Statics: Lesson 18 - 2D Statics on a Particle, Multiple Free Body Diagrams

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  • Опубліковано 1 лют 2025

КОМЕНТАРІ • 56

  • @ninjacoolbeans3
    @ninjacoolbeans3 4 роки тому +60

    why is this 10x more usful than any of my profs, this man alone is gonna save my statics grade

    • @harveyabordo4491
      @harveyabordo4491 4 роки тому +1

      same.

    • @Peter_1986
      @Peter_1986 2 роки тому +11

      Teachers who upload their own video instructions to the public are typically the teachers who actually truly enjoy teaching, and those people are gonna do their best to truly help their viewers, since they genuinely enjoy it. You can notice this very clearly in teachers like Jeff Hanson, Professor Leonard and Michel Van Biezen.

    • @oximas-oe9vf
      @oximas-oe9vf 2 роки тому

      @@Peter_1986 agreed

    • @cerulity32k
      @cerulity32k 3 місяці тому

      @@Peter_1986 so true, tbh i want to upload educational videos on programming, math, or smth else because ik people who struggle with that and if i can help someone understand something they didnt before, that would be amazing

    • @waynethurman2144
      @waynethurman2144 2 місяці тому

      Because most profs are likely on an ego trip instead of being a servant!

  • @georgesadler7830
    @georgesadler7830 3 роки тому +1

    Professor Hanson, Thank you for a solid analysis of 2D Statics on a Particle in mechanics, Drawing different types of Free Body Diagrams is very helpful.

  • @randzobaloyi3706
    @randzobaloyi3706 3 роки тому +2

    Wooowwwww, you can really teach. Thank you so much. Everything looks clearer now. I have hope.

  • @williamwelmans8648
    @williamwelmans8648 4 дні тому

    A lovely lesson. Thank you! ❤

  • @MichaelMunozGomez-x2d
    @MichaelMunozGomez-x2d 5 днів тому

    thank you jeff you are the goat man

  • @willmcgregor7184
    @willmcgregor7184 Рік тому +1

    Thanks again. You explain things more fully than my instructor !

  • @joshuafranzosayta9274
    @joshuafranzosayta9274 4 роки тому +2

    Cheers! all the way from the Philippines! thank doc!

  • @randzobaloyi3706
    @randzobaloyi3706 3 роки тому +1

    This was a beautiful session. Wow. I am grateful. I have more understanding now.

  • @rondavidfesalbon4843
    @rondavidfesalbon4843 4 роки тому +3

    Thank you Dr. Hanson

  • @assa8248
    @assa8248 Рік тому

    Hi professor @jeff hanson why when we used slope tringles for T(DA) we didn't just considered this cable as 5 and went to calculate it with components?

  • @fredyguevara3304
    @fredyguevara3304 4 роки тому +2

    Good evening professor, thank you very kindly

  • @kibandesteven5117
    @kibandesteven5117 3 роки тому +2

    😁😁😁a very big thank you soo soo much ,all the way from Uganda . You are a wonderful teacher

  • @joeking3688
    @joeking3688 Рік тому +2

    How did TAB x-axis turn to 3/5? Which mathematical inference is that?

    • @ilya8132
      @ilya8132 11 місяців тому

      When looking for the x-component of T[AB], we see that the x-axis lines up with cosine. So, when referring to our special triangle that is assigned to T[AB], we see that cosine (adjacent over hypotenuse) gives raito 3/5.

  • @kingrenny
    @kingrenny 3 роки тому +1

    Incredible video once again!!

  • @chekopacheko9786
    @chekopacheko9786 3 роки тому +3

    Thank You Dr. Hanson, these videos have been very helpful. I do have a question though, where do we get those little triangles from.....you know triangle 3,4,5 sides and the other triangles? Like am I suppose to be able to tell which triangles they are?

    • @djilawdlevel
      @djilawdlevel 3 роки тому

      also wondering of this

    • @JimmyKha1
      @JimmyKha1 3 роки тому

      You can find them using the pythagorean theorem but the ones you’re talking about (3, 4, 5 or 5, 12, 13) are some of the common ones you’d find in problems (from what i’ve seen).

    • @firstlegend5105
      @firstlegend5105 2 роки тому

      You derive them from SOH CAH TOA method. This is one of the method that is simplified if you don't want to use the angles method. But don't worry, either way, you'll get the same answers, you can get used to this method with enough practice

    • @pr.dr.nachtigaller5154
      @pr.dr.nachtigaller5154 2 роки тому

      You can also just use them to get the angles you need to get the x and y formulae. They worked for me fine, I got the same results as him

  • @marcialm8496
    @marcialm8496 4 роки тому +2

    This helped a lot!

  • @ham5483
    @ham5483 3 роки тому +1

    9:30 i have ti30xs i dont think i have system solver, how do you find the tension of Tab and Tad without using the calculator?

