6:10 You said 'the colour band is grey' but highlighted the green band on the table. I think it would be better if you put a caption for correction because I see many people bewildered by the contents of the video. Other than that, pretty well explained. Great job
You should include the voltage drop across the LED when calculating the resistance required to produce 30mA. Typically, red LEDs operate at 2V. So the calculation should be (9V - 2V)/0.03 = 230 ohms. However, with 300 ohms, the current will be 23mA, which is better than 30mA, because you should never operate any device at its rated maximum.
At the 2:28 mark you converted the mille amp ( 1/1000th ) of 30 to 0.03 to give 9/0.03 . Others may not have caught that if they were just checking the tutorial out.
The LED part is inaccurate, since you didn't take into account the voltage drop on the LED. A 3mm red LED has about 1.7V drop across it, so the drop on the resistor is about 7.3V. The correct equation is R=7.3V/30mA, so R=243.333Ω
Great video; however, I see two mistakes right away. 1st one is the LED itself, its hooked up backwards, shorter leg is usually/normally always negative. The 2nd mistake is that he chose the wrong value of the resistor's Multiplier, even though he did say the right one (he chose green instead of gray).
@Brian, I am starting my first project. I need someone with knowledge to review my project contents and recommend missing/needed resistors, etc to complete my project to fully function able in all areas. Can I resource you? I have a handicap that limits the way/method I obtain knowledge. Hence the “first” time, I need guidance/ assistance. I am determined not only to complete this project… but obtain. Skills to complete a total of 250 projects on my own….later on. Most Humble Appreciation! Alton
if you take the example of a hydraulic pipe then when the flow of the water is resisted hence creating pressure and the same happens with resistors then shouldn't the voltage shoot up in relation with the flow of electrons? just like when you press the tube of a vinyl pipe when water is flowing through it?
Does resistor delays power consumption? i had a case of smoke generator that i mdel a coil out of vape wire and a 5v fan and the power was 7.5volt 1000mah rechargeable battery, it runs for roughly 8 -10 minute and the power will ran out, one of the biggest reason i'm thinking on adding a resistor was i hope it would slow down the flow of the current but does this actually means same amount of power would still be wasted ? and that protects the fans and the heater wire coil from burn out?, i'm working on my second homemade smoke generator for my RC(remote control) tiger 1 1:16 , but this time the boiling chamber was much more compact and smaller which made the smoke liquid runs out even faster and the coil would caught lit up with fire and later extinguish itself when the oxygen in the bottle was used up, i still had a lot of adjustment to do with this smoke generator , improved until it was much more feasible to use than conventional aftermarket smoke generator.
According to formula , when you use Voltage , you must use Amper as a unit.So there is a conversion between milliampere to Ampere then 30mA makes 0.03 Ampere.Actually they are the same value.
Hi, when a current enters the resistor does it decrease the amount of electrons and we get less electrons comes out of resistor (at the other end) OR it (resistor) decreases the speed of electrons and we get slower electrons coming out from the other end of the resistor? Also when we say that 2A is going through resister R , does that mean before entering the resister or after the resister? Please help
Lovely video content! Apologies for the intrusion, I would appreciate your thoughts. Have you considered - Qanayce Wiyulian Equalizer (Have a quick look on google can't remember the place now)? It is a good one off product for unveiling the technique to repair your electronic items without the hard work. Ive heard some interesting things about it and my work buddy after many years got excellent results with it.
would you please tell me if you know that in the 6 minute and 9 seconds you; it seems make the grey band calculate with a green value .....if this is so then you may want to indicate a correction and give the video the high standard you have with the rest of it , for the sake of those who are less able to deal with errors in their self educating. I appreciate the hard work you all put into the priceless videos on youtube in this field. thanks john
This version of the essential resistor was designed and developed in 1959 by Chicago inventor, Otis Boykin. Mr. Boykin would later become better known for his next invention, a control unit for the pacemaker, which used electrical impulses to stimulate the heart and create a steady heartbeat.
Around 4:00, how does the wire become a resistor for the wirewound? Is it the material it is made of? Wrapping a wire around a piece of wood doesn't reduce current, does it?
***** that is practically the only reason or the coloured stripes also if you were wondering how high wattage power resistors work, they are just thicker cable
Mitch Sandoe the f#@! you mean by nope?!!!! it is a Light Emitting DIODE!!! get your facts right! diodes only allow electric current one way!! yes IT DOES MATTER!
Anas Malas You're correct. If you're not trolling, than you've misunderstood the question. To clarify, the arrangement of the resistor and LED in series does not matter in series so long as you have the diode forward biased.
2:51, Im new to this topic, and trying my best to understand but im a little confused at this point...... you say that the 9v batter will burn out the led, well instead of using a resistor why dont people use a different battery ? one with less voltage? I dont see the point of a resistor at all, , why cant we just use the correct battery?
I'm also new so I might be wrong but, what if you didn't have another battery? And it's better applied to more complex circuits where there is a constant source. Which means some components can't handle that much current so use a resistor to provide to those components. If you see what I mean.
We better use resistor than changing battery because high voltage batteries are more efficient than low ones, even if adding resistor within the circuit. Just my opinion.
And should u dont get why high voltage batteries are more efficient than low ones, because P=V.I. The higher the current I, the higher the power loss due to conductor and thermal losses. So they have to make higher voltage batteries than components requirements to maximize efficiency
That was actually a very bad example use of a resistor; I was cringing as I watched it. Changing voltage is often not a reasonable option, since LEDs are frequently just used as indicators in a larger circuit. If I'm working with a circuit that primarily uses an automobile supply voltage (~13.8VDC), I may not want to step-down the voltage just for some LEDs. A voltage regulator doesn't save any energy and a buck converter is unnecessary complexity. LEDs have very low resistance, which is why you won't find them powered directly with a battery; however, they drop voltage. The voltage dropped across a diode is called the "diode drop." Red LEDs drop around 2V. If running maximum rated current, then you'll want to check the specifications for your LED. The diode drop occurs regardless of the potential (voltage) in that branch of your circuit. So, I'll use the example from this video. If you power the circuit with a 9V alkaline battery, you should expect supply voltages up to around 9.6V. Subtract the diode drop of the LED (9.6V - 2.0V = 7.6V), then calculate the resistor based upon the result (7.6V / .03A = 253.3 Ohms). Neglecting the diode drop when calculating the resistance for a single LED on a 9V battery may result in a slightly dim lamp. But on a regulated 3.3V supply, you'd better calculate your LED's resistor after subtracting the diode drop, because a 330 Ohm resistor will NOT supply your LED with 10mA.
