Remainders 5 || Number Systems || Quantitative Aptitude || CAT PExam reparation 2024
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- Опубліковано 9 лют 2019
- Number System by Ravi Prakash | Quantitative Aptitude for CAT 2024
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i am not preparing for cat but still these videos are best for quant from very basic to pinnacle. It's a great gift you have given to your students sir thanks a lot. I came across these lecture through a friend preparing fr cat.
What sorcery is this, I never knew maths could be this easy and fun! much love sir..
Hats Off Sir!
Everything seems easy!
Thank You for the wonderful lectures
God bless you for providing such quality for free. And I absolutely love binging on your videos Ravi Prakash sir!
Sorry but his name is ved prakash😅
I do love your VARC video very sir thank you for to you also
Amazing videos.got to know about it from my friend on my birthday.i think it's the best birthday gift I received.ravi sir thank you making everything so easy
happy birthday
Did you crack CAT?
Hyyyy
Fakne me aag ho
Thank you sir your videos are free and really helping me thanks sir
Sir where can i get the quizzes . can you please share the link ?
Sir,I can't thank you enough for explaining these tricky concepts in such a simple and easy manner.. Thank you sir.
sheer hardwork reflecting
plese provide the link of quizes and practice sets.
You always do good question, good question.
Sir, where can I find your quizes??
Where are the quiz questions available?
At 18:20 if I'm taking 22^7 instead of (-3)^7 I am getting the different answer that is 3......can anyone explain why is it so or I am making mistake somewhere.
Can someone please guide me where is the quiz sir is talking about in every video
where can i find the quizz questions
Amazing concepts😊❤
In chinese theorem questions instead of solving the complete qsn u all should directly divide the power with 4 and than u will get a remainder than open the powers of giving qsn and than divide with denomentr you will get answers with in 10 to 20 second
chinese theorem ans should be different is 47 and sir ans is 63 hows is possible?
@@dheerajghuge7374 how
Sir why some questions show different results for Euler Theorem and Chinese remainder theorem
Eg:- For question (32^32)/6
Euler answer : 1
Chinese theorem answer :4
I am Having problem in applying the theorems in which questions ?
Please read Euler's theorem's condition .. a and b should be co prime to apply Euler's theorem
@@priyarani9569 Oh! Yes, you are right. 😃
He has applied the Euler theorem for 32 and 3 as they are coprime but it can't be applied on 32 and 6 as they are not coprime.
💕💕💕💕Thank you i wanted the same answer. Thank you .@@priyarani9569
Sir what we do for rc's ?? ❣️🙏
From where we can get questions to solve???
Sir, can we also use negative reminder in the last equation as "4x-1=25y-12"
Sir please explain at 13:00 how didi we get x = 6
I first like and then watch the videos :) thanks sir ❤
Thank you so much sir.❤❤
Are students still watching these masterpiece videos?? Well best of luck for CAT 2022 ...
😅😅yups
Yesss hehe
i am preparing for CAT 2024 and these videos are like a blessing
Are you taking any coaching also?
@@Bestevershorts1212 no bro, self preparation
check my about
Same
where is the quiz?
From where I can get quize
if we reduce the 32/6 fraction and solve it via the euler method i am getting 2 (after multiplying the number i divided it with) so how is the ans 4 ?
32,6 not co prime ,so euler not applicable
In 1: 41 why it's again divided by 2/3??
sir from where we can practice quiz questions ? and sir thankyou so much for ur prceless efforts .
Did you get quiz
sir where can i find the quizzes?
where i can find the quiz questions!!!!!!!!!!...... i tired to find it out i was unable to find...if anyone knew anything regarding quizes then please lemme know
Thank you so much sir ❤️🙏
How Euler of 4 is 3,can anyone tell me
Quiz kaha milega?
where is question of quiz....?
Sir, 2 and 153 are co-prime. But if we apply the Euler theorem to this, the ans is 2^32, which will be an even no. And not equal to 103. Can you please clarify??
2^32 is greater than 153, so well calculate the remainder which 2^32 produces when divided by 153
Wish you give insight on upsc 2023 csat .. very helpful sir 🙏🏼
Why 2/17 remainder is 2?
First Question i.e. 32^32/6 is not giving the remainder 4 when solved by Euler's method. Can someone please help me by solving it by Euler's method?
Euler method is only valid when divisor and dividend base are co prime to each other
Sir I have a doubt in 347^347÷100
In this while taking 347÷4 taken as remainder 3 so why we haven't take remainder as 1 ( because 348 is divisible by 4 completely )
We can also write it that way, but the remainder we get is -1. Since we don't write the final remainder of any number in terms of negative remainder, converting -1 to positive remainder gives 3 as the answer
Even paying 1 lakh fees to private coaching doesn't teach like you
Keep it up sir
Hii
wonderful
sir in first question (32^32)/6, Euler of 6 is 2,if we solve directly by euler method the remainder of power which is (32/2)r becomes 0 . Which in overall gives remainder as 1 but the answer is 4. Please sir can you explain were I am wrong?
