sir u r awsome and incredible....youtuber like you are the legend for next generation education...this type of video are the revolution in education system...thank you...
i was curious to know about this MATHEMATICAL DESCRIPTION OF SIGNAL WAVEFORM as no textbook (as far as i know ) has taught it exclusively .It is of great help in understanding the other part of signals and systems.GREAT JOB SIR
Veryyy nicee explanation sir ....it's awesome 👏👏 👏 . Your videos are the best I have ever seen...i have understood this concept by seeing your lectures only.pleaseee upload video by taking some complicated examples sir...I am still confusing ....
@@PoluBalaji the slope was from -2 to 0. Thus, you subtract the final slope with the initial slope which is 0 - (-2) = 2. That is why it is 8/4 which is 2.
@@Sharmine_ 2tu(t)-2(t-1)u(t-1)-2u(t-1) Expand the (t-1) by Multiplying... 2tu(t)-2tu(t-1) Last 2 terms are Cancelled. Hence We only Left with 2tu(t)-2tu(t-1).
Sir in this lecture when take the derivative of 2r(t) you write 2tu(t) and the next lecture 2r(t) = 2u(t) I have problem in this part if you could explain it thanks
Thank you sir for this clear and nice explanation :), I need to plot the following function: Hw(tau)=H[Cw(t-tau)-r],could you please help me to plot it?Thanks again :)
In the second Example, shouldn't it go down by -17u(t-4) ?? because, if we go down by just 16, then a unit step would begin at t=4, and that will make the value of the signal 1 from t>=4 ?? Please clear the doubt.
Sir my question is that -What happened when the slop of ramp become 90 degree.As we know that tan90 is not defined. Please reply sir as soon as possible Thank you
hi I guess it is way too late, but the reason for that is because it is represented as "step" signal beceause there is a discontinuity, and therefore only the level is changing from 16 to 0.
@neso academy u askss us to comment in comment section if we hve any doubt but ihve been seeing that you didn't replied to anyone.. and didn't clearer any doubts
please can anybody plot 2nd in matlab? clc close all hold on t=-100:0.01:100; y= t>=0; r=t.*y; r1=(t-4).*y; x2= t-4>=0; p=4*y+3*r+-3*r1-16*x2; plot(t,p,'black') axis ([-5,10,-10,20]) xlabel ('Time,t') ylabel ('Exp. rising signal,sinc(t)') hold on t = -1000:0.01:5000; plot(t.*0,t) hold on t = -1000:0.01:5000; plot(t,t.*0) didn't work
sir u r awsome and incredible....youtuber like you are the legend for next generation education...this type of video are the revolution in education system...thank you...
i was curious to know about this MATHEMATICAL DESCRIPTION OF SIGNAL WAVEFORM as no textbook (as far as i know
) has taught it exclusively .It is of great help in understanding the other part of signals and systems.GREAT JOB SIR
Ma sha Allah! Lots of prayers for you, respectable sir.
Only Your Video is correct, simplified & short on whole UA-cam. I m very happy that now i can apply waveform synthesis 😇.
Just great. You don’t know what this means for me. All I can say is thank you, best of luck, and keep it up!✊🏾
Hello to everyone in Neso Academy. Your team is great. I am very happy to known you. thanks God. God bless all of your team.
Thank you again. 🌹💙💙💙
Wow amazing great superb explained .Saw almost 50 videos but didn't get explaination like this
I saw to many vid relATED TO RAMp prblm
But ur vid is cleared mY doubt.
Tq so much sir
Veryyy nicee explanation sir ....it's awesome 👏👏 👏 . Your videos are the best I have ever seen...i have understood this concept by seeing your lectures only.pleaseee upload video by taking some complicated examples sir...I am still confusing ....
Thank U so much Sir.... Thanks a lot.... I just can't explain how much I am grateful to u !! Thanks again ...
I wonder why, at 4:00 we add 2r(t-4) but at 7:38 did not add +4u(t-0) (and also at 9:03 didn't add +1u(t-1) ) ?
Helped me a lot
Thx from Egypt 💞
Sir, can you please explain the changing of ramp signal to U(t) I could not understand
come teach at my university you worth every penny! good job sir
This is the clearest explanation ever. Thank you so much
Understood everything in this video...???I've doubts can u explain
@@PoluBalaji Yes. Why?
@@juanmarcuslopez3018 I've one doubt can u please explain.??
@@juanmarcuslopez3018 At 4:03 the line passing through x-axis then slope is equals to zero but @neso academy took slope as 8/4 can u explain..?????