This is amazing. I have a question though. why does a resistor have to be on the positive lead? I understand that the assumption of the current direction ( from +ve to -ve ) was a mistake bcuz scientists when they were first working with electricity, they didn't know about the structure of an atom. Shouldn't we adopt the correct direction then to prevent the LED from burning out? which is from -ve to +ve? (Thank you in advance for any help you might be able to provide)
So does the resistor change its Ohms if connected to something else ? Like, using that same as in the LED example, with another 45mA LED, will that same resistor switch to 200 Om ? Or is that value a constant depending on what ? The material that resistor is built with ? Can that same transistor be used for some high voltage stuff like city electrical connections with 1.000.000 V ? If no why not ?
Yes, when you connect two or more resistors in series in a ckt, (i.e R1 & next to it, R2, R3), each resistor values (ohms) "R" are added, as to find Equivalent Resistance Requ= R1+2+R3, while calculating the current flow I=V/(R1+R2+R3)=V/Requ. The reason is , the voltage potential at the first resistor arriving at the resistor R1 is taken as Voltage for calculating current flow on each resistors in series. Hence, the current flows on all the resistors will be the same, but with drop in voltage.
No I don't think that is correct. By ohm's law: V=(A)(R) The higher the resistance, if the amperage stayed the same, voltage would also rise proportionally; obviously, that is NOT what happens, resistors do not add voltage. If the voltage stays the same (given a potential differential = X from a given source like a battery) and if we change the value of the resistor, then what must change is the current to make the numbers add up: V=10 R=10 , 100 , 1000 A=X 1. 10=(x)(10) A=1 2. 10=(x)(100) A=0.1 3. 10=(x)(1000) A=0.01 The higher the resistance = the LOWER THE CURRENT.
I got a little light-headed trying to absorb all that. Actually for a guy as dumb as me, it made good sense. I now have a basic understanding of what resistors are. Thanks.
I just started learning, but here I get confused - Which way do the electrons flow in a battery? my previous reads "negative to positive" but here he connects resistor in positive side. Pls clarify me..
In physics, for stupid reasons, you have conventional flow, which is the flow of positive charges towards a negative charge, and electron flow, which is negative to positive. When talking about current, you say that it moves from positive to negative. When talking about electrons, you say negative to positive.
thanx for the information but can any one say that in the video it was shown that by connecting the resistor in series with bulb the current was controlled but in case of theory we use to say that for series connection of resistors the current flowing is same at all the resisters connected in series what does it mean?
Hello my resistor has burnt out but it look's like it is 1 brown and 3 black, can you please tell me what the resistor strength is, or even if you can get that configuration. Thanks and hope you can help. I've asked 4 other people but they haven't answered. Please help.
Great vid, thanks for sharing. Do you know where I can find an electrical board hr51a? It is used for charging an 18v. There is only 4 parts on this board, 3 are resisters I don't know what the other part s is. It is a cylinder shape thing with 3 loops around it . Two brown and one black. Thanks
I have the same question! please anyone explain why he put the resistor in the positive side? I believe that the current will move from the negative to the positive, so it will pass the light from the positive one. Thus, we need to limit the current flow before gets in the light to avoid blowing out! im just confused now!! please explain, Thx
Ahmed AlGazi an electrical current goes from positive to negative so it will first reach the risistor and then reach the LED. As they will say in Holland: Nothing on the hand.
I'm sure you could. Conventional current flow as used in diagrams and designs show the electrical path going from positive to negative, but electrons in a circuit actually flow from neg to pos, while the hole flow is from pos to neg..
When we draw a circuit, we usually assume that current (an amount of electrons) flows from positive to negative. They actually flow from negative to positive. This was discovered a long time ago but we still use + to - in diagrams for convention. www.mi.mun.ca/users/cchaulk/eltk1100/ivse/ivse.htm
Everything Perfect except the green color band was actually grey and the green should have been 100K not 10 K . Thank you for this video. It helped a lot.
You may only use resistors if they have been preapproved by the Federal Resistor Polarity Commission for handling either positive charge (protons) or negative charge (electrons) else your circuit will either start generating antielectrons or antiprotons (depending, obviously, on the type of resistor you are attempting to abuse) and explode or it will suddenly vanish into the 8th dimension. Never ever forget: Knowledge is Power in today's increasingly technological world.
Ok, so I know this might be a noob question, but what do I put I front of an LED if I want a short delay after I switch the circuit on? If you want to know why I'm asking, it's because I'm soldering some LEDs to my xbox controller and I want to have a delay for each of them when the rumble activates. I am using 6 LEDs, 3 on each side of the clear front trim (what I mean is after 1 second 1 led lights then after 2 seconds 2 LEDs light and after 3 secs all 3 (on each side) light up). It would be amazing for a reply. Thanks!
Well, since that us their primary job, I would say no, but given the tolerance of the resistor you using some might drop a little bit more than others inside their specified tolerance.
The analogy with water flow was incorrect. Making the tube more narrow will not reduce the current, but speed it up in that area. And the current will return back to what it was when the diameter of the tube returns back to its original value. Also, the pressure on the left is the same as on the right. It's the pressure in the middle that is reduced. You would be better off using a water wheel to represent the resistor. Somebody please correct me if I'm wrong.
