How to Find Theoretical Yield (2023)
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- Опубліковано 1 жов 2024
- * Convert all amounts to Moles
* Divide all moles by the COEFFICIENT of balanced chemical reaction
* Whichever of those results is lowest corresponds to your LIMITING reactant
* Use that reactant's number of moles and a MOLE RATIO to figure out amount of product made
* Convert to grams if necessary
Explained this better in 5 minutes than my professor did in an hour
So true
Really
I watched 10+ tuts, and din't get any shit out of them, this explained the concept in less than 6 minutes, W professor.
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Hey guys don't think deeply, people who work in pharmaceutical it's very easy to find.. Molecular Weight of your product/Molecular Weight of Starting Material*Batch input(Theoretical yeild), Batch input/Theoretical yeild*100= Percentage of yeild
what if you not given the mases of the reactants only one?
Then your screwed
Then the reactant about which information is given is your limiting reagent
What a great UA-cam find. 💯 Thank you for your services
Isn’t the molar mass 2H2 4?
Or are we ignoring the mole?
for some reason theoretical yield is a concept i was NEVER able to wrap my head around no matter how many times it was explained to me. after literal and actual weeks, THIS is the video that's finally managed to drum it into my thick skull. Thanks man
The explanation was great, I finally understand it. Thank You. BUUUT, where did you get the initial 3.0g for 2H2 and the 29.0g of O2. Can you please explain? Thank You,
It's part of the question
you explained this SO clearly, i finally understand THANK YOU !!
You can't belive how much did your video help me... This subject has too many videos explaining too many different useless ways of solving something as simple as you just put it. Great job, you saved me!
EDIT: I have a quiestion though... what do I do if I am not given the masses of not the reactants but only of the product?
Watch Kevin maths and science he's better
It's the day before the last day of school. I've been stuck on the last problem on my portfolio assignment for hours. I couldn't figure out theoretical yield. I watch this video and in 5 minutes and 21 seconds I finally understand. Thank you very much for this video and teaching me a problem that closely resembles the one I have to do. Thanks again!
Thanks sir for uploading such an amazing vid
Wa Ter
But why dindnt you multiplythe 2 of H2O by the 1.5 of h2
Yes! Wonder why this wasn't the case?
Understanding the yield calculation was so easy. I never even thought about it before.
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I watched so many videos and could not understand how to do this until I found this one! Thank you so much!
thank you allan from smiling friends i appreciate your help
Thank you thank you thank you👍👍👍👍👍
Wouldn't o2 be limiting cause it's completely used up
You might have just saved my chemistry exam😭
Magical video 📸
Thanks dude! I was confused by this for years and you made it so simple.
thank you!
How would I find the percent yield with this kind of equation, where neither PY or actual Yield is given. Would the AY be molar mass of a product - the amount of product lost?
genious!
I tried doing this with the net ionic eqn but it didn't give the same mass of product in the end. Strange
It's for a quiz retake im doing with the reaction between 0.040 moles of Silver I Nitrate and 50.0 ml of 0.60 M Calcium Chloride.
Great Explanation ❤
Thank you:)
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Among the reaction which reactant are we suppose to use for us to find theoretical yield
❤🎉
@chemistNate what happens when you three products
Thank you sooo much
Uve really helped me tnx a lot
You may have just saved my grade, and for that I thank you ✨
Good video, bit wanted to ask that what if we don't know the mass of one reactant
Damn that was faster than the other formula and much easier
Great explanation this is the only video that’s helpful for me
very well explained!!
Really great explanation!! Thanks so much❤
❤good video
Perfectly clear, thank you.
Angas gagi HAHAHAHA
W mans
Thank you man😊
Thank you so much!!!!
Very helpful thank youuu
Couldn't understand better
Thank you!!best of luck!
love it
where the hell did you get 18.0 grams from?
The molar mess of H2O
❤❤
very useful! Thanks a lot
Thank you
Thank you!!!:)))
Thank you so much for this!
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