thank you so much!!!! I have been struggling with this fora whole and now i finally get it :) hopefully it all works out well in my chemistry gcse tomorrow !!
Video solutions do not provide an accurate working out. Instead: Step 1. Draw up 2 columns with two rows (first row=mole ratio (coefficient of molecule), second=number of moles) Example: Mg MgO 1 2 2.4686 (mol) x Step 2. Add an x (or any other variable) to fill in the mass you are trying to find (refer to above example) Step 3. Apply mole ratio (2.4686*2 to equalise it) Step 4. Convert final mole value to desired measurement (for moles, multiply it by molar mass to get mass) Correct Solution (more accurate) Mg MgO 1 1 2.4686 2.4686 Finding mass of MgO: 2.4686 (mol) * 40.3 (molar mass) = 99.5g Hope that helps.
you fucking douche, most schools doesn't have this ratio shit. If you have that free time to insult people. why don't do some videos explaining the fucking ratio shit. you fucking donkey.
Since oxygen is present in air, so we usually don't really calculate the absolute amount of O2 present in the reaction. For example, whenever you arrange a party, you'll be making sure the enough sufficient amount of food to be served to guests yet not be worrying about the amount of water, they'll be drinking, right. This is how it works
During the video: I can totally do this
After the video: What did he even say
I've been struggling with this for ages and you've just made it make sense for the first time - thank you so much!
thank you man you’re a god. all the other videos make it seem way more complex than it actually is.
I've never been so baffled in my life 😭😭
e.bleu_ L it's easy
@Have you Creamed
People like you are gross
IGCSE CHEM IN 4 HOURS AND COUNTING.... LETS GET THIS BREAD LADS
What if the moles aren't the same? What if it's a double-displacement type of of equation?
OMG U EXPLIANED SOMETHING SO HARD IN 6 MINS , ur a legend
thank you so much
Thank you so much for this video ^-^ I used to sturgle with this a lot but now I finally understand it ^-^
thank you so much!!!! I have been struggling with this fora whole and now i finally get it :) hopefully it all works out well in my chemistry gcse tomorrow !!
Hi Olivia. I'll post a video in the next few days with an example when it's not 1:1. Hope everyone's exams are going well!
I'm having trouble locating the 2:3 ratio video. What is it called?
my brain just hurt
What would we have to do if the ratio for the equation isn't 1:1?
Shamekh
I know that it's a bit late but just divide the two dividing factors and then multiple by that number
Thanks, weren't the magnesiums already balanced at 1 each in the beginning?
What would I do if I had a molar ratio of 5: 3, would I put it as a fraction?.
Thank Youuuu ! Helping With My MasteringChemistry
cross multiplication, 60x40=2400, 2400/24=100 simple, not sure if it works for all
Very helpful!
Thanks man.
my tutor never explains properly tysm!
Tyyyyy
Thank you
Amazing
Video solutions do not provide an accurate working out.
Instead:
Step 1. Draw up 2 columns with two rows (first row=mole ratio (coefficient of molecule), second=number of moles)
Example:
Mg MgO
1 2
2.4686 (mol) x
Step 2. Add an x (or any other variable) to fill in the mass you are trying to find (refer to above example)
Step 3. Apply mole ratio (2.4686*2 to equalise it)
Step 4. Convert final mole value to desired measurement
(for moles, multiply it by molar mass to get mass)
Correct Solution (more accurate)
Mg MgO
1 1
2.4686 2.4686
Finding mass of MgO:
2.4686 (mol) * 40.3 (molar mass)
= 99.5g
Hope that helps.
the mole of MgO is 2 and the Mr is 40. How come the mass is 100. its 80.
HAKEEM Thank you!👏
ur dumb
ur even worse are u blind?
you fucking douche, most schools doesn't have this ratio shit. If you have that free time to insult people. why don't do some videos explaining the fucking ratio shit. you fucking donkey.
u look like my left toe
what if the ratio is 2:3
Mixed Nuts lmoof
What about the oxygen though? Surely you need to take the oxygen into account?
Since oxygen is present in air, so we usually don't really calculate the absolute amount of O2 present in the reaction. For example, whenever you arrange a party, you'll be making sure the enough sufficient amount of food to be served to guests yet not be worrying about the amount of water, they'll be drinking, right. This is how it works
So helpful, thank you
What if it's not a 1:1 ratio? What if it was like 1:3?
I think then, at 5:10 instead of x1 you do x3 idk tho
@@kyntak5244 Yeah you do to balance it. If its a 3:2 ratio ,left to right, and youre trying to find the right side, you divide by 3 and multiply by 2
is it bad that i got a similar question in 9th grade ? i dont know how to do it.
Ik same
his profile pic tho hahahahaha
The dislikes are jealous teachers!
barin hurt
So confusing!
Who's got there gcse on Wednesday here?
Have you Creamed yep😂
what tier you doing pal?
Science higher tier chemistry Additional!
I do :) good luck guys 😊😊
ohhh gl booys