The Arrhenius Equation

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  • Опубліковано 17 гру 2024

КОМЕНТАРІ • 13

  • @Oramosengr
    @Oramosengr 2 роки тому +8

    Love the different ways to write the equation! I moved things around and my problem was cake! Thank you!

  • @patriciaflores5460
    @patriciaflores5460 3 роки тому +1

    Thank you so much, Sir! I really learned a lot from your vids! More power

  • @footballeditzs4957
    @footballeditzs4957 4 роки тому +1

    Excellent video which throughly explained the concept

  • @williamcullen2759
    @williamcullen2759 4 роки тому +4

    How do you work out the uncertainties for them?

  • @gautama2168
    @gautama2168 5 місяців тому

    Great knowledge ❤

  • @Anime_games-_-XUnknown
    @Anime_games-_-XUnknown 9 місяців тому +4

    Isn't the rate constant supposed to be 8.314 J /K¹ mol¹ here..

    • @azal-jameel22
      @azal-jameel22 8 місяців тому +1

      8.314 is in joules, but what is in the video is 0.008314 kJ, so it is 8.314/1000 to convert to kJ

  • @cricketpatients2202
    @cricketpatients2202 3 роки тому +1

    🖤🖤🖤very nice 🖤🖤🖤

  • @divineayemien8884
    @divineayemien8884 11 місяців тому

    Please sir how did you get the 1/T and ink

  • @Knob126
    @Knob126 4 роки тому +1

    Thank you sir

  • @zaraakubra4118
    @zaraakubra4118 Рік тому

    I extract iron from iron ore and know i will calculate the arrhenius equation. So my experiments under temperature are 343K ,353K and 363K , 373k and 383k for each temperature time is 10,20,30,40 and 50 mints .So how can i find arrhenius factor there activation energy and rate constant.
    Equation is k= A × e^Ea/RT
    R is gas constant 8.315 J.K^-1 mol^-1.
    Actually i want to calculate these data to make a graph lnk verses 1/T.
    As i done kinetics model equations. In which 1-(1-x)^1/3 equation is best fit because the highest R² values.
    From where i can get this rate constant K.

  • @SamuelSocceresports
    @SamuelSocceresports Місяць тому

    Anyone preparing for 1 day before exam

  • @omarakoey7088
    @omarakoey7088 Рік тому

    It was great but you should have used the linear regression on calculator