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How would you do this for a load with a negative slope? Also , how would you 'turn off' this load?
i think you turn off a load by doing the same term again but with a negative sign (and also obviously the x value will be different than when the load started)
Nice Video. What software or app do you use to draw/write?
Thanks. Only the Notes App on an iPad :D
@@LessBoringLectures damn, u talented
I don't understand how come ^0 =0 for x
= 0 for x
In the singularity function for the reaction force, doesn't the exponent need to be -1. An exponent of 0 refers to a load right?
Should triangular load be = (1/2) * w0 * (L/2 * 1/3)
You're thinking about the equivalent force
What if the slope starts at wo and ends at 0
How would you do this for a load with a negative slope? Also , how would you 'turn off' this load?
i think you turn off a load by doing the same term again but with a negative sign (and also obviously the x value will be different than when the load started)
Nice Video. What software or app do you use to draw/write?
Thanks. Only the Notes App on an iPad :D
@@LessBoringLectures damn, u talented
I don't understand how come ^0 =0 for x
= 0 for x
In the singularity function for the reaction force, doesn't the exponent need to be -1. An exponent of 0 refers to a load right?
Should triangular load be = (1/2) * w0 * (L/2 * 1/3)
You're thinking about the equivalent force
What if the slope starts at wo and ends at 0