at 29:14 Metal will gain slight electropositive character due to deficient of electrons... everything is explained nicely with good tactics. Thank you and keep resuming this wonderful work.
Sir u r very hardworking and at the same tym calm and patient that evn aftr technicl issue u keep on teachng so calmly that ovrpowers these typ of things in this video.thanku for ur efforts..
Sirr ..place that mirror which is behind the board ...in front of camera while filmjng so that you can see from the place where you are teachingg...and plz make an video or tell me a book about boron hydrid..
Sir plz upload a video about how to find out no. Of bridging carbonyl ligand in a organometallic compound and also finding out the no. Of M-M bond and bridging carbonyl simultaneously.
a big thanku for such kind of precise videos as well preparation strategies when the exam is knocking at the door..will u please give some lecture on raman spectroscopy?
sir! In miessler and tarr,I have found that they have given octahedron for 6 skeletal atoms and pentagonal bipyramidal for 7 skeletal atom.so which table we have to follow?
sir,in house craft books one similar type of tables has been given in page no -717 but on the basis of total electron count where when if TEC =90 then the geometry should be trigonal prism and also one example is solved in this books,i.e. for [Os6(co)18P]-(WITH ONE NEGATIVE CHARGE) BUT when i go through your tables and findind the SEP i got 9 for this same comolex which means it has dodecahedron geometry,how this two geometry co-relate ,i have checked ,these two geometries are totally different.which is correct please told me.
sir it not work for Rh6C(CO)15with 2 negative. question in dec. 2106. Acc to u S.E =9 dodecahedron. but ans is trigonal prism ....... dodecahedron is not in option of csir net dec 2k16
Formula to be used is (TVE-(12*n)-(2*n))/2. Where the first 'n' represent the number of transition metal and the second 'n' represent the number of main group element. When solved we get 10 SEP and hence its structure is tricapped trigonal prism
Can you please explain how to calculate the structure of (Rh6 C (CO)15)-2. SEP comes out to be 9. So the structure should be decahedron. But the correct answer is trigonal prism. Can you please explain sir?
In case of( fe4c(co)12)4_ u r not contributing carbon while substracting it as 12 *n while in case of co2B8c2h10(cp)2 u substracting ....pls explain..is we HV to subtract when both r present only???
In your last example where both transition and non transition atom is present you calculate SE predict the geometry of complex if we want know its is closo nido aur arachano..then ???
sir, in complex os6(co)18 the S.E=6 so a/c to u the geometory should be trigonal bi pyramidal but the answer is capped trigonal bipyramidal.are the both same
Sir what is the geometry of [ReH9]2_ ? According to you geometry is Dodecahedron. But csir and is tricapped trigonal prism... Dec 2016 set B , question no 80. Sir plz kindly check it
Sir, if both polyene attached with metal are aromatic and even no. Of carbon then where nucleophile will attack (no. Of carbon is different in both polyene....
Sir Co2BaC2H10(Cp)2...here how 70-12*2-2*10 12*2 I could understand.how 2-2*10...here non transition elements Ba,C know..then how..pls explain sir..this question at 18:27 in the video..my doubt is that no.of non transition elements how it is 10.pls sir
The geometry provided here for SeP is arranged in wrong order if I'm not wrong. Shouldn't it be octahedron for 6, pentagonal bipyramid for 7? Please clarify.
Great videos sir!!! One suggestion regarding y ur videos stop recording I'm between is that you might be getting msgs or calls on your phone ,in such instances video stops recording, try recording videos in airplane mode ....
Sir according to you if skeletal electron pair is 9 then Dodecahedron geometry. But csir ans for the compound RhC(CO)15 with 2 negative charge is trigonal prism which contain 9 electron pair. Sir PL kindly reply ....
Sir in ( fe4 c CO12)2- why u not considered carbon metal ...like u done after calculating TVE ....to find skeleton electron pair... shouldn't it be like( 62-4.12-2.1)÷2
![Wade Rule and Wade-Mingo's rule[Simplest Explanation] | Finding Geometry of Metal Cluster](http://i.ytimg.com/vi/qypcvnf9k3I/mqdefault.jpg)
at 29:14 Metal will gain slight electropositive character due to deficient of electrons...
everything is explained nicely with good tactics. Thank you and keep resuming this wonderful work.
Sir, today I had to take seminar on wade-mingos rule. This video really helped me a lot. Thank you sir.
Your hardwork and efforts in making this video is really appreciable🙌🙌🙌🙌....thank you so much for this video sir
Your work is great you dont know you helping so manny students who hv no proper resources to crack the exam.. continue..it..plz..great job
I agree
Sir u r very hardworking and at the same tym calm and patient that evn aftr technicl issue u keep on teachng so calmly that ovrpowers these typ of things in this video.thanku for ur efforts..
Best way of teaching... It helps us alot. Thanx for the great help...