32 and 6 must be the coprimes to apply the Euler's Theorem so we can't solve it directly
What about cancelation factor
Sir how 2/17 remainder is 2
if i solve 32^32/6 by eulers theorem im getting remainder 1 and solving it by chinese theorem im getting it as 4, why this so?
We cannot apply euler's theorem in this question as 32(power) and 6 are not Co prime with each other
@@jagrucmahant1113 he is using the elur theorem when 32^32/3 after splitting 6 into co prime no............btw i have same doubt
@@kajalsingh3906 same doubt please let me know if you have reason
@@kajalsingh3906 simple, 32 and 3 is co prime with each other
@@kajalsingh3906 thanks bro
In the last question, how are we getting 2 as the value of y when taking the remainder of -1y/4|r = 2?
because in this case for denominator 4, we already know that remainder is 2, so we can easily calculate -ve remainder as 2 - 4 = -2, now consider minimum value of y when put in -1(y)/4 will give rem. as -2, we know that when denominator is bigger than numerator, remainder is numerator only. so if we put y = 0, remainder will be 0, for y = 1, remainder is 3 or -1, now put y = 2, we get remainder as 2 or -2 which satisfies the condition.
Thank you Sir🙏
With the Euler method on 32^32/6, I am getting the wrong answer (I got 1), could you check it?
Because Euler theoram only applies to co prime nos.
Since 32 and 6 are not coprime, you cannot use Euler theoram here
See by solving 32^32/6 by normal cancellation with 2 where 2 is common factor we are getting remainder 2 plz do check.
remainder is still 4.
When you cancel it, (32 x 32^31/6) = 16 x 32^31/3 with cancellation factor = 2. Now solve it, you will still get 4 as reminder
where are the quizes you mentioned in the video?
On our FB group
@@raviprakash6021 sir please attach the link of your FB page
Thankyou sir 🤍🤍🤍
After solving eq. u always say 32^32 is of form of 4+6k but u got this form using 3 and 2 I.e denominator I think it’s wrong to say that statement. Please let me know if I m wrong
when 2 and 3 are separately divided by 32^32, then only after solving two equations a general form representing the value is obtained and you can verify the statement from the last lecture where numerator was relatively smaller value so you can calculate it verbally too.
merko smjh nahi aaya 2/17 rem 2 kaise aaya , and 2/9 m rem two kaise 8:44 , please help
If ur numerator is smaller then denominator then the numerator itself becomes the remainder.
5:35 the ans is not the same if we do it by euler's theorem
for eulers theorem numerator and denominator must be co-prime
@@rashikagarg147 great memory 👍🏼👍🏼
@@rashikagarg147 thanks my question answered
Sir I tried solving the 1st question using Euler Theorem but I am getting 1 as a remainder instead of 4. Please help sir
For Euler’s theorem, the Numerator and denominator need to he co-prime.
In Q1, 32 and 6 aren’t co-prime as they have a common factor 2. Hence we can’t apply Euler’s theorem.
Sir, I have one question- What is the remainder when we divide 3^90 + 5^90 by 34?
Can we find remainder of first term and second term separately and add?
@@gunjanchaudhary2999 are you doing prep for cat 2023 or 24 and have you joined any institute/academy for cat?
Mera answer to 21 Aya h
In Chinese remainder theorem :split it into coprimes
thankyou sir
11:50 the lowest value of the eqn. 17x+1 = 9y+4 is x=3 & y=1.
Why do you think 51 = 13?
@@rohankhurana913 1st no. satisfying the expression would be the answer so if x=3 is lesser than x= 6
for your logic, if we put x= 6 then it is 103 = 13
Is this true?
Or i maybe confused in this part.
Would be glad if you explain me the steps for this one
20:52 if we take Y=6 then also remainder will be -2...so, if Y=6 then answer would be 163.
My doubt is also same ans coming is 163
Your problem resolved?
Bro you're thinking correct but the smallest number is always the answer so if you take y=6 then it will.gibe remainder as -2 but the final answer will be a bigger number than the correct answer
Where are the quiz questions?
sir when we solve the 1st question, (32^32)/6 with cancellation factor method then the answer is 2.
But with chinese remainder theorem we got answer 4
???????
how cancellation factor? 4 is anyways correct
For the same problem by directly applying Euler form the answer is 1...sir please check it and explain once
@@Rodha 32^32/6 can be Writtle as 2^160/6. Dividing by 2 on numerator and denominator gives common factor as 2 and equation becomes 2^159/3. Hence remainder is - 1^159*CF. Equals - 2 or +1.