Go to the hardware store. Buy two feet of PVC pipe with a 4 inch diameter, and two end caps. Drill a 3 inch hole in one of the end caps, and an eighth-inch hole in the other. Put the cap with the 3 inch hole on the pipe. Orient the pipe perpendicular to the ground, cover the hole, and fill the pipe with water. Use a clock, and record the amount of time it takes for the pipe to drain. Repeat with the 1/8" inch cap. Voltage in this case is supplied by the earth's mass. Gravity acts on all of the water at the same time and "wants" it to get through that pipe. The voltage therefore never changes, but the flow will. If you do this experiment, you will see that decreasing the size of the hole increases resistance of flow, resulting in less volume exiting the pipe in a given second. All a water pressure regulator does is change the size of a hole (or diaphragm) based on some input. The flow of water is a great analogy when it comes to explaining the relationship between voltage, current, and resistance.
vegasbryan I hear what you’re saying, and you’re not exactly wrong, but your example isn’t analogous to the situation at hand. Filling pipes with water and letting it fall out of holes of different diameters doesn’t include a constant mass flow rate as an example with connected pipes does. The amount of water going into a section of a pipe is the same as the amount of water coming out. Therefore if the section’s diameter were reduced, the water would have to flow faster (increased current) in order to keep a consistent mass flow rate. Even with a consistent push (voltage). Think of it like this. If you put a nozzle on a water hose, the water coming out will be moving faster than the water moving through the hose because it has to keep a constant mass flow rate with decreased volume. This isn’t the case with a circuit, which is why using a smaller diameter valve to represent a resistor isn’t accurate. A resistor is supposed to slow the current, not speed it up. This is why most lessons will use a water wheel to represent a resistor when using water flow to represent a circuit. A water wheel causes resistance, slowing the current and transferring the kinetic energy of the water to rotational kinetic energy of the wheel. In the same way, a resistor slows current and creates heat.
vegasbryan Wouldn't it be better though to say that in the case of a resistor, if we're talking about an analogy to electrical flow...that it would be the equivalent of making very small precise holes. Resistance is basically the amount of the electricity flowing through a conductor that's lost to heat, right? So it can't do useful work...Wouldn't that be equivalent in springing leaks in the pipe so simply not as much water reaches the destination (load)?
A resistor limits current in an electric circuit much like a partially closed valve limits mass flow in a hydraulic system. A redistribution of pressure occurs and more pressure drops across the valve to sustain a lower mass flow rate. When this occurs less pressure is available across the existing hose or pipe to maintain the previous water flow. A similar thing happens in an electric circuit, most of the voltage drops across the resistor (partially closed valve) to maintain a now lower electrical current. Less voltage is then available across the existing conductors to maintain the previous electron flow (current). Electrons actually do move faster in the resistor then they do in the conductor material since the resistance in the conductors is so low that they act like huge diameter pipes. The increased electron velocity creates a large transfer of energy into the resistor in the form of thermal energy (heat) and the resistor gets warmer in the process. You are right that the mass flow in a hydraulic system is the same everywhere in the system whether the water is moving quickly in a small diameter pipe or slowly in a large diameter pipe but fact remains that the mass flow rate is changed by a restriction in the system. A new, lower, mass flow rate is created by a restriction and the restriction requires a redistribution of system pressure to maintain the new lower mass flow rate.
Hi, I think u should correct formula at about 2:31 because it's approximative, assuming battery voltage 9 V and Led Voltage about 2 V ("standard" led, not for bright led types), we have Vbatt=Vresistor+VLed so 9=Vresistor+2 then Vresistor=9-2=7V. So we got R=V/I so R=7/0.03=233.3 Ohm. It's Different to 300 ohm, your formula is not correct, so if u use it and different voltages u could damage the led. U must consider right Voltage Drops...
No. I think you are confusing HydroStatics with HydroDynamics. Bernoulli's principle must be applied for incompressible flow through a pipe. Pressure and Velocity will change as a function of the diameter of the pipe. When the diameter diminishes, pressure goes down and velocity goes up. It is an energy conservation law. He used a bad analogy. The better analogy for potential(V), current(i) and Resistance(R) (Ohms Law: V=iR) is the vertical water pipe with gravity acting as the potential. The diameter of the pipe is the analog for resistance.
This was great, been searching for "what is a resistor pack?" for a while now, and I think this has helped. Ever heard of - Henucas Panrooklyn Equalizer - (should be on google have a look )? It is a smashing one off guide for discovering how to repair electronic devices like a pro without the headache. Ive heard some interesting things about it and my mate got great success with it.
+Arman Kordi You CAN use a pair resistors to reduce a voltage, it's called a voltage divider; however, it's only meant for low currents, typically to create a voltage reference for other components. A potentiometer is in fact a variable voltage divider.
helo,,, can i ask some question,, how can i control the dynamo speed,,, i mean i need to turn it to slow, is it using the adjustable resistor(variable)?? tq
I answer to your 2nd query first, Ampmeter is connected series to resistor for measuring the current being passed by resistor.When we say 2A is going through,i.e I=V/R, it's current Amp value = voltage drop (Vs-Vf)/Ohms measurement.Vs=voltage source(may be 9v or 12v),Vf=forward voltage (the volume going to be allowed to consume by device/simply say device rating voltage).This 2A current is allowed by the resistor.Now, for your 1st query, resistor is not controlling the speed of electrons.
Theres something wrong in this video but we can adjust for simple error ...make sure to be more strict in posting video to help more newbies but u explain well about the topic sir god bless and more power...
My receiver only stays on for 15 minutes then it will just turn off automatically m. What capacitor would it most likely be, please? Or is it something else?
Thank you so much over a year I am trying to understand this but, you did it to get me understand; by diagram examples with water pipe. | once again thanks___
so what if that 9v battery was 3v, how would I determine the current then? wouldn't I need the resistance of the led itself? I'm confused because everyone puts a resistor on their 3mm LEDs in xbox controllers. BUT it's 3v from the controller, which is what the LED's are rated for. So what's the point of the resistor?
FroztiProductions if the leds are rated for 3v what is there rated current rate? How many milliamps can they handle is what you need to know if it's any voltage could be 3v, 9v 12v you still need the resistor for a led as they are generally rated at 30ma like in this video and the resistors stop to much current going onto the led and burning it out, basicially like if it was a water pipe it stops to much water going Into the led and flooding it.
Well if they are rated for 3v I assumed the current rating would be calculated by that voltage the the internal resistance of the LED itself . I'll double check.
FroztiProductions - use a potentiometer ("pot") in series with the LED and battery, and adjust the pot until it glows just enough for you. Then use your multimeter to measure the resistance of the pot, and substitute it with a fixed resistor. Just be careful not to turn the pot too far down or you will burn out your LED. Oops!
