for those who dont know, system solver in a ti 84 or any graphic calc is just making a matrix in this case you make a 3x4 matrix, and hit in the numbers for your i,j, and k after that go to home screen 2nd matrix rref(the matrix you made) and enter
8:54 I spent twenty minutes on this problem, thinking I made a mistake. Your method was correct you just plugged in the wrong value into your calculator. -0.5/2.06 and not -0.5/2.006 The correct answers are: BA = 954 N CA = 858 N DA = 932 N
Hi professor, I’ve followed you since I took statics in 2015-16 but I am unsubscribing for a bit because you are taking up my feed with your re-uploads. I will re-subscribe after you have added your new intro but I will always thank you for being the best resource in engineering courses on UA-cam. Thank you so much Dr. Hanson
The z dimension is 2 metres (he forgot to write it down, he notices at 2:55 ). If you pause in the begging and try to solve it you will need that information.
Forgive me if I am wrong; however, if you are considering that the 2500N is in the positive Z direction, then shouldn't the coordinates of B be (-0.5, 1, 0)?
My calculations, based on your values, come up with Tab=963.140N, Tac=846.632N, Tad=937.400N Using excel matrix calculation. Retired EE auditing class for fun.
BTW I used EXACT numbers for the unit vectors in calculation (irrational numbers like root(17)/17) and when I solved the system my answers were each, on average, about 1% higher than what you got. How do you go about using sig figs, how about in the real world??
İf you look the shape it is written (.5) it means 0.5. It is already given. You just need to check one by one the coordinates to write. ( Thanks to you, I realised .5, I tried to calculate like 5)
for those who dont know, system solver in a ti 84 or any graphic calc is just making a matrix in this case you make a 3x4 matrix, and hit in the numbers for your i,j, and k after that go to home screen 2nd matrix rref(the matrix you made) and enter
GOAT
Appreciate fr
There's also an app called PlySmlt2 that you can download, I find it easier to use than a matrix
8:54 I spent twenty minutes on this problem, thinking I made a mistake. Your method was correct you just plugged in the wrong value into your calculator.
-0.5/2.06 and not -0.5/2.006
The correct answers are:
BA = 954 N
CA = 858 N
DA = 932 N
I also got confused there good thing others caught that as well.
here i am and got those exact values. good eye
Another reason to use variables until you want the answer
I thought I was going crazy lmaoo I just caught it and was checking to see if others did too
Good catch.
DR. Hanson, thank you for a positive introduction to 3D Statics About a Particle. These are difficult problems in 3D.
You are the best lecturer ever. God bless you sir 🙏🙏
Hi professor, I’ve followed you since I took statics in 2015-16 but I am unsubscribing for a bit because you are taking up my feed with your re-uploads. I will re-subscribe after you have added your new intro but I will always thank you for being the best resource in engineering courses on UA-cam. Thank you so much Dr. Hanson
Dr. Hanson, hour book has the x and y axes opposite the way you have it in your book on Page 65
The z dimension is 2 metres (he forgot to write it down, he notices at 2:55 ). If you pause in the begging and try to solve it you will need that information.
10min laytorr...
Good thing it made me realize it was not going to work
I just have a question; why cannot we take (x,y,z) in a regular way i.e the way we use in quadrant system which will make B(1,.5,0) , can you explain?
Forgive me if I am wrong; however, if you are considering that the 2500N is in the positive Z direction, then shouldn't the coordinates of B be (-0.5, 1, 0)?
This is correct I think. I had the same question.
@@josephh.1243 also ran into this issue
i think the Fz equation should have been -.873TAB-.9704TAC-.8964TAD=-2500N (neg 2500N).
i'm thinking we're noticing same thing. am i wrong?
Is this for the lambda ac coordinates? (C?) i ran into the same problem too
Pretty sure he divided everything by -1 so that all the signs would be positive@@tomferbend3323
thank you so much Dr. Hanson for your effort , you are such a great person ,thank you.
Around 2:37 it sounds like he's listening to the old video for the dimension :)
Thank you so so much, God bless your soul.
Its a sad day when you cant use your smart calc on the test. No system solver :(
My calculations, based on your values, come up with Tab=963.140N, Tac=846.632N, Tad=937.400N Using excel matrix calculation. Retired EE auditing class for fun.
BTW I used EXACT numbers for the unit vectors in calculation (irrational numbers like root(17)/17) and when I solved the system my answers were each, on average, about 1% higher than what you got. How do you go about using sig figs, how about in the real world??
God bless! What was the scripture at the end?
2:28 bro just left
Very Nice Lecture
I'm confused in lambda method particularly on how to get the coordinates of points.
You base it on the illustration of the problem
The way I think about it is that 2 cables are anchored in a flat surface (x and y) and the third one (z) is anchored somewhere up in a hill.
Can anyone tell me I'm not clear about point B why he got B(0.5,-1,0)?
İf you look the shape it is written (.5) it means 0.5. It is already given. You just need to check one by one the coordinates to write. ( Thanks to you, I realised .5, I tried to calculate like 5)
🙂
BEAT SOME OF YOUR WISDOM INTO JOHHNY WEEEEAAK SOUCE