Thanks for liking my comments. Main is channel se kuch mahino pehle half of ckt theory padha tha. Fir notes bhi gum ho gye thhe... Now i tried to watch concepts on different diff channels but in videos ko hi khojta tha..... coz yahan ka maal or kahi ni milne wala.... Even books se padh ke bas confirm hota hu.... Ur level is best... Plz recommend a book for gate for ckt theory
Solution of the examples have been uploaded. Although it is handwritten notes, but I think it will do the job. drive.google.com/file/d/0B3FOmN0FcD6ORlVUZzBlUnhNY00/view?usp=sharing&resourcekey=0-MRv5_nLdkC3sococcGqLFQ
Yes, but they are connected in series. It won't alter the KVL equation. e.g if you have 1v followed by 1ohm resistor, followed by 2V source. The current through 1 ohm resistor is 3A. It will remain the same if you move 2V voltage source just before the resistor and so does the voltage across the resistor. I hope it will clear your doubt.
its very helpful no doubt about it. but it could be better if you explain sign conventions also while sourse transformation like voltage to current sourse and vice-versa.
At the end of finding the resultant current I, why do you take the direction of current according to 2A current source but not 8/3A current source. (8/3A > 2A). Please answer as soon as possible. I need to clear this concept as fast as possible. Thank you for the video.
The only reason is we want to find the Vx with the given polarity. + at the top and - at the bottom. That means the equivalent current should pass through 3 ohm resistor from top to bottom. And that will happen when the current direction is upwards. I hope, it will clear your doubt.
The current I = -2/3 A. That means it is flowing from bottom to top. So, the bottom terminal will be positive, while the top terminal will be negative. Therefore, Vx is -2V. I hope it will clear your doubt.
In the 10th minute and 35 seconds you combine both the voltage sources which are in series ,you say in the video that the resultant voltage source is given by 8+8/3 , but it should be (8-8/3)volts as the polarity of the 8/3 voltage source is negative??
It will be 8+ (8/3). Please look at the example once again. The negative terminal of 8/3 V is in series with a positive terminal of 8V. So, the addition will be 8+(8/3) only. And still, if you have any doubt then do let me know.
If you see, 8/3 A current is going downwards, while the 2 A current is going upwards. That means the resultant current which is going upwards is 2 - (8/3) A. I hope it will clear your doubt.
If the two voltage sources are connected in the series and if the positive terminal of the one source is connected to the negative terminal of the other source then the voltages of the two sources will be added. i.e V= V1 + V2 similarly, if the positive terminal of the source is connected to the positive terminal of the other source, in the case the overall voltage will be the difference between the two sources. I hope it will help you.
If you closely observe once again both currents are flowing in opposite directions. 2A current is flowing in the upward direction, while 8/3 A current is flowing in the downward direction.
@@ALLABOUTELECTRONICS But Sir, both 8/3 and 2 are in same loop and flowing in same anticlockwise fashion...so what's the problem if we take 8/3-2 instead of 2-8/3?
If the current source is in the upward direction then the transformed voltage source will have positive polarity followed by negative polarity. In short in the transformed voltage source, the current which is flowing through it should be in the same direction as the current source. I hope it will clear your doubt.
hello! I'm just stuck on one problem, after I transform, I don't know where to put the resistors? do we usually just move it up (if it is from parallel)? does the way we move it matter based on the polarity of the source? since I have a problem where the resistor is on the left and the current source is on the right, while all the rest of the circuits is to the right, so after I transform this to series, the resistor will move up to be in series, even though my source is pointed down?
It depends on the polarity of the current source. If the current from the current source is flowing downwards, after the transformation voltage source will have polarity - to +. And the resistor will be connected to the negative terminal of the voltage source. Because, before transformation, the current is going away from the resistor. For better understanding, you can see that in the video at 9:20. So, after transformation, the same thing should be followed. I hope it will help you in clearing your doubt. If you still have any doubt then do let me know here.
If you see at 11:41, 8/3 A current is going downwards, while 2A current is going upwards. That means total (8/3)A - (2A) current is going downwards. Or in other words, 2/3 A current is going downwards. I hope it will clear your doubt.
I think you are talking about 8 and 8/3 Voltage source, right? If you actually see, they are not in the opposite direction. The negative terminal of 8/3 V voltage source is connected to the positive terminal of 8V voltage source. So, actually they will get added to each other.
If you see a 32/3 V voltage source, then there is a negative sign at the top and a positive sign at the bottom. Therefore after the source transformation, the current source is going downwards. If there is a positive sign at the top and a negative sign at the bottom in the voltage source, then after the source transformation, the direction of the current would have been upward. I hope, it will clear your doubt.