These all resistance value colors below: Value. Color. Multiplier (x10) Tolerance 0. Black 0 1. Brown 1 1 % 2. Red 2 2% 3. Orange 3 4. Yellow 4 5. Green 5 0.5% 6. Blue 6 0.25% 7. Purple/Violet 7 0.1% 8. Grey 8 0.05% 9. White 9 10. Gold -1 5% 11. Silver -2 10% 12. No color --- 20% For example of 4 band or 5 band color of a resistor: For 4 band color: 10 Ω with tolerance is 5% (brown - black - black - gold) 47 Ω with tolerance is 5% (yellow - purple/violet - black - gold) 560 Ω with tolerance 5% (green - blue - brown - gold) 5.100 Ω (5,1k/5K1Ω) with tolerance is 5% (green - brown - red - gold) 15.000 Ω (15kΩ) with tolerance is 5% (brown - green - orange - gold) 270.000 Ω (270kΩ) with tolerance is 5% (red - purple/violet - yellow - gold) 2.000.000 Ω (2MΩ) with tolerance is 5% (red - black - green -gold) 12.000.000 Ω (12MΩ) with tolerance is 5% (brown - red - blue - gold) 240.000.000 Ω (240MΩ) with tolerance is 5% (red - yellow - purple/violet - gold) 1.000.000.000 Ω (1GΩ) with tolerance is 5% (brown - black - grey - gold) 47.000.000.000 Ω (47GΩ) with tolerance is 5% (yellow - purple/violet - white - gold) For 5 band color: 47 Ω with tolerance is 1% (yellow - purple/violet - black - silver - brown) 390 Ω with tolerance is 2% (oramge - white - black - black - red) 2.200 Ω (2,2k/2K2Ω) with tolerance is 1% (red - red - black - brown - brown) 51.000 Ω (51kΩ) with tolerance is 1% (green - brown - black - red - brown) 470.000 Ω (470kΩ) with tolerance 2% (yellow - purple/violet - black - orange - red) 1.500.000 Ω (1,5MΩ) with tolerance is 2% (brown - green - black - yellow - red) 15.000.000 Ω (15MΩ) with tolerance is 1% (brown - green - black - green - brown) 470.000.000 Ω (470MΩ) with tolerance is 1% (yellow - purple/violet - black - blue - brown) 1.500.000.000 Ω (1,5GΩ) with tolerance is 2% (brown - green - black - purple/violet - red) 56.000.000.000 Ω (56GΩ) with tolerance is 1% (green - blue - black - grey - brown) 470.000.000.000 Ω (470GΩ) with tolerance is 2% (yellow - purple/violet - black - white - red)
Absolutely brilliant tutorial; so easily explained for my science students to follow and understand. Thank you.
6:10
You said 'the colour band is grey' but highlighted the green band on the table. I think it would be better if you put a caption for correction because I see many people bewildered by the contents of the video. Other than that, pretty well explained. Great job
that's true
7 years on bro....you're sh*t's still important ✌️
You should include the voltage drop across the LED when calculating the resistance required to produce 30mA. Typically, red LEDs operate at 2V. So the calculation should be (9V - 2V)/0.03 = 230 ohms. However, with 300 ohms, the current will be 23mA, which is better than 30mA, because you should never operate any device at its rated maximum.
you should cheer for a better team
this 6 minute video explained more than all of grade 9 science.... Thank you!!!!!!!
Thankyou :)
+Sylvie Ruland hi hello
you aur so sexy girl
@@sylvieruland8697 Science sucks
Very nice lesson. Easy to understand and nicely put together :D Bravo!
Isn't the longest wire the positve side of the LED?
Kim Pacolet yes
Micco Millchris Reyes
so in 2:46 he should've connected the wire differently ?
hello brother resistor connected any way any side in only series the above circuit diagram is series diagram
The led should not work he has to flip it over and it is not called a lid
At the 2:28 mark you converted the mille amp ( 1/1000th ) of 30 to 0.03 to give 9/0.03 . Others may not have caught that if they were just checking the tutorial out.
whats a mille amp???
Thank you for making it understandable for someone like me with no knowledge of electronics.
Hi there
The LED part is inaccurate, since you didn't take into account the voltage drop on the LED. A 3mm red LED has about 1.7V drop across it, so the drop on the resistor is about 7.3V. The correct equation is R=7.3V/30mA, so R=243.333Ω
+yotam amit Yep, i noticed that too.
I think he was trying to simplify it
"the third band is grey.." picks the green one -_-
+Niels Langeweg He's color blind
+Niels Langeweg Just stay away from the light
exactly. wtf is going on?
also said it has x10k.. lol.
lol
faith in humanity restored. thank you for your to the point 0 fluff tut. Your a great speaker
Wow this was way more in depth than I thought it'd be. Thanks!
Great video; however, I see two mistakes right away. 1st one is the LED itself, its hooked up backwards, shorter leg is usually/normally always negative. The 2nd mistake is that he chose the wrong value of the resistor's Multiplier, even though he did say the right one (he chose green instead of gray).
@Brian,
I am starting my first project. I need someone with knowledge to review my project contents and recommend missing/needed resistors, etc to complete my project to fully function able in all areas. Can I resource you? I have a handicap that limits the way/method I obtain knowledge. Hence the “first” time, I need guidance/ assistance.
I am determined not only to complete this project… but obtain. Skills to complete a total of 250 projects on my own….later on.
Most Humble Appreciation! Alton
It looked better in this way,this video is more theory than practical
6:07 Has a grey band, points to green, says it has a multiplication factor of 10K...
I was going to comment that
Mistake over a mistake 😂
fuck man, totally. lol.
if you take the example of a hydraulic pipe then when the flow of the water is resisted hence creating pressure and the same happens with resistors then shouldn't the voltage shoot up in relation with the flow of electrons? just like when you press the tube of a vinyl pipe when water is flowing through it?
Does resistor delays power consumption? i had a case of smoke generator that i mdel a coil out of vape wire and a 5v fan and the power was 7.5volt 1000mah rechargeable battery, it runs for roughly 8 -10 minute and the power will ran out, one of the biggest reason i'm thinking on adding a resistor was i hope it would slow down the flow of the current but does this actually means same amount of power would still be wasted ? and that protects the fans and the heater wire coil from burn out?, i'm working on my second homemade smoke generator for my RC(remote control) tiger 1 1:16 , but this time the boiling chamber was much more compact and smaller which made the smoke liquid runs out even faster and the coil would caught lit up with fire and later extinguish itself when the oxygen in the bottle was used up, i still had a lot of adjustment to do with this smoke generator , improved until it was much more feasible to use than conventional aftermarket smoke generator.
