Відео

I'm glad I was able to help out! And I'm glad you passed that test like a friggin genius 😎

Thanks that means a lot to hear! And I'm glad you're finding the content helpful 👍

Lol that happens sometimes but I'm glad it makes sense now! 🙏

lmao I'm so glad to hear that! 🧡🧡🧡🧡🧡

@Cocoinsane-w3l youre welcome, all I want to do is save math lives 🙏

Ok I see! Do you have any specific problems in mind that you'd like to see solved?

Yes when one side of the equal sign/ inequality doesn’t contain a fraction but the other does while the side that has the fraction also has an absolute value equation . And the side that doesn’t have a fraction also doesn’t have a parentheses around both terms

Also when there’s a numeral on the outside of the absolute value on one side of the problem alongside say x+4 within that absolute value bracket and on that same side there’s an accompanying coefficient with a variable outside the absolute value brackets . And on the opposite side of the equal sign there are two terms and an operator within parentheses.

@@Ebonixyon lol sorry I should've been more clear - I assume you're working on homework so could you just tell me what your exact homework problem is so I can show you how to solve it?

@ lol ooo I’m really just prepping for mac1105 but I’m reviewing basics first. One of them is 1/2 |3c+5|= 6c+4. Which I solved after I watched a few different videos and the other was 4|3x+4|= 4x+8. But a few different examples of this kind would do me justice.

You're very welcome - Happy to help! 😀

@@Eat_Piyour an good teacher✨!

Happy to help! 😀

All I want to do is save math lives 🙏

@ I GOT AN A ON MY TEST

@@ramwashere1985 IM SO PROUD OF U, U FRIGGIN GENIUS!! 😃

Thank you, I appreciate that! 😎

lol it's a tricky subject but I'm glad the video was helpful and that you were able to figure it out! 💪

👋

You're welcome! And that means a lot to hear, I'm so glad it was helpful! I'm always happy to help 🧡

@@Eat_Pi i hope i will get a good grade... But without ur tutorial i would have failed 100% ❤️❤️

Hi thanks for the question! I have a video on solving linear inequalities with fractions that you can watch here: ua-cam.com/video/S761rWXWCoU/v-deo.htmlsi=Eq3Fv-24MO88x5Td If it's not what you're looking for then let me know what problem you'd like me to solve in a new video 👍

@@Eat_Pi Thank you so much!

@Ebonixyon you're welcome! Always happy to help :D

Sure! Just let me know what the problem is and I can make a video for it 👍

Good question! I assume you're talking about the slope? Yes, you could use either: -2 over 1 or 2 over -1 Both are equal to -2, so yes -2 over 1 works perfect 👍

That's awesome to hear! I'm glad it was helpful 😀

Goodluck on your finals - crush them like a friggin genius 😎

@Eat_Pi YESS I GOT A FULL MARK

@AhmedyaaaaAlowais That's incredible to hear, I'm so proud of you!!! :D

Good question! You only add exponents when you're multiplying 2 terms and the bases are the same. Here, the bases were never the same: we had a 2 and 3. So that's why we would never add the exponents in this case 👍

Thanks! I'm so glad it was helpful 💪

You're welcome, I'm so glad they were helpful 🙏

You're welcome!

That's awesome to hear, I'm always happy to help! :D

You're welcome! Hope you crushed that exam like a friggin genius 😎

@@Eat_PiYep got a perfect score 😎

Great question! I assume you'd have to be given what f(x) is equal to and then plug in your x-ints, leaving "a" as the only unknown. But if you tell me your specific problem I could probably help you more easily 👍

I'm so glad to hear that, you're welcome! 🙏

Thank you for the feedback, thats a great point! If you check the pinned comment at the top of the comment section, you'll see someone asked me the same thing a few years ago and I answered it there. If I make another video on this topic, I'll be sure to include it in the video as well! 👍

lmao thank you, that's really nice of you! 😆

I'm so glad the video helped, you're definitely not getting the belt now! 😁

lmao procrastination is the best until its due day! Also the it kind of depends on your specific problem, but the equation doesn't necessarily have to run through the y-int. You would just have to make sure you show the limits of the equation in the inequality that you write next to it in the set.

@@Eat_Pi Alright thanks man. You might have very well just saved my grades

@TeamHusky I hope so! My goal is to save all your math asses.. masses if you will 🙏 Goodluck with your hw! 👍

You're welcome! I'm happy to hear you're ready, now go crush that exam like a friggin genius 😎

lmao you're not entirely wrong about that 😅

@@kaverigupta4823 so happy to hear that! 😃

@@Joshith-o8i Absolutely, always happy to help 🙏

@@user-wk3yt3un4v That's awesome to hear, I'm always happy to help! 😃

@@PEEINK I appreciate that 🙏

@@taniamitra6247 That's wonderful to hear, and you're welcome! 😁

@AndrewDeGuzman-g8m That's really nice of you to say, thank you! I love to help as many people as possible with these topics, so I'm glad you're finding them helpful 🙏😃

@marguuh9443 Hi thanks for the question! Sure, do you have a problem in mind?

Yeah these problems can get a little messy just because there's a lot to keep to track of! So lets use equations 2 and 3 to eliminate y. 2x - 3y + 5z = -7 6x - y +4z = -3 Remember, to eliminate a variable from both equations, they have to have the same number and opposite signs. The y terms we have are -3y and -y To match the -y to -3y, we need to multiply the -y by 3. However, they need to have opposite signs. How do you turn a negative number into a positive one? By multiplying by another negative number. negative times a negative = positive. So lets not multiply by 3, but rather -3. Also remember that we have to multiply the whole equation by -3, not just the y term: -3(6x - y +4z = -3) -18x + 3y - 12z = 9 So now the 2 equations we have are: 2x - 3y + 5z = -7 -18x + 3y - 12z = 9 Adding them together we get: -16x + 0y -7z = 2 -16x -7z = 2 👍