of a and b
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a^2-b^2=49 a=25 a=7 b=24 b=0 (a,b)=(25,24),(7,0)
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=(a-b)^2= 49]= 7*7=7^2=2]= a-b^2=2 a-b=2-2=1 a=b+1=b ] a=b=1
a,b = 7,0 & 25,24
25 to the power 2 is 625 and 24 to the power 2 is 576. 625-576=49. Hence a=25 b=24
Given a and b are natural numbers (7,0) is not a valid solution.well explained 👍
Simple when a^2-b^2 is odd just divide the odd number into two equal parts, answer is there 49=24+25, 25 and 24 is an answer
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a=7 , b=0
a=25
b=24
25,24 is the correct answer since 0 is not a N number
First hu chand mere bhai ❤
If a, b are natural numbers, then value of b should not be zero. Am I right ? 0 is not a natural number.
a=25 and b=24.
(A-B)(A+B)=16 thenA=? B=?
A= 5, B= 3 or A=5, B= -3
b=0 is not possible 0 not belongs to N
It is huge mistake only a=25 and b=24 is solution
0 is not a natural number
The natural number starts from 1. The numbers which are used for counting are called natural numbers. 1,2,3,.........
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