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Subnetting (Solved Problem 1)
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- Опубліковано 17 лип 2022
- Computer Networks: Subnetting (Solved Problem 1)
Topics discussed:
1) A Solved problem based on subnetting a network.
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This video tutorial deserves praise. It's so clear and easy to understand especially with the method that is shown step by step throughout. Very nice! :)
Wow this is the best content!!!! So easily understood the whole subnetting theory
I am from Ethiopia! I like NESO ACADEMY too much and your education suit to me thank you❤❤❤
In order to get no:of host address for an ip 2n - 2 In your example
2 power of 5 and - 2 = 32-2 == 30
So we need to take 5 bits from right to left of the octate
For no:of subnets
2n
2 power of 3 = 8
So in order to get 8 subnets we need to take 3 bits from left to right of the octate
Sir.... This... Is very useful for many students.... You did a great job sir... God bless you sir.. And thank you❤
Thank you for your video. It is very indeed very clear and easy to understand!
thank you may god bless you.i dont know how to thank for your explanations.
00:08 Learn how to subnet a network based on host requirements.
01:42 Subnetting a Class C IP address into 30 hosts per subnet
03:23 Understanding subnet mask and subnet generators.
04:55 Representation of binary number 30 requires 5 bits.
06:30 Identified subnet generator and octet position.
08:07 Generate new subnet mask and start subnet generation.
09:41 Understanding subnetting and IP address range calculation
11:21 Understanding network and broadcast addresses
Crafted by Merlin AI.
After days and 4hrs in a row I can't understand what even the IP subletting is thanks man every IP subletting can communicate with his IP that's make sense 100/200
I actually watched this twice and trust me the 2nd time it was different (😯)
I failed in my exam again. Now total failed paper is 18. I tried by unable to pass. your video r a great relief.
Great video sir! Clearly understood the topic😍
Balu ser 💥💥
Thanks, very good explanation, it makes sense, now I understand it clearly.
Thankyou so much sir today I gave my CN exam and it was fabulous 💚💚
han bhai aaj hai 😂😂😂😂😂😂
@@DhruvParekh_ 😂👍
Awesome and simple video to understand subnetting ❤❤
Clean and clear explanation
fantastic.
Thank you so much sir, this video is really helpful for my tomorrow's exam🙏❤
One of the favourite ❤️❤️❤️ channel... 🌿🌿🌿🌿
the best explanation on the world !!!!
Thanks!
4:46, you said there must be 5 bits. but 16+8+4+2 = 30, then why that 0 is necessary, as you said 5 bits are must, is there any firm reason for that necessity ?
Really loved this one 🤩,
Kal mera etp hai cse307 ka
Aur abhi yeh dekh rha hu as a last topic for revision
Thanks a lot...Your explanation makes it easy to understand
Superb. Very easy to understand
Thanks for the amazing lecture💗💗
clear and concise.
wonderful, your videos are awesome to understand. Thank you.
Tou are telling the classless subnetting but you are using the classes of ip.
Anybody answer
Thank you very much sir 🙏
having an exam in 5h, thank you sir
Very good explanation
crystal clear... thankyou so much sir
Sir when will you upload part 2 of subnetting🙃 I have an exam in a day and I was relying on your lectures completely. Sir pls upload soon😭🙏 btw u are God sent😍😍❤❤
Soja bro
nicely explained and easy to understand the subnetting concept...thnak you
your the best (from sri lanka)
Excellent work
Good explanation
Clear explanation... Thank you!!
Please upload more videos on subnetting
Great explanation , thank you ❤
if the binary number of "total host number is start with zero", then can we generate subnet's ? please tell me sir!
Great lecture ❤
Wonder Full
Thanqq so much sir 🤩
Why didn't I watch this before my exam? Because I didn't have time. Or did I?
To tu exam bad ku dekh Raha he
@@ketansharma1411to tu exam ke baad usko reply kyu kr rha h?
Superb explanations !! Hats off and THANK YOU
Can we use this trick for classless addressing
Well done👍
After subnetting the class C IP address 216.21.5.0/24 into a range of IP addresses, all the new subnets have 255.255.255.224 or /27 subnet masks. How can they fall into different networks despite having the same subnet mask which is the /27 subnet mask? Is there someone who can help me with this doubt, please!!
god level teaching skills
Lol....
Teaching skills are very good but this sentence is wrong
great sir geo
Superb
Wow . Awesome explanation
My Lecturer😊😊
Plz upload power electronics videos
Sir plz can you give homework question on this video too 🙏
Hello sir pls solve this question " An Organization is granted 130.56.0.0/16 .The administrator wants to create 1024 subnets. a)Find First and Last address of first subnet. b) Find first and last addresses of the last subnet.
This Question was ask in UGC NET EXAM. pls help.
a)136.56.0-130.56.7.0
b)136.56.248-136.56.255.0
To solve this question, we first need to determine how many bits will be used for subnetting. Since the administrator wants to create 1024 subnets, we need at least 10 bits (2^10 = 1024).
Now, let's break down the steps to find the first and last addresses of the first subnet and the last subnet:
1. **Determine the subnet mask:**
Since we're starting with a /16 network (130.56.0.0/16), and we need 10 bits for subnetting, the new subnet mask will be /26 (16 bits for the original network + 10 bits for subnetting = 26 bits total).
2. **Calculate the subnet size:**
With a /26 subnet mask, each subnet will have 2^(32-26) = 64 IP addresses. However, we'll have to skip two addresses in each subnet (network address and broadcast address), leaving us with 62 usable IP addresses per subnet.
3. **Find the first and last addresses of the first subnet:**
- First address: The first subnet will start at 130.56.0.0 (network address) + 1 = 130.56.0.1
- Last address: The last usable address in the first subnet will be 130.56.0.0 (network address) + 62 = 130.56.0.62
4. **Find the first and last addresses of the last subnet:**
- To find the last subnet, we need to determine the network address of the last subnet and then calculate the first and last addresses accordingly.
- Since there are 1024 subnets and each subnet has 64 addresses, the last subnet will start at 130.56.0.0 (network address of the original network) + 1024 * 64 (addresses per subnet) = 130.56.64.0
- First address of the last subnet: 130.56.64.0 (network address) + 1 = 130.56.64.1
- Last address of the last subnet: 130.56.64.0 (network address) + 62 = 130.56.64.62
So, the answers are:
- First subnet: First address = 130.56.0.1, Last address = 130.56.0.62
- Last subnet: First address = 130.56.64.1, Last address = 130.56.64.62
For a class c IP address 4 octets will be there ..but in your example only 3 octets are filled.216.215.0 ..why so?
It is 216.21.5.0
Neso Academy deserves University Fees. Thank u
Why 5 bits specifically?
Why is there 224 in the 4th octet of the new subnet mask?
Thank uuuu
On a class B network, how many subnets are available with a subnet mask of 248? write if anybody no the answer with explanation
Shouldn't the subnet generator be 64?
How did you get 224?
I understand the 27 but not the 224
Oh never mind I got it, thank you
how do you identify that it is class C- type
there are some predefined ranges
if the starting range of a network is from 0-127 that means it belongs to Class A
same goes for the other ones
128-191 (Class B)
192- 223 (Class C)
224- 239 (Class D)
240- 255 (Class E)
The reservation process is from left to right i guess. And now here it is from right to left
IF anyone is aware of this topic,I have one doubt EX:- For my company i need three branch and in each branch i need to have 50 hosts ? Can you !.
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216.215.0 kaha se aaya?
Behave your self
💖🙏
bhai mujhe kuch jhaat nhi samja
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