As they are connected in the series, so the addition of the two sources won't affect the rest of the circuit on the right side (12 ohm and 2A Source). The remaining circuit on the right side will still see the same voltage across the two terminals.
Although it appears that the polarity is different. But actually if you see, the negative of one source is connected to the positive of the second source. That means two sources are in series. Hence, the equivalent voltage will be the summation of two sources.
Yes, you can say so, if you take I as, (8/3)-2. And in that case current will be positive and will be from bottom to the top. But voltage Vx will remain negative. As, we are measuring voltage from top to the bottom. So, in short I would say, it's just matter of direction. If you assume current is flowing from top to bottom then it is negative and if you assume it is flowing from bottom to the top then its positive. I hope it will clear your doubt.
after adding voltage source 8+8/3 the resultant voltage source 32/3 terminal (- +) . why not plus minus(+-). if we check numerical also 8V is greater than 8/3 Volt. voltage source must be connected to 4 ohms must be positive terminal only why negative... can any one explain.
To understand it, just interchange the position of the 4-ohm resistor and 8V source. Just place the 8V source on the left side. You will observe that both 8V and 8/3 sources are in series and the total voltage would be (8 + 8/3) = 32/3 V with the negative terminal on top and positive at the bottom. I hope it will help you in visualizing it.
If you apply the KCL at the node, then you will see that Is is the entering current at the node, while I and Ix are leaving currents. According to KCL, the sum of leaving current and entering current is equal. That's why, Is= Ix +Iy. I hope, it will clear your doubt.
In case of an inductor, first of all, you need to find the impedance at the operating frequency. Then you can apply the source transformation and can treat the impedance like a resistance.
Just apply the KCL at the node above 3 ohm resistor. Current I and 8/3 A are leaaving the node, while 2A current is entering the node. That means I + (8/3) = 2 Or I = 2 - (8/3).
I'm having a MID EXAM in a 3 hrs. Thank you. :) :D
@Alvin Alaric what do you mean
@@mero0o0o02011 its a scam
@@JafakeinUnc thank you very much
What are you doing now mate
@Shreyas Singh I have graduated 🎓 and I just became a process engineer 😅💪. Thank you for bringing me back to the comment
Only channel with water like conceptual clarity. Thanks for being here
Thanks for liking my comments.
Main is channel se kuch mahino pehle half of ckt theory padha tha. Fir notes bhi gum ho gye thhe... Now i tried to watch concepts on different diff channels but in videos ko hi khojta tha..... coz yahan ka maal or kahi ni milne wala.... Even books se padh ke bas confirm hota hu.... Ur level is best... Plz recommend a book for gate for ckt theory
nothing but a good video
hahahaha
Nice
😁😁😁
HHahahahBahababahahahahahahahahahahaha
I think we should subtract both the voltages (8/3)v and 8v because the signs are opposite so it will subtract right this is my small doubt
Thankyou for once gain with new concept....learning video good work keep it up. .
Very informative video. Thanks for uploading
Solution of the examples have been uploaded. Although it is handwritten notes, but I think it will do the job.
drive.google.com/file/d/0B3FOmN0FcD6ORlVUZzBlUnhNY00/view?usp=sharing&resourcekey=0-MRv5_nLdkC3sococcGqLFQ
Thanks, you explain these topics ver well, thanks for taking the time to share your knowledge.
what is the rule used here to add the two voltage 32/3 , 4 v and to substract 2,8/3 A
You r doing gr8 work..hats off sir
Sir why did you add two voltages 8v and (8/3)v at 10:23 since it has a resistance of 4 ohm between them?
Yes, but they are connected in series. It won't alter the KVL equation. e.g if you have 1v followed by 1ohm resistor, followed by 2V source. The current through 1 ohm resistor is 3A. It will remain the same if you move 2V voltage source just before the resistor and so does the voltage across the resistor. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS sir, then why did you subtract volatages in example 1..96-6
You saved my assignment marks with this video.
its very helpful no doubt about it. but it could be better if you explain sign conventions also while sourse transformation like voltage to current sourse and vice-versa.
Its up to your knowledge
Thank you sir for your best explanation 👍💯
Amazing video. Thnx a lot. Your channel is awesome. Keep making more videos like that
explanation is good bro
Thank you sir for teaching me
At the end of finding the resultant current I, why do you take the direction of current according to 2A current source but not 8/3A current source. (8/3A > 2A). Please answer as soon as possible. I need to clear this concept as fast as possible. Thank you for the video.
The only reason is we want to find the Vx with the given polarity. + at the top and - at the bottom. That means the equivalent current should pass through 3 ohm resistor from top to bottom. And that will happen when the current direction is upwards. I hope, it will clear your doubt.
amazing, simple and easy bravo!
