Sum = S = x + y = 6 → y = 6 - x Product = P = x . y = 36 You can say that S and P are the solutions of the following equation: z² - Sz + P = 0 z² - 6z + 36 = 0 z² - 6z + 9 + 27 = 0 z² - 6z + 9 = - 27 (z - 3)² = 27i² z - 3 = ± i√27 z = 3 ± i√27 z = 3 ± 3i√3 First possibility: x = 3 + 3i√3 Recall: y = 6 - x y = 6 - 3 - 3i√3 y = 3 - 3i√3 Second possibility: x = 3 - 3i√3 Recall: y = 6 - x y = 6 - 3 + 3i√3 y = 3 + 3i√3
Something very strange here .x+y=6 so , x=(6-y) …..y(6-y) = 36 …..y^2 -6y +36=0 Using the quadratic formula ……x =. -2.1961524 ………y. = 8.1961524 ……add up to 6 . But to xy = - 18 …! Clearly there is something here that is wrong as for the equation to work, the individual values can replace x and y to fit the equation , this is clearly not the case. Some explanation is required as there are two criteria that need to be proven and the individual who posted did not provide clear values for either x or y .
At 1:30 he has: 6x - x^2 = 36 Multiply by -1 and minor rearrangement: x^2 -6x = -36 He wants the left side to be a perfect square, so add 9 to both sides: x^2 - 6x + 9 = 9 - 36 = -27 That's where the 27 comes from. Then: (x -3)^2 = -27 And: x-3 = ±√(-27) Which is: x-3 = ±3i√3 And: x = 3 ± 3i√3
How is 6x-x^2= 36 become x^2-6x+36=0. Dont understand how 6x-x^2 is flipped around.
Multiply through by -1
Just do it: x.(x+y)= x. 6 and x^2+x.y=6.x and x^2+36 = 6.x and x^2-6.x+36=0 and solve ir for x.
Nice sir
Sum = S = x + y = 6 → y = 6 - x
Product = P = x . y = 36
You can say that S and P are the solutions of the following equation:
z² - Sz + P = 0
z² - 6z + 36 = 0
z² - 6z + 9 + 27 = 0
z² - 6z + 9 = - 27
(z - 3)² = 27i²
z - 3 = ± i√27
z = 3 ± i√27
z = 3 ± 3i√3
First possibility: x = 3 + 3i√3
Recall: y = 6 - x
y = 6 - 3 - 3i√3
y = 3 - 3i√3
Second possibility: x = 3 - 3i√3
Recall: y = 6 - x
y = 6 - 3 + 3i√3
y = 3 + 3i√3
Where did that 27 come from?
Where did the 27 come from?
Something very strange here .x+y=6 so , x=(6-y) …..y(6-y) = 36 …..y^2 -6y +36=0
Using the quadratic formula ……x =. -2.1961524 ………y. = 8.1961524 ……add up to 6 .
But to xy = - 18 …! Clearly there is something here that is wrong as for the equation to work, the individual values can replace x and y to fit the equation , this is clearly not the case.
Some explanation is required as there are two criteria that need to be proven and the individual who posted did not provide clear values for either x or y .
Math is solved here in a very beautiful and simple way by the teacher .. 👍 @ 🌹
The video was very helpful 👍
X+Y=6 , X=6 - Y ए कैसे आया ए केवल हुशार विधार्थी समज सकता है.इतका मतलब आपके पास जो है सबको दे नही सकता.
Why 27?
Yeah why 27....where did 27 come from....aaaaaaah
At 1:30 he has: 6x - x^2 = 36
Multiply by -1 and minor rearrangement: x^2 -6x = -36
He wants the left side to be a perfect square, so add 9 to both sides: x^2 - 6x + 9 = 9 - 36 = -27 That's where the 27 comes from.
Then: (x -3)^2 = -27
And: x-3 = ±√(-27)
Which is: x-3 = ±3i√3
And: x = 3 ± 3i√3
Gone case padh lo phele 🤣