    • @tommymazak7477
      @tommymazak7477 3 роки тому

      just isolate either Tab or Tad then plug it into the other equation that way the equation is in terms of one variable. Once u solve for that then plug that number into the equation to solve for the other variable.

  • @jonathanlorens2312
    @jonathanlorens2312 Рік тому

    How do you know whether to label, for example, TAD or TDA?? Does it make a difference?

    • @YoungMan-uu4ro
      @YoungMan-uu4ro Рік тому

      No it doesn’t matter that’s the same thing.

  • @westwest001
    @westwest001 2 роки тому

    Hello sir, In the free body diagram of point A why didn’t you negate 5/13 because in that quadrant the X component which is the 5 is negative. So something like -5/13(TAD). I’m just asking though???

  • @pariwarthanpatel1067
    @pariwarthanpatel1067 Рік тому

    T(AD) was in tension in second free body diagram but in third free body diagram in think the direction was opposite in reference to second fbd. Can we do that for all tension problems?

  • @mrzombiesbo
    @mrzombiesbo Рік тому

    Why is Tad not equal to Tab? Shouldn't tension be constant in the cable?

    • @YoungMan-uu4ro
      @YoungMan-uu4ro Рік тому

      TAB is a separate cable connected to the wall it can’t be constant.

  • @DethCompany
    @DethCompany Рік тому

    Why is the tension only 100 for the first FBD if the weight is 200?

  • @agnieszkasojka4379
    @agnieszkasojka4379 Рік тому

    I thought force on both side of pulley is the same like in the other examples. Maybe this is just weight not a pulley. I am sorry I am new to this. Any help, please?

  • @willmcgregor7184
    @willmcgregor7184 Рік тому

    Anyone found (from a reputable source) Solutions to Hibbeler's Static text?

  • @eduardosdelarosa5539
    @eduardosdelarosa5539 4 роки тому

    Thank you

  • @GhulamMustafa-gp2lp
    @GhulamMustafa-gp2lp 4 роки тому

    great

  • @Rio_KaWHK
    @Rio_KaWHK 3 роки тому

    I don't get how he gets the answers...how do u pluck in the digits; what does he mean by "Enter"...there's no "Enter" on my calci...

    • @sadpluto7410
      @sadpluto7410 3 роки тому +1

      There's a system solver in your calculator, you can find tutorials online on how to do it on the specific calculator that you are using. What he means by enter is the equal sign on the calculator. You press equal to move on to input another number. Hope this helps

  • @3zombie81
    @3zombie81 4 роки тому

    how do i use the system solver?

    • @zunaidhassan9662
      @zunaidhassan9662 4 роки тому +1

      How To: TI36x-Pro - Solving 2 Equations, 2 Unknowns: ua-cam.com/video/o9h4DMC7YpY/v-deo.html&ab_channel=JeffHanson

  • @MehmetSaidSeckin
    @MehmetSaidSeckin 2 роки тому

    We don't know that Tdc is parallel to the x axis, so the last free body diagram is wrong. "I think."

    • @Robbie-Robb
      @Robbie-Robb Рік тому

      He told us it was at the beginning of the video.

  • @gutierrezgutierrez5901
    @gutierrezgutierrez5901 4 роки тому +2

    should not be 5/13 instead of 12/13? sin=opp/hyp

    • @samuelrusch9189
      @samuelrusch9189 4 роки тому +3

      Idk if you were still wondering about this but the reason it is 5/13 for Tad is because the 5 side of the triangle lies in the X direction and the 12 side lies in the y direction (think of the triangle sides as ratios of the vector Tad in the X and Y direction).
      The negative sign on the 5/13 Tad comes from breaking up the vector Tad into its X and Y components (basically follow the x path and y path from the tail to the head of the vector to get the direction of the X and Y components). When this is done, you'll see the X component of vector Tad is parallel with the 5 side of the triangle. This should also help explain why we use 5/13 instead of 12/13.
      We see that the X component of that vector acts in the negative X direction, so the x component of the vector is -5/13 Tad. Hope that helps.

    • @gabrieldayot4921
      @gabrieldayot4921 4 роки тому

      it will depend based on where the angle is in the right triangle.

  • @victorcasillas8057
    @victorcasillas8057 3 роки тому

    can i get a negative answer. please hurry

    • @1234jhanson
      @1234jhanson  3 роки тому

      Yes, means you picked wrong direction on your free body diagram.

    • @victorcasillas8057
      @victorcasillas8057 3 роки тому

      @@1234jhanson Thank you.

  • @باب_الحارة_1
    @باب_الحارة_1 2 роки тому

    🤌🏼🍓

  • @Anuq
    @Anuq 4 роки тому

    I got T(ab) as 48lb , did anyone get that too ?

  • @oscart.grouch9061
    @oscart.grouch9061 2 роки тому +1

    Thank you

  • @mahdikmahamad1425
    @mahdikmahamad1425 Рік тому

    thank you