#you have done a excellent job bro
Nice video thank you sir
exam in 1 hour sir u saved my life
nice video about transformation😀
i believe ur Vx should be 2V as its the opp direction of (3 x (-2/3))
The current I = -2/3 A. That means it is flowing from bottom to top. So, the bottom terminal will be positive, while the top terminal will be negative. Therefore, Vx is -2V.
I hope it will clear your doubt.
Sir videos are great but pls make them short and simple so we can learn more in less time
That's y i played on 2x
VIDEO IS REALLY AWESOME!!!!! KEEP DOING SUCH KIND OF VIDEOS!!!!
Thanks a lot sir... The video was helpful 😊
Thanks for the explanation sir😊😊😊
Excellent explanation bro
great job sir... kindly make a video for duality principle of network analysis please...
thanku very much sir for this nice explaination
thank you boss , you are god
Thanku so much sir
In the 10th minute and 35 seconds you combine both the voltage sources which are in series ,you say in the video that the resultant voltage source is given by 8+8/3 , but it should be (8-8/3)volts as the polarity of the 8/3 voltage source is negative??
It will be 8+ (8/3). Please look at the example once again. The negative terminal of 8/3 V is in series with a positive terminal of 8V. So, the addition will be 8+(8/3) only.
And still, if you have any doubt then do let me know.
Thank you
Nice video...too clear..good explanation
Great Video. Thanks....
NICE EXPLANATION.
U r really great 🙏
awesome explanation
I didn't understand the last step about how you have written the value of I=2-(8/3)
If you see, 8/3 A current is going downwards, while the 2 A current is going upwards. That means the resultant current which is going upwards is 2 - (8/3) A.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS thanks
nice video.... very helpful
Hi
Nice explanation
Thnku for content
Superb
Description lo third problem answer 3volts. Is it correct?
nicely explained
Explain the sign convention for the addition of two voltage source..
If the two voltage sources are connected in the series and if the positive terminal of the one source is connected to the negative terminal of the other source then the voltages of the two sources will be added. i.e V= V1 + V2
similarly, if the positive terminal of the source is connected to the positive terminal of the other source, in the case the overall voltage will be the difference between the two sources.
I hope it will help you.
Great job bro❤
Hi Sir, I didn’t understand the last part. Why we negated 2-8/3 even though both currents are flowing in the same direction
If you closely observe once again both currents are flowing in opposite directions. 2A current is flowing in the upward direction, while 8/3 A current is flowing in the downward direction.
@@ALLABOUTELECTRONICS But Sir, both 8/3 and 2 are in same loop and flowing in same anticlockwise fashion...so what's the problem if we take 8/3-2 instead of 2-8/3?
thank you
SIR, why you subtracted the two currents
Super class
Good example 👍👍
Sir can you share this type of problems
very heplfull tutorial
Play on 2x
very clear explanation. Thank You :)
Why 4ohm is connected at the negative end of the 32|3 v and not with the positive one
Why do we take the resistance in parallel after transforming the source
Awesome👏👏👏
I have one doubt...what about the direction of current and voltage source after the transformation?
If the current source is in the upward direction then the transformed voltage source will have positive polarity followed by negative polarity. In short in the transformed voltage source, the current which is flowing through it should be in the same direction as the current source.
I hope it will clear your doubt.
How to transform series curent source and resistance into voltage
The source transformation is possible when there is a voltage source in series with resistor or a current source in parallel with some resistor.
amazing video sir 😎😎😎
hello! I'm just stuck on one problem, after I transform, I don't know where to put the resistors? do we usually just move it up (if it is from parallel)? does the way we move it matter based on the polarity of the source? since I have a problem where the resistor is on the left and the current source is on the right, while all the rest of the circuits is to the right, so after I transform this to series, the resistor will move up to be in series, even though my source is pointed down?
It depends on the polarity of the current source. If the current from the current source is flowing downwards, after the transformation voltage source will have polarity - to +. And the resistor will be connected to the negative terminal of the voltage source. Because, before transformation, the current is going away from the resistor. For better understanding, you can see that in the video at 9:20. So, after transformation, the same thing should be followed.
I hope it will help you in clearing your doubt.
If you still have any doubt then do let me know here.
Nice....
Why the direction of 2/3A current is taken downwards (pblm)
If you see at 11:41, 8/3 A current is going downwards, while 2A current is going upwards. That means total (8/3)A - (2A) current is going downwards.
Or in other words, 2/3 A current is going downwards.
I hope it will clear your doubt.
I have one doubt you subtract 2-8/3 in opposite direction in current but you do addition for opposite direction of voltage why?
I think you are talking about 8 and 8/3 Voltage source, right?
If you actually see, they are not in the opposite direction. The negative terminal of 8/3 V voltage source is connected to the positive terminal of 8V voltage source. So, actually they will get added to each other.