Why did the 30mA turn into 0.03 on the equation at 2:28 ? Thanks in Advance !
According to formula , when you use Voltage , you must use Amper as a unit.So there is a conversion between milliampere to Ampere then 30mA makes 0.03 Ampere.Actually they are the same value.
Hi, when a current enters the resistor does it decrease the amount of electrons and we get
less electrons comes out of resistor (at the other end) OR it (resistor) decreases the speed
of electrons and we get slower electrons coming out from the other end of the resistor?
Also when we say that 2A is going through resister R , does that mean before entering the resister or after the resister?
Please help
I'm glad you explained how resistance affects the "LID" ;)
6:08 If the third band is grey, then why did you highlight the green?
thank you so much! loved the example with the light - made me understand why its important to have a resistor
thanks for your video.
Lovely video content! Apologies for the intrusion, I would appreciate your thoughts. Have you considered - Qanayce Wiyulian Equalizer (Have a quick look on google can't remember the place now)? It is a good one off product for unveiling the technique to repair your electronic items without the hard work. Ive heard some interesting things about it and my work buddy after many years got excellent results with it.
Content 👍👍👍 watching from Indonesia 🇮🇩🔔✅
would you please tell me if you know that in the 6 minute and 9 seconds you; it seems make the grey band calculate with a green value .....if this is so then you may want to indicate a correction and give the video the high standard you have with the rest of it , for the sake of those who are less able to deal with errors in their self educating. I appreciate the hard work you all put into the priceless videos on youtube in this field. thanks john
This version of the essential resistor was designed and developed in 1959 by Chicago inventor, Otis Boykin.
Mr. Boykin would later become better known for his next invention, a control unit for the pacemaker, which used electrical impulses to stimulate the heart and create a steady heartbeat.
Nederlands accent herken je altijd!!!
Toch goed geprobeerd.
Ja, zeker weten dat meneer weerstand een nederlander is. Tenslotte sluit hij ook nog de LED verkeerd om aan.
Around 4:00, how does the wire become a resistor for the wirewound? Is it the material it is made of? Wrapping a wire around a piece of wood doesn't reduce current, does it?
That is how wire wound resistors work and wrapping a wire around a piece of wood like that would make a very crude and weak resistor
NeXTSTORMING but, it is the same principle, correct? Instead of wood, maybe porcelain?
***** the material of the core dosen't matter just what the wire is mad of
NeXTSTORMING so, why the color coded piece? Just to let you know its value?
***** that is practically the only reason or the coloured stripes
also if you were wondering how high wattage power resistors work, they are just thicker cable
Does it matter if you put the resistor on the other side of the LED (so it's hooked up to the black negative lead)?
Nope.
Mitch Sandoe
the f#@! you mean by nope?!!!! it is a Light Emitting DIODE!!! get your facts right! diodes only allow electric current one way!! yes IT DOES MATTER!
Anas Malas You're correct. If you're not trolling, than you've misunderstood the question. To clarify, the arrangement of the resistor and LED in series does not matter in series so long as you have the diode forward biased.
looks like i just made a fool out of myself.... shame on me...
i didnt even read that he was talking about the resistor!
Good summary of what a resistor is and the various types available.
2:51, Im new to this topic, and trying my best to understand but im a little confused at this point...... you say that the 9v batter will burn out the led, well instead of using a resistor why dont people use a different battery ? one with less voltage? I dont see the point of a resistor at all, , why cant we just use the correct battery?
I'm also new so I might be wrong but, what if you didn't have another battery? And it's better applied to more complex circuits where there is a constant source. Which means some components can't handle that much current so use a resistor to provide to those components. If you see what I mean.
We better use resistor than changing battery because high voltage batteries are more efficient than low ones, even if adding resistor within the circuit. Just my opinion.
And should u dont get why high voltage batteries are more efficient than low ones, because P=V.I. The higher the current I, the higher the power loss due to conductor and thermal losses. So they have to make higher voltage batteries than components requirements to maximize efficiency
That was actually a very bad example use of a resistor; I was cringing as I watched it.
Changing voltage is often not a reasonable option, since LEDs are frequently just used as indicators in a larger circuit. If I'm working with a circuit that primarily uses an automobile supply voltage (~13.8VDC), I may not want to step-down the voltage just for some LEDs. A voltage regulator doesn't save any energy and a buck converter is unnecessary complexity.
LEDs have very low resistance, which is why you won't find them powered directly with a battery; however, they drop voltage. The voltage dropped across a diode is called the "diode drop." Red LEDs drop around 2V. If running maximum rated current, then you'll want to check the specifications for your LED. The diode drop occurs regardless of the potential (voltage) in that branch of your circuit. So, I'll use the example from this video. If you power the circuit with a 9V alkaline battery, you should expect supply voltages up to around 9.6V. Subtract the diode drop of the LED (9.6V - 2.0V = 7.6V), then calculate the resistor based upon the result (7.6V / .03A = 253.3 Ohms).
Neglecting the diode drop when calculating the resistance for a single LED on a 9V battery may result in a slightly dim lamp. But on a regulated 3.3V supply, you'd better calculate your LED's resistor after subtracting the diode drop, because a 330 Ohm resistor will NOT supply your LED with 10mA.
because they only have a 9 v batery that is better then with onlh 1.5 v!
like me, i Always use 9 v batery!!
This is amazing. I have a question though. why does a resistor have to be on the positive lead?
I understand that the assumption of the current direction ( from +ve to -ve ) was a mistake bcuz scientists when they were first working with electricity, they didn't know about the structure of an atom. Shouldn't we adopt the correct direction then to prevent the LED from burning out? which is from -ve to +ve?
(Thank you in advance for any help you might be able to provide)
Finally i got to know about the resistors thank you 🙏
ua-cam.com/video/TqWyt0Fz0V8/v-deo.htmlsi=g4C8f389oPLv2irO
Can you explain why you placed the resister at the positive lead, and not ground?
So does the resistor change its Ohms if connected to something else ? Like, using that same as in the LED example, with another 45mA LED, will that same resistor switch to 200 Om ?
Or is that value a constant depending on what ? The material that resistor is built with ?