Nice video sir non of single video on mingo rules u did it only thnk u sir
Your efforts are outstanding keep it up 👏👏 ur videos r really helpful for us thanks for making such a wonderful videos
Sirr ..place that mirror which is behind the board ...in front of camera while filmjng so that you can see from the place where you are teachingg...and plz make an video or tell me a book about boron hydrid..
Awesome Sir...all examples are really helpful..
thanking you sir for valuable information... video is not filming again again but you tried for us is very important... thanks a lot again sir
nice video making .specially thankfull sir .it is very helpfull for preparation for interance exam ...
Very useful and resourceful video.Thank you for the effort
very nice way to solve the questions
Sir very useful video I have never found it before in such a good way.
Sir plz upload a video about how to find out no. Of bridging carbonyl ligand in a organometallic compound and also finding out the no. Of M-M bond and bridging carbonyl simultaneously.
Awesome 👍😘👍😘👍
Thankyouuu so much sir... even ASF didn't tell me the geometries of skeletal electrons. I was so confused before watching this... thanks a ton sir.
really I was waiting for this type lectures especially for csir ...
helpful
thanks for preparing simple explanations. your all videos are easy to understand
Your videos are superb! Thank you so much..Please make a video on Mossbauer spectroscopy taking all previous years questions of CSIR NET exam
lecture was to good
one suggestion for u put mirror in front of ur phone to look recording is on or not
bcoz ur effort shld not be wasted.
thank you
Sir thanks A lot i started preparation after 3 year n you clear my doubts
Very unique and helpful...
Keep up the good work bhai
Excellent sir... It helped a lot...
Respecting your hard work sir
a big thanku for such kind of precise videos as well preparation strategies when the exam is knocking at the door..will u please give some lecture on raman spectroscopy?
you are simply awesome. Can you please share tricks to bag single digit rank.
sir! In miessler and tarr,I have found that they have given octahedron for 6 skeletal atoms and pentagonal bipyramidal for 7 skeletal atom.so which table we have to follow?
it was really helpful..... thanks Dada......
Sir, in Mungo's rule if two polyenes have odd number of carbons then nucleophile attacks or not.
After the attack of nucleophile in Mingos & Greevs Rule, what will be the compound final structure? What will be the final hapticity of ligand?
sir,in house craft books one similar type of tables has been given in page no -717 but on the basis of total electron count where when if TEC =90 then the geometry should be trigonal prism and also one example is solved in this books,i.e. for [Os6(co)18P]-(WITH ONE NEGATIVE CHARGE) BUT when i go through your tables and findind the SEP i got 9 for this same comolex which means it has dodecahedron geometry,how this two geometry co-relate ,i have checked ,these two geometries are totally different.which is correct please told me.
Sir , I think the Geometries tbp is for SE=7 , and in that way all the other Geometries are shifted from their SE values ,,, as written on the Board
Sorry Sir , Geometry pbp is for SE=7
Thx i finally got a interesting chemistry explaner ....method is too effective
Thank you sir... Very nice collection both closo, neido type.. As well as geometry..
sir it not work for Rh6C(CO)15with 2 negative. question in dec. 2106. Acc to u S.E =9 dodecahedron. but ans is trigonal prism ....... dodecahedron is not in option of csir net dec 2k16
Sir did you find the correct solution for this? Plz reply sir
Formula to be used is
(TVE-(12*n)-(2*n))/2. Where the first 'n' represent the number of transition metal and the second 'n' represent the number of main group element. When solved we get 10 SEP and hence its structure is tricapped trigonal prism
deebika baskar hi mam. ...here by applying that formula we got 8 SEP.how u got 10 SEP ? can u plz explain ?
Can you please explain how to calculate the structure of (Rh6 C (CO)15)-2. SEP comes out to be 9. So the structure should be decahedron. But the correct answer is trigonal prism. Can you please explain sir?
Thank you soo much sir..... Very greatful for ur work 🙏
Sir, can you explain why you didnt subtract 2n from [Fe4(C)(Co)12]2- eventhough carbon is present.
The struture of Os4(CO)16 is square planar not pentogonal bipyramidal
In case of( fe4c(co)12)4_ u r not contributing carbon while substracting it as 12 *n while in case of co2B8c2h10(cp)2 u substracting ....pls explain..is we HV to subtract when both r present only???
Why did you not consider the C atom for se calculation in Fe4C(CO)12 2-
please tell me that whether geometry depends on SE pairs or NO. OF VERTEX ( and whether no. of vertex = SE pairs or Not)
thank u very much sir plz keep going on to upload these videos
you really helps a lot for cracking such competitive exams .
Goood job dear..... u are awsme....
good job sir
thank you sir for helping us in such a way........
In your last example where both transition and non transition atom is present you calculate SE predict the geometry of complex if we want know its is closo nido aur arachano..then ???
