Harvard University Admission Question | Solve For Sqaure root of Iota? | Algeria

In this video, I'll be showing you step by step on how to solve this Harvard University Admission Problem using a simple trick.
Please feel free to share your ideas in the comment section.
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[@ubiraceelihimas]

Muito bom, já tinha resplvido

[@andretewem3385]

Easier with the polar writing.
Set i = (1,pi/2 + 2k.pi)
with k = 0 or 1.
Then for k = 0 ==>
sqrt(i) = (1,pi/4) =
(sqrt(2)/2).(1 + i)
for k = 1 ==>
sqrt(i) = (1,pi/4 + pi) =
(-sqrt(2)/2).(1 + i)

[@gp-ht7ug]

Hello, why didn’t you apply sqrt(i)=sqrt(e^(i*pi))?

[@germanalexandru]

i=(-1 + 2*i + 1)/2=[ (i + 1)^2] / 2
The rest is simple.