Can that same transistor be used for some high voltage stuff like city electrical connections with 1.000.000 V ? If no why not ?
Yes, when you connect two or more resistors in series in a ckt, (i.e R1 & next to it, R2, R3), each resistor values (ohms) "R" are added, as to find Equivalent Resistance Requ= R1+2+R3, while calculating the current flow I=V/(R1+R2+R3)=V/Requ. The reason is , the voltage potential at the first resistor arriving at the resistor R1 is taken as Voltage for calculating current flow on each resistors in series. Hence, the current flows on all the resistors will be the same, but with drop in voltage.
No I don't think that is correct.
By ohm's law: V=(A)(R)
The higher the resistance, if the amperage stayed the same, voltage would also rise proportionally; obviously, that is NOT what happens, resistors do not add voltage.
If the voltage stays the same (given a potential differential = X from a given source like a battery) and if we change the value of the resistor, then what must change is the current to make the numbers add up:
V=10 R=10 , 100 , 1000 A=X
1. 10=(x)(10) A=1
2. 10=(x)(100) A=0.1
3. 10=(x)(1000) A=0.01
The higher the resistance = the LOWER THE CURRENT.
I got a little light-headed trying to absorb all that. Actually for a guy as dumb as me, it made good sense. I now have a basic understanding of what resistors are. Thanks.
2:45. R= 300. Does the resistor have to be exactly 300 or no less then 300?
Isn't the LED positive lead the long one? Might want to update your image.
Little criticism - The long leg of the LED is positive - therefore should be hooked up to the red line drawn from the battery - am I right?
hey, can you tell me what is keramic? I've never heard of that stuff
+Kahain he meant ceramic
Are you Harald Baldr?
Man thank you for clear my mind on this resistor presentation
at 6:19 green or grey?
what do you mean?
Can someone explain where he got the number 0.03 from on 2:33? It is confusing me D:
I just started learning, but here I get confused - Which way do the electrons flow in a battery? my previous reads "negative to positive" but here he connects resistor in positive side. Pls clarify me..
In physics, for stupid reasons, you have conventional flow, which is the flow of positive charges towards a negative charge, and electron flow, which is negative to positive.
When talking about current, you say that it moves from positive to negative. When talking about electrons, you say negative to positive.
HugThePolice cool explanation thanks
whats up with that colored code resistor ? does that thing actually physically change colors with different voltages applied to it ?
thanx for the information but can any one say that in the video it was shown that by connecting the resistor in series with bulb the current was controlled but in case of theory we use to say that for series connection of resistors the current flowing is same at all the resisters connected in series what does it mean?
So resistor lowers the current and the voltage or only current??
Thank you, this video made some things very clear!
Well done!
np
Thank you for this video, i gained lot of information about resistors which I could also share to my students
Question: I have a Bose speaker system in my car and all the speakers are 2 ohm. What resistor can I use to take a 4 ohm speaker and make it 2 ohm?
I enjoyed your video. It was very helpful. Thank you!
Hi there
Awesome video! The LED example made me understand it better. Thanks a lot
Hello my resistor has burnt out but it look's like it is 1 brown and 3 black, can you please tell me what the resistor strength is, or even if you can get that configuration. Thanks and hope you can help. I've asked 4 other people but they haven't answered. Please help.
Great vid, thanks for sharing. Do you know where I can find an electrical board hr51a? It is used for charging an 18v. There is only 4 parts on this board, 3 are resisters I don't know what the other part s is. It is a cylinder shape thing with 3 loops around it . Two brown and one black. Thanks
sounds like an inductor
I dunno anything about electric connection but is the batter +ve connecting with led - ve ??
can i put the resistor on the negative side of the battery?
I have the same question! please anyone explain why he put the resistor in the positive side? I believe that the current will move from the negative to the positive, so it will pass the light from the positive one. Thus, we need to limit the current flow before gets in the light to avoid blowing out! im just confused now!! please explain, Thx
Ahmed AlGazi an electrical current goes from positive to negative so it will first reach the risistor and then reach the LED. As they will say in Holland: Nothing on the hand.
I'm sure you could. Conventional current flow as used in diagrams and designs show the electrical path going from positive to negative, but electrons in a circuit actually flow from neg to pos, while the hole flow is from pos to neg..
thebuzzcjc wut?
When we draw a circuit, we usually assume that current (an amount of electrons) flows from positive to negative. They actually flow from negative to positive. This was discovered a long time ago but we still use + to - in diagrams for convention.
www.mi.mun.ca/users/cchaulk/eltk1100/ivse/ivse.htm
Sir really good .Very clear voice easy to understand. Thanks
Everything Perfect except the green color band was actually grey and the green should have been 100K not 10 K . Thank you for this video. It helped a lot.
do resistors have polarity (positive or negative)?? or can we use them in the circuit anyways... thanks
You may only use resistors if they have been preapproved by the Federal Resistor Polarity Commission for handling either positive charge (protons) or negative charge (electrons) else your circuit will either start generating antielectrons or antiprotons (depending, obviously, on the type of resistor you are attempting to abuse) and explode or it will suddenly vanish into the 8th dimension. Never ever forget: Knowledge is Power in today's increasingly technological world.
Ok, so I know this might be a noob question, but what do I put I front of an LED if I want a short delay after I switch the circuit on? If you want to know why I'm asking, it's because I'm soldering some LEDs to my xbox controller and I want to have a delay for each of them when the rumble activates. I am using 6 LEDs, 3 on each side of the clear front trim (what I mean is after 1 second 1 led lights then after 2 seconds 2 LEDs light and after 3 secs all 3 (on each side) light up). It would be amazing for a reply. Thanks!
you would need a microprocessor! those tall black ones i mean
ድንቅ ነው።
ተባረክልኝ።
Can we also say a step down transformer?
How did you determine the 0.03 for the Amperage?
0.03 A = 30 mA
thanks, very interactive and clear 👍
Thanks For your information. This Information will help me
l have a doubt.........Is there is any voltage drop between the terminals of resistor???
Well, since that us their primary job, I would say no, but given the tolerance of the resistor you using some might drop a little bit more than others inside their specified tolerance.