Sir when SE is less then 6 then how to find geometry
sir, in complex os6(co)18 the S.E=6 so a/c to u the geometory should be trigonal bi pyramidal but the answer is capped trigonal bipyramidal.are the both same
very helpful video sir thanks..
Great work thnku so much
thank you so much sir..you are doing a very good job .. it's really helpful sir..may God bless you
sir how to find structure of (Bi5)2+ , there is no matching with 4n+2 or 4n+4 ...
Sir what should be studied from the topic chemistry of noble gases??
Sir what is the geometry of [ReH9]2_ ?
According to you geometry is Dodecahedron.
But csir and is tricapped trigonal prism...
Dec 2016 set B , question no 80.
Sir plz kindly check it
Thank you sir.. I requested this video . U responded soon.. thanks a lot for ur support and guidance
Sir, if both polyene attached with metal are aromatic and even no. Of carbon then where nucleophile will attack (no. Of carbon is different in both polyene....
Sir Co2BaC2H10(Cp)2...here how 70-12*2-2*10
12*2 I could understand.how 2-2*10...here non transition elements Ba,C know..then how..pls explain sir..this question at 18:27 in the video..my doubt is that no.of non transition elements how it is 10.pls sir
sorry sir..it 's my mistake.i thought it's Ba.actually it is B8.then valence electrons is 24..👍👍
Which book follow for Davis mingoes & greaves rules?
sir agar pi acceptor h to electronegative. kaisi hoga
Sir i have one doubt sir... Co2 B8C2 H10cp 2is considered under nontransition thenwhy we dont consider c in Fe4 C CO 12 2- ....
sir when both rings having odd no.of carbon means how to find out the attack of nucleophile like ferrocene
The geometry provided here for SeP is arranged in wrong order if I'm not wrong. Shouldn't it be octahedron for 6, pentagonal bipyramid for 7? Please clarify.
okay, thanks
vry helpful video , thnx sir
Sir how to calculate M-M bonds for those system which doesn't follow 18 e's rule.
and sir if we want to solve queations from wherewe can pracise
You are the best.
thanks a lot sir u r doing great work for us
ur doing great job
Sir geometry rule is totally wrong plz correct that one .
Could you please tell me what's wrong. Which geometries, and what should they be?
Yes sir number only changes in geometry
Manisha Subedi 6 was octahedron
Sir what if both the polyenes are even numbered & aromatic??
when two T.metals are there then how to find metal metal bond such as in Co2Fe2(CO)11(mu4-PPh2)
Sir how can we calculate bond order in metal halide clusters, eg in (Nb6Cl12) 2+?
Great videos sir!!! One suggestion regarding y ur videos stop recording I'm between is that you might be getting msgs or calls on your phone ,in such instances video stops recording, try recording videos in airplane mode ....
Could you please explain why H2Os6(CO)18 has capped square based pyramid ( housecroft)
Sir NMR spectroscopy (problem)..can you provide full detailed lecturers. I look forward
N really ur videos r very helpful for our preparation..
Ok sir..
Sir what is the geometry of [RhC(CO)15]2-
how can we find terminal and bridged carbonly atttached group in a molecule
What will be the case for [ Rh9P(CO)21] 2- ?
Thanks sir easy to understand..😀
Sir according to you if skeletal electron pair is 9 then Dodecahedron geometry.
But csir ans for the compound RhC(CO)15 with 2 negative charge is trigonal prism which contain 9 electron pair.
Sir PL kindly reply ....
Rh can't be only one... Your question is wrong
Thanku so much sir fr these wonderful videos..they means a lot fr my csir preparation.please upload as many videos as possible.
plz upload a video on various hydroxylations across a double bond (uncommon ones)......thanks for the earlier videos.....means a lot
Is n-4 is tetracapped or n-3 is tetracapped? U mentioned n-4 as tetracapped in this video.
very much THANK you keep doing it bro please
Sir in os5co16 SEP is 6 means TBP geometry.... But u have drawn octahederal pyramidal
sir, may i know the name of the book from which you have taken the table of geometry?
Very helpful video
Sir in ( fe4 c CO12)2- why u not considered carbon metal ...like u done after calculating TVE ....to find skeleton electron pair... shouldn't it be like( 62-4.12-2.1)÷2
But sir in Co2B8C2H10cp2 ...then here why we took contribution from both B and C....can they able to replace vertex Co
Sir I am not getting it
Sir how we will know which atom have replaced which ..in metal cluster
What is the geometry of [Rh6C(CO)15]2-
sir what shd i do from solid state on point of view for csir only
Sir Is this rule is apply only closo borane.Plesse clear it.
Sir will you please upload some videos on molecular orbital theory of diatomics and multi atomics like ch4 sf4 etc
I think steric no should be 5 for trigonal bipyramidal geometry...??
Thank you for your patience.....
Thank u sir ,,, very useful videos...