@@ALLABOUTELECTRONICS oh yes ok understand it thanks a lot please suggest me a book so that I can solve many problems from source transformation
nice video...informative..(y)
if we replace voltage source into current source why we put resistance in parallel to find the current?
In the first 4 minutes of the video, I have explained it. Please go through it again, you will get it.
Can we just add 2 voltage source in series?
Yes.
Sir what if value is positive
Thanku sir🤗🤗🤗🤗
Loveee u bro, soooo nicely explained 🫶🏻🫶🏻🫶🏻
Why we are taking 8/3A as negative??
In last step??
If you see a 32/3 V voltage source, then there is a negative sign at the top and a positive sign at the bottom. Therefore after the source transformation, the current source is going downwards. If there is a positive sign at the top and a negative sign at the bottom in the voltage source, then after the source transformation, the direction of the current would have been upward. I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS thanks for your reply sir🙏
But still now I am not clear why not 8/3-2
How can we add 2 voltage source there is a resistance between them ??
As they are connected in the series, so the addition of the two sources won't affect the rest of the circuit on the right side (12 ohm and 2A Source).
The remaining circuit on the right side will still see the same voltage across the two terminals.
Can we transfer voltage source parallel resistor to current source series resistor...??plz anyone answer
Sir the link for more solutions isn't opening. Could you repost the link. Thanks sir
It is opening now. Please check the link given in the description.
If you still find the difficulty then let me know here.
@@ALLABOUTELECTRONICS It is opening now sir. Thank you
10:28 Polarity of voltage sources are different can we add that simply🙄 anyone clear this doubt
Although it appears that the polarity is different. But actually if you see, the negative of one source is connected to the positive of the second source. That means two sources are in series. Hence, the equivalent voltage will be the summation of two sources.
i understood it all but in the last step i didn't understand why I=2-8/3 i mean we could say I=8/3-2 and then I would be positive ?!
Yes, you can say so, if you take I as, (8/3)-2. And in that case current will be positive and will be from bottom to the top. But voltage Vx will remain negative. As, we are measuring voltage from top to the bottom. So, in short I would say, it's just matter of direction. If you assume current is flowing from top to bottom then it is negative and if you assume it is flowing from bottom to the top then its positive.
I hope it will clear your doubt.
#you are cool SIR..!
after adding voltage source 8+8/3 the resultant voltage source 32/3 terminal (- +) . why not plus minus(+-). if we check numerical also 8V is greater than 8/3 Volt. voltage source must be connected to 4 ohms must be positive terminal only why negative... can any one explain.
To understand it, just interchange the position of the 4-ohm resistor and 8V source. Just place the 8V source on the left side. You will observe that both 8V and 8/3 sources are in series and the total voltage would be (8 + 8/3) = 32/3 V with the negative terminal on top and positive at the bottom.
I hope it will help you in visualizing it.
Tq
in which way they will ask in the EEE exam
tnx sir
Great u
Sir source configuration ki video ha?
i couldn t understand the Is=ix +Iy and how to add two current sources or two voltage source
If you apply the KCL at the node, then you will see that Is is the entering current at the node, while I and Ix are leaving currents. According to KCL, the sum of leaving current and entering current is equal. That's why, Is= Ix +Iy.
I hope, it will clear your doubt.
ALL ABOUT ELECTRONICS hogaya exam Or ye question. Nai bana
How to do soucre transformation when inductor is connected instead of resisitor
In case of an inductor, first of all, you need to find the impedance at the operating frequency. Then you can apply the source transformation and can treat the impedance like a resistance.
Nice video, but please avoid the replication of the word 'nothing but'
Also where can I get the solutions?
You can try it by yourself. If you find any difficulty then do let me know here.
The solution has been uploaded.
drive.google.com/open?id=0B3FOmN0FcD6ORlVUZzBlUnhNY00
Although it is handwritten notes, I think it will do the job.
Last step can't mind
Great!!!!
Bahi bata need source transformation
bro can u make videos under 10 mins. it feels slow and long.
7:40
🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗
12:50 why you subtract
Just apply the KCL at the node above 3 ohm resistor.
Current I and 8/3 A are leaaving the node, while 2A current is entering the node. That means I + (8/3) = 2
Or I = 2 - (8/3).
sir i want solution for this tutorial
Ok, I will also upload the solution very soon.
The solution has been uploaded.
drive.google.com/open?id=0B3FOmN0FcD6ORlVUZzBlUnhNY00
Although it is handwritten notes, I think it will do the job.
❤️
Does anyone know why I = Is - Ix?
Applying KCL at the node above resistor, you will get the equation.
Thanks! Your videos are very helpful by the way!
Bro give me ans. For pdf questions
I have already given that. Please check description or the pinned comment.