I thought you were going to say "Normally youtube videos don't help me...AND THIS ONE DIDN'T EITHER" 😆 I'm so glad to hear that it helped though! And you're very welcome 😁
thank you so much for this it was soooo helpful. quick question though, how would I graph a piecewise function if it never touches the y axis and moves in a diagonal line upward? how would I find my b?
That's a great question! It kind of depends on the limits though. Do you mind sharing your exact problem? What functions are you graphing and what are their limits?
@sunoo1446 oh I see! So let's clear a couple things up. First, y=-x-4 does touch the y-axis, specifically at -4. To graph linear functions you can either use an x/y table or use the Slope-intercept formula which is y=mx+b where: m= Slope b = y-intercept So here, m = -1 And b = -4 You can draw a straight line at a slope of -1 that runs through the point y=-4 The 2nd thing we need to clear up is that the function is only valid when X < 3 So the function is only valid where x-values are SMALLER than 3. U can draw a vertical "limit" line at x=3 (since that's the limit); Everything to the left of that line will be valid, and everything to the right would be invalid. I hope that makes sense but let me know if you still have questions 👍
great video! it really helped me understand a little more, but i still need help with a problem. so i have a trapezoid shape on my graph, where it starts from -2 on the x-int, (y=2x+4), goes over to 4, then from (2, 4), it goes down to 4 x-int, with an open circle. and it shows that line to be -2x+8. HELP😔
@@Eat_Pi thats the thing! there is none😭😭 theres only an open circle at the end of the line, and no other circles anywhere else. ive been watching a bunch of other videos though, and they all seem to seperate the lines with closed circles from the beginning of the line and opened circles at the end of it, is that how it always is??
@@grabacolgates Oh I see! Yes generally there's an open circle on one end and a closed circle on the other end. They're basically used to show where 1 function ends and the next one begins. But we can probably assume that those circles would be at the corners of your trapezoid, since those are the spots that each line/slope changes. It'll be kind of difficult to write everything out here so I'm going to make a video on it tomorrow!
Thanks again for the question! Here's a link to the video on how to solve this exact problem: ua-cam.com/video/h0AQZUWERdc/v-deo.html Let me know if you still have any questions! 👍
Graph the 2 points and connect them with a straight line. Then you should have one or two more lines that you have to graph, but none of them should intersect 👍
IDK WHO YOU ARE BUT I LOVE YOU!!!!!!!!
@@Edie_Johnson610 IDK WHO YOU ARE EITHER BUT I FEEL INCREIDBLY STRONG ABOUT YOU AS WELL!!!!!!!!!
Normally youtube videos don't help me...but this one actually did. Thank you! :)
I thought you were going to say
"Normally youtube videos don't help me...AND THIS ONE DIDN'T EITHER"
😆
I'm so glad to hear that it helped though! And you're very welcome 😁
thank you so much for this it was soooo helpful. quick question though, how would I graph a piecewise function if it never touches the y axis and moves in a diagonal line upward? how would I find my b?
That's a great question! It kind of depends on the limits though. Do you mind sharing your exact problem? What functions are you graphing and what are their limits?
@@Eat_Piyeah! so i figured the function is -x-4 if x
@sunoo1446 oh I see! So let's clear a couple things up. First, y=-x-4 does touch the y-axis, specifically at -4.
To graph linear functions you can either use an x/y table or use the Slope-intercept formula which is y=mx+b where:
m= Slope
b = y-intercept
So here, m = -1
And b = -4
You can draw a straight line at a slope of -1 that runs through the point y=-4
The 2nd thing we need to clear up is that the function is only valid when
X < 3
So the function is only valid where x-values are SMALLER than 3.
U can draw a vertical "limit" line at x=3 (since that's the limit);
Everything to the left of that line will be valid, and everything to the right would be invalid.
I hope that makes sense but let me know if you still have questions 👍
@@Eat_Pithank u so much! sorry for the late reply but i really appreciate it
@@sunoo1446 You're welcome! I'm always happy to help 👍
thank you so muchhh u explained this better than my teacher!
LOL you're welcome, I'm glad it makes sense now! :D
thank you so much, i’m doing school online and none of my practice problems covered this! such a life saver
@ina.rl.s You're very welcome! I'm glad it was helpful :D
Nice video, it helped me understand this easier.
That's great to hear! I'm glad it makes sense now :D
Honestly so much help, thanks so much. 🎉🎉🎉🎉
That's so great to hear! And you're welcome :D
this vid saved me thank you 🙏🏼
I care for all of God's creatures, including you friggin geniuses 😎🙏
Thank you! ✨🍀
You're welcome, I'm always happy to help! 👍
Jesus loves you
thank you so so so so so much 🙏
You're so so so so so welcome 🙏😄
Great video thank you!
You're welcome, I'm glad I could help! 😃
I understood this better than the graphing
That's great to hear I'm glad it made sense!
great video! it really helped me understand a little more, but i still need help with a problem. so i have a trapezoid shape on my graph, where it starts from -2 on the x-int, (y=2x+4), goes over to 4, then from (2, 4), it goes down to 4 x-int, with an open circle. and it shows that line to be -2x+8. HELP😔
Thanks for the question! Could you please tell me where else you have open and closed circles? That part is important when writing the inequalities.
@@Eat_Pi thats the thing! there is none😭😭 theres only an open circle at the end of the line, and no other circles anywhere else. ive been watching a bunch of other videos though, and they all seem to seperate the lines with closed circles from the beginning of the line and opened circles at the end of it, is that how it always is??
@@grabacolgates Oh I see! Yes generally there's an open circle on one end and a closed circle on the other end. They're basically used to show where 1 function ends and the next one begins. But we can probably assume that those circles would be at the corners of your trapezoid, since those are the spots that each line/slope changes.
It'll be kind of difficult to write everything out here so I'm going to make a video on it tomorrow!
Thanks again for the question! Here's a link to the video on how to solve this exact problem: ua-cam.com/video/h0AQZUWERdc/v-deo.html
Let me know if you still have any questions! 👍
@@Eat_Pi thank you so much for your replies and help!
Thank you😄
You're welcome 😊
Thanks 😊
Anytime, happy I could help 😀
One of my lines ona piecewise graph has two points (1,6.5) closed circle, and (3,5.5), what do i do?
Graph the 2 points and connect them with a straight line. Then you should have one or two more lines that you have to graph, but none of them should intersect 👍
❤
💙💙
Thank you
You're welcome!
but now I have equations that aren't linear. what now?!?!
What type of equations do you have?
y=-1/2 + 4
Thank you so much! This was really helpful. :) 🥹
You're welcome! I'm so glad to hear that :D