@@PoluBalaji the slope was from -2 to 0. Thus, you subtract the final slope with the initial slope which is 0 - (-2) = 2. That is why it is 8/4 which is 2.
After long time finally I got the point bz of you sir,thanks alot sir
ربي يحفظك ويسعدك يادكتور 💚🙏🏻
X(t) 3r(t) - 3r(t-4)- 16 U(t-4)
This is answer of problem 2 and topic is mathematical representation
Great and simple representation
Excellent work sir,thanks a lot...keep making lectures as you have been
You're a blessing 💥❤️
the way of explanation is fantastic Sir...👏👏
thank you thank you thank youu very much sir
finally I understand it !!
❤❤
Very nice explanation 👍👍
Very well explained .. thank you
Amazing work Sir, thank you!
at 3:34 , dont u think it should be 2r(t-4) because it is not turning at 0 but at 4?
Thank you very much ❤
Nice content! Go on...
Thank you for your explanation,Sir.
thank you for explaining
Best explanation ever sir😍
Please explain how to represent an exponential signal by this method?
Brilliant!
thank you thank you.............................
Thank you
Sir,
Please explain step at 10:01. i.e. How does 2tu(t)-2tu(t-1) was obtained from 2tu(t)-2(t-1)u(t-1)-2u(t-1)..?
By opening the bracket of "(t-1)" of second term.
I still don't get it. Can anyone explain it? thanks
@@Sharmine_
2tu(t)-2(t-1)u(t-1)-2u(t-1)
Expand the (t-1) by Multiplying...
2tu(t)-2tu(t-1)
Last 2 terms are Cancelled.
Hence We only Left with 2tu(t)-2tu(t-1).
@@VamsiKrishna-zv1tv Thank you!
Super awesome👏✊👍 sir truly ur fan
Will u plz make a vedio on introduction of micro processor
u r the best👍🏻👍🏻
Sir in this lecture when take the derivative of 2r(t) you write 2tu(t) and the next lecture 2r(t) = 2u(t) I have problem in this part if you could explain it thanks
Sir, please explain how to write signal in terms of the gate signal.
Thank you 😀
Excellent
Sir explain on how to obtain the mathematical representation
Sir, can you explain what will be the equation if there is trigonometric function , for eg. Sine wave...
is there a way to do this by using only the step function?
Thank you sir for this clear and nice explanation :), I need to plot the following function: Hw(tau)=H[Cw(t-tau)-r],could you please help me to plot it?Thanks again :)
In the second Example, shouldn't it go down by -17u(t-4) ?? because, if we go down by just 16, then a unit step would begin at t=4, and that will make the value of the signal 1 from t>=4 ?? Please clear the doubt.
how to cross check the equation?.....by putting values of "t".......for que 1 at t=-1 it comes out 4....but how to know if that's correct or not?
nice work
Sir my question is that -What happened when the slop of ramp become 90 degree.As we know that tan90 is not defined.
Please reply sir as soon as possible
Thank you
hi I guess it is way too late, but the reason for that is because it is represented as "step" signal beceause there is a discontinuity, and therefore only the level is changing from 16 to 0.
sir what is the difference between r and u ?
Thanksva lot sir
@neso academy u askss us to comment in comment section if we hve any doubt but ihve been seeing that you didn't replied to anyone.. and didn't clearer any doubts
sir why do we have to settle for constant value?
thanku Sir.
How are you saying that this one is a unit signal and this one is a ramp....plz reply fast ?
Watch previous video of this topic 74 number
Sir is it true for gate exam we need to know all waveforms mathematical representation?
Answer conversion of ramp to step signal is ok sir, but suppose step to ramp signal conversion how to done sir. .....
@neso acedemy how u take 8/4r (t-4)...???at t=4 slope is 0 right..???
This is the basics right line passing through x-axis has slope zero…..!!
thumps up!
Sir i didn't get the calculations at the end. Can someone explain
r(t) = t u(t) ; as u(t) = 1 for t>0 & r(t) = t for t>0 , so r(t) = t*1 = t * u(t)......
please can anybody plot 2nd in matlab?
clc
close all
hold on
t=-100:0.01:100;
y= t>=0;
r=t.*y;
r1=(t-4).*y;
x2= t-4>=0;
p=4*y+3*r+-3*r1-16*x2;
plot(t,p,'black')
axis ([-5,10,-10,20])
xlabel ('Time,t')
ylabel ('Exp. rising signal,sinc(t)')
hold on
t = -1000:0.01:5000;
plot(t.*0,t)
hold on
t = -1000:0.01:5000;
plot(t,t.*0)
didn't work
iam the first
Thanku so much sir
Thank u sir