I have a final engineering exam tomorrow for engr 311 and all your videos have helped me so much. thank you so much for these. you gained another subscriber and like.
I'm searching for the best lecture , but when i watch this video it was very awesome and topic which i found difficult seems to be easy . Thank you mam
I found the value of m by solving the corresponding auxiliary equation. For example, consider the equation with x: X'' - 4a^2X = 0. The corresponding aux equation is m^2 - 4a^2 = 0.
Can you please explain at 15:00, in the partial derivative, why the dependent variable became X instead of u? Previously you referred to it as d^2u/dx^2 where d is the partial derivative sign.
thank you so much Professor, you came to rescue my life, i spend days trying to understand this topic but i could not, then l came across your video, which book where you referring to
Can you make a drive link in which you upload all the chapter 12 notes I have my finals in 2 days and they would really help. And your lectures are a life saver So much better then what my professors teach. Thanks
thank you for making your lectures public. They really help.
I have a final engineering exam tomorrow for engr 311 and all your videos have helped me so much. thank you so much for these. you gained another subscriber and like.
I'm searching for the best lecture , but when i watch this video it was very awesome and topic which i found difficult seems to be easy . Thank you mam
Watching these for a refresher in my DE's for 2-D heat transfer, they're very helpful!
I have a final in 3 days. You saved my life. Thank you!
Same here buddy
@@borataspek7562 I have a final tomorrow
same here
This is really wonderful. Keep it up with the good lessons. Wishing you were my mentor.
thank you for this. You just save my life.
I have a quick Question, Ma'am.
13:03 Is It Necessary For The Constant to be Negative?
تشرح احسن من جماعتنا
con facilidad explica las EDP. muchas gracias
thank you very much for sharing this in youtube
how are you calculating the value of m? at around 18:00 ?
I found the value of m by solving the corresponding auxiliary equation. For example, consider the equation with x: X'' - 4a^2X = 0. The corresponding aux equation is m^2 - 4a^2 = 0.
@@alexandraniedden5337 then how did u integrate this into C4e^ -2ax
Can you please explain at 15:00, in the partial derivative, why the dependent variable became X instead of u? Previously you referred to it as d^2u/dx^2 where d is the partial derivative sign.
thank you so much Professor, you came to rescue my life, i spend days trying to understand this topic but i could not, then l came across your video, which book where you referring to
Advanced engineering mathematics by dennis G. Zill
how do you know when to use cos and sin or e for the general solution?
You find the general solution in terms of the trigonometric functions sin and cos by looking at the auxiliary equation
Madam Thank you. It helps a lot
Thankyou Respected Instructor
obrigado!
Thanks alot mam🙏🙏🙏
Lord bless you.
Help for complete solutions to this chapter.
Is this in the playlist
what would change if you had a constant in the original equation how could you solve that?
THANK YOU PROFESSOR!!!!
Can you make a drive link in which you upload all the chapter 12 notes I have my finals in 2 days and they would really help. And your lectures are a life saver So much better then what my professors teach. Thanks
Thank you so much!
Can you please share Handwritten Notes
drive.google.com/file/d/184MkUHrxdvp_X0-YgfpnT26nW1UZ3g6Q/view?usp=sharing
@@alexandraniedden5337 Thanks
احبج وعلي
Plz post question no 13 of 12.1 also
My tuition should go to you instead of my Professor.
Thank you!
❤❤❤