Thank you. I was able to understand the explaination easily. Good Video!
thanks
The analogy with water flow was incorrect. Making the tube more narrow will not reduce the current, but speed it up in that area. And the current will return back to what it was when the diameter of the tube returns back to its original value. Also, the pressure on the left is the same as on the right. It's the pressure in the middle that is reduced. You would be better off using a water wheel to represent the resistor. Somebody please correct me if I'm wrong.
Go to the hardware store. Buy two feet of PVC pipe with a 4 inch diameter, and two end caps. Drill a 3 inch hole in one of the end caps, and an eighth-inch hole in the other. Put the cap with the 3 inch hole on the pipe. Orient the pipe perpendicular to the ground, cover the hole, and fill the pipe with water. Use a clock, and record the amount of time it takes for the pipe to drain. Repeat with the 1/8" inch cap. Voltage in this case is supplied by the earth's mass. Gravity acts on all of the water at the same time and "wants" it to get through that pipe. The voltage therefore never changes, but the flow will. If you do this experiment, you will see that decreasing the size of the hole increases resistance of flow, resulting in less volume exiting the pipe in a given second. All a water pressure regulator does is change the size of a hole (or diaphragm) based on some input. The flow of water is a great analogy when it comes to explaining the relationship between voltage, current, and resistance.
vegasbryan I hear what you’re saying, and you’re not exactly wrong, but your example isn’t analogous to the situation at hand. Filling pipes with water and letting it fall out of holes of different diameters doesn’t include a constant mass flow rate as an example with connected pipes does.
The amount of water going into a section of a pipe is the same as the amount of water coming out. Therefore if the section’s diameter were reduced, the water would have to flow faster (increased current) in order to keep a consistent mass flow rate. Even with a consistent push (voltage). Think of it like this. If you put a nozzle on a water hose, the water coming out will be moving faster than the water moving through the hose because it has to keep a constant mass flow rate with decreased volume. This isn’t the case with a circuit, which is why using a smaller diameter valve to represent a resistor isn’t accurate. A resistor is supposed to slow the current, not speed it up. This is why most lessons will use a water wheel to represent a resistor when using water flow to represent a circuit. A water wheel causes resistance, slowing the current and transferring the kinetic energy of the water to rotational kinetic energy of the wheel. In the same way, a resistor slows current and creates heat.
Ashon Randall could you please suggest me a resource on Basic Fundamental Electronics ?
I need to understand inside-out of these...
PLEASE
vegasbryan
Wouldn't it be better though to say that in the case of a resistor, if we're talking about an analogy to electrical flow...that it would be the equivalent of making very small precise holes. Resistance is basically the amount of the electricity flowing through a conductor that's lost to heat, right? So it can't do useful work...Wouldn't that be equivalent in springing leaks in the pipe so simply not as much water reaches the destination (load)?
A resistor limits current in an electric circuit much like a partially closed valve limits mass flow in a hydraulic system. A redistribution of pressure occurs and more pressure drops across the valve to sustain a lower mass flow rate. When this occurs less pressure is available across the existing hose or pipe to maintain the previous water flow.
A similar thing happens in an electric circuit, most of the voltage drops across the resistor (partially closed valve) to maintain a now lower electrical current. Less voltage is then available across the existing conductors to maintain the previous electron flow (current). Electrons actually do move faster in the resistor then they do in the conductor material since the resistance in the conductors is so low that they act like huge diameter pipes. The increased electron velocity creates a large transfer of energy into the resistor in the form of thermal energy (heat) and the resistor gets warmer in the process.
You are right that the mass flow in a hydraulic system is the same everywhere in the system whether the water is moving quickly in a small diameter pipe or slowly in a large diameter pipe but fact remains that the mass flow rate is changed by a restriction in the system. A new, lower, mass flow rate is created by a restriction and the restriction requires a redistribution of system pressure to maintain the new lower mass flow rate.
thank you so much, now i am pro because i learn lots of thing from your video
can i use this video for our blog?
can you give me the color code of 32 ohms? please help...
+hotnewsread .com orange, red, black. 32x1 = 32.
When did 1000 change from m to k?
How can I reduce the current while reducing the wattage of the complete circuit also?
Hi, I think u should correct formula at about 2:31 because it's approximative, assuming battery voltage 9 V and Led Voltage about 2 V ("standard" led, not for bright led types), we have Vbatt=Vresistor+VLed so 9=Vresistor+2 then Vresistor=9-2=7V. So we got R=V/I so R=7/0.03=233.3 Ohm. It's Different to 300 ohm, your formula is not correct, so if u use it and different voltages u could damage the led. U must consider right Voltage Drops...
I love your website.! Very helpful. Thanks
1:00 Doesn't Pascal's law tell us that The pressure in a closed hydraulic system is the same at all points? P1=P2?
oh
Bubble Coffee Well all circuits are closed, so all of these hydraulic demonstrations have to be closed.
No. I think you are confusing HydroStatics with HydroDynamics. Bernoulli's principle must be applied for incompressible flow through a pipe. Pressure and Velocity will change as a function of the diameter of the pipe. When the diameter diminishes, pressure goes down and velocity goes up. It is an energy conservation law.
He used a bad analogy. The better analogy for potential(V), current(i) and Resistance(R) (Ohms Law: V=iR) is the vertical water pipe with gravity acting as the potential. The diameter of the pipe is the analog for resistance.
My girlfriend is a resistor ;-(
wa bro
i can't stop
Alcohol's conductivity reduces resistance!
Ha ha lol
This was great, been searching for "what is a resistor pack?" for a while now, and I think this has helped. Ever heard of - Henucas Panrooklyn Equalizer - (should be on google have a look )?
It is a smashing one off guide for discovering how to repair electronic devices like a pro without the headache. Ive heard some interesting things about it and my mate got great success with it.
My ex
does a resister reduce 240 volts to 115 volts
+amer limbu that's a step-down transformer's job
BUT WHY BY RESISTER?
resistor is for limiting current flow not voltage
Oh
+Arman Kordi You CAN use a pair resistors to reduce a voltage, it's called a voltage divider; however, it's only meant for low currents, typically to create a voltage reference for other components. A potentiometer is in fact a variable voltage divider.
Excellent video. I learned a lot. I am 67.
Thanks, from now I start to learn electronic
helo,,, can i ask some question,, how can i control the dynamo speed,,, i mean i need to turn it to slow, is it using the adjustable resistor(variable)?? tq
Hi! I have a question. Why don't they simply write the numbers instead of using colours?
I answer to your 2nd query first, Ampmeter is connected series to resistor for measuring the current being passed by resistor.When we say 2A is going through,i.e I=V/R, it's current Amp value = voltage drop (Vs-Vf)/Ohms measurement.Vs=voltage source(may be 9v or 12v),Vf=forward voltage (the volume going to be allowed to consume by device/simply say device rating voltage).This 2A current is allowed by the resistor.Now, for your 1st query, resistor is not controlling the speed of electrons.
Theres something wrong in this video but we can adjust for simple error ...make sure to be more strict in posting video to help more newbies but u explain well about the topic sir god bless and more power...
Wonderful. Great lesson for beginners.
yeah
where did you get the 0.03?
30 Ma (Light Bulb)
=
.03 Volts/Ohms
Since we are working with volts, lets work with amps and not milliamps. 1 A = 1000 MilliAmps. So 30milli amps/1000 = 0.03 A
+Cedric Mania superb
My receiver only stays on for 15 minutes then it will just turn off automatically m. What capacitor would it most likely be, please? Or is it something else?
Thank you so much over a year I am trying to understand this but, you did it to get me understand; by diagram examples with water pipe. | once again thanks___
what is the resistor inside the appliances
Why doesn't the resistor burn up or atleast get hot?
It does. But when the resistors limits are exceeded
is gray band is color green?
so what if that 9v battery was 3v, how would I determine the current then? wouldn't I need the resistance of the led itself?
I'm confused because everyone puts a resistor on their 3mm LEDs in xbox controllers. BUT it's 3v from the controller, which is what the LED's are rated for. So what's the point of the resistor?
FroztiProductions if the leds are rated for 3v what is there rated current rate? How many milliamps can they handle is what you need to know if it's any voltage could be 3v, 9v 12v you still need the resistor for a led as they are generally rated at 30ma like in this video and the resistors stop to much current going onto the led and burning it out, basicially like if it was a water pipe it stops to much water going Into the led and flooding it.
Well if they are rated for 3v I assumed the current rating would be calculated by that voltage the the internal resistance of the LED itself . I'll double check.
How can I be sure about the voltage drop, use multimeter to test voltage before and after LED?
FroztiProductions - use a potentiometer ("pot") in series with the LED and battery, and adjust the pot until it glows just enough for you. Then use your multimeter to measure the resistance of the pot, and substitute it with a fixed resistor. Just be careful not to turn the pot too far down or you will burn out your LED. Oops!
Positive leg of LED is longer, you have battery reversed.
+Michael Esping Almost always positive leg of LED is longer.
+Michael Esping Does the resistor always have to be on the positive side?
+jedi22300 The resistor can be connected either on the positive side or on the negative side
حنا بطرس Okay thank you
This was the fastest responce any one can have
if current flow in series, does not it the value will remain same? but how the resistor can reduce the current value in series? anyone can help me
thanks this was help full for my casp report
Great lesson ❤
isn't 2.6 mega ohms 2.6 million ohms, which would be true if the multiplcation band was blue? or am I completely missing something?
LID? Don't you mean LED?
+CoolAsFinnBro No. I'm pretty sure emitting starts with the letter I. Still. It's a good video and it's free. Why not enjoy?
+CoolAsFinnBro There is nothing called LID. LED is Light Emittimg Diode. Lead means wire
+Sss Ttt I know, he says lid in the video
CoolAsFinnBro Ok cool.
+Sss Ttt You're a bitch lol
These all resistance value colors below:
Value. Color. Multiplier (x10) Tolerance
0. Black 0
1. Brown 1 1 %
2. Red 2 2%
3. Orange 3
4. Yellow 4
5. Green 5 0.5%
6. Blue 6 0.25%
7. Purple/Violet 7 0.1%
8. Grey 8 0.05%
9. White 9
10. Gold -1 5%
11. Silver -2 10%
12. No color --- 20%
For example of 4 band or 5 band color of a resistor:
For 4 band color:
10 Ω with tolerance is 5%
(brown - black - black - gold)
47 Ω with tolerance is 5%
(yellow - purple/violet - black - gold)
560 Ω with tolerance 5%
(green - blue - brown - gold)
5.100 Ω (5,1k/5K1Ω) with tolerance is 5%
(green - brown - red - gold)
15.000 Ω (15kΩ) with tolerance is 5%
(brown - green - orange - gold)
270.000 Ω (270kΩ) with tolerance is 5%
(red - purple/violet - yellow - gold)
2.000.000 Ω (2MΩ) with tolerance is 5%
(red - black - green -gold)
12.000.000 Ω (12MΩ) with tolerance is 5%
(brown - red - blue - gold)
240.000.000 Ω (240MΩ) with tolerance is 5%
(red - yellow - purple/violet - gold)
1.000.000.000 Ω (1GΩ) with tolerance is 5%
(brown - black - grey - gold)
47.000.000.000 Ω (47GΩ) with tolerance is 5%
(yellow - purple/violet - white - gold)
For 5 band color:
47 Ω with tolerance is 1%
(yellow - purple/violet - black - silver - brown)
390 Ω with tolerance is 2%
(oramge - white - black - black - red)
2.200 Ω (2,2k/2K2Ω) with tolerance is 1%
(red - red - black - brown - brown)
51.000 Ω (51kΩ) with tolerance is 1%
(green - brown - black - red - brown)
470.000 Ω (470kΩ) with tolerance 2%
(yellow - purple/violet - black - orange - red)
1.500.000 Ω (1,5MΩ) with tolerance is 2%
(brown - green - black - yellow - red)
15.000.000 Ω (15MΩ) with tolerance is 1%
(brown - green - black - green - brown)
470.000.000 Ω (470MΩ) with tolerance is 1%
(yellow - purple/violet - black - blue - brown)
1.500.000.000 Ω (1,5GΩ) with tolerance is 2%
(brown - green - black - purple/violet - red)
56.000.000.000 Ω (56GΩ) with tolerance is 1%
(green - blue - black - grey - brown)
470.000.000.000 Ω (470GΩ) with tolerance is 2%
(yellow - purple/violet - black - white - red)
You have made my life easier
Thank you. That was brilliant - explained simply and clearly. Always thought resistors looked like Liquorice Allsorts. :)
Thank you very much that was very grateful short video basic knowledge