But Chinese method gives 4.???????? How
@@Rodha also if we make the equation as (4^79*2)/3 remainder is 4/3 gives +1 and 2/3 gives +2. Hence remainder is 2*1 that is 2..
How????????
3 methods 3 different answers??????
thaank u sir!!!!!!!😇😇😇😇
eulers theorem video has some audio glitch which makes it difficult to understand eulers theorem.
ua-cam.com/video/hzlafE36Zvc/v-deo.html this is the corrected version of Euler's thm video
@@divine7696 Bhai itni mehnat se link bheja usko, aur reply tak nhi aaya...😓😂
@@nef_nef divyashu be like--gajab bezzati hai Yaar 😁😁
If we solve first question by euler method the remainder will be 1. ( Euler of 6 =2 , (32/6)r =2 and (32/2)r= 0 so (32/6)r^(32/2)r → 2^0=1 ) please explain this.
we can"t apply euler theorem because 32 and 6 are not co prime
at 12:50 when we divide -6 with 9 we don't get remainder as 3. Anyone please explain?
See the Concept of negative remainder in 1st video of remainders
@@Rodha but why do need to take -6 instead of 3? pls explain
32^32/6 cannot be solved using euler theorem! Please correct me if I am wrong.
32^32/6= (32/6)^(32/5)= 2^2= 4 so by using Euler's theorem we still get 4 as remainder
how 25 and 4 pair
Question 1
Sir please explain this
32^32/6=32^32/3 and 32^32/2 right
In 32^32/3 if we use Euler then 32/3|r^32^2|r if we use negative remainder here then 32/3|r=-1 and 32/2|r=0 and -1^0=-1 3-1 =2 we are getting right? Please explain sir
Euler's nhi lagega because 32/6 coprime nhi ha but 1+ -1 vala concept se answer 2 arha ha Mera bhi!
Doubt 2^40/11 gives reminder 5 by euler's theorem but.. Same thing gives answer 1 as Reminder by normal method like
2^40/11 = (2^5)^8/11
= 32^8/11
= (-1)^8
= 1
🙄
bro, by euler it is coming 1 only -> (2/11)r = 2 & (40/E11)r = (40/10)r = 0, so 2^0 =1
14:35 sir you said that any number divided by hundred then the remainder will be last two digits but in this the answer is 63 but according to that equation the answer should be 47
347^347 will be a number which will extend to a integer _________63, whose last 2 digit will be 63. Like 3^8=6561.
Good evening sir, what if i take the break up as 10*10 for 100 at 21:00
if you're talking about breaking denominator 100 into 10*10 for splitting the denominator , it won't be possible as these two numbers are not co prime
where can i get the practise questions
?
32^32÷2 how the remainder is 0
can you help me to solve (7^52)/2402 what would be reminder ?
@@sahajdeepsingh475 bro!
Answer is...2401
Break the denominator into co-prime factor...2*1201
7^4=2401 after it become easy
In the last question, how did you get y=2?
10/ 4 = 2 ; 2/4 = -2
Therefore -1y/4 = -2
-1(2)/4= -2
Y=2
I hope you get it now :)
@@mrunalmisal6896 but there is power as 2 right so if we put y=2, then it will become 4/4. please clarify.
Can anyone tell how to split number in seconds?
Do tables
Sir in first ques we cancel it by 2 i.e cancellation factor and then by applying euler ans is 2
32 and 6 should be co prime to apply euler.....check the conditions
In the first question if we solve by euler's theorem answer is coming 1 and by Chinese remainder theorem answer is coming 4.i really need help pls pls pls help me out
Euler theorem is not applicable , u can solve using cancellation factor ..
why is euler theorem not applicable here?
Because numerator and denominator should be co primes to apply Euler's theorem , but in qn 32 and 6 are not co primes..
So, split denominator into 2×3 , convert numerator in the power of 2. Then , it will be easy to solve..
5600÷6 gives remainder 4 only right, since 5556/6 is 926...hence the 2nd sum solution has a mistake...
How u got 5556? 🤔
can anyone tell where can i find the quiz?
You found it?
Why remainder of 347/4 is 3 and not -1?
-1 is also right.. but 3 is small enough for further calculation and why to complicate things by adding negative remainder
Remainder should be +, if u subtact your negative remainder by the denominator (4-1) you will again get 3, so both are correct try to get remainder as +
sir at 13:17 you have said that x has to be = 6 but if we take 6 as value of x then remainder should be -3 (-6/9 remainder = -3) if Im wrong can someone plz explain how its remainder is -6 and not -3
3/9 leaves a remainder of +3. but since left hand side(LHS) is negative, we have to put a negative remainder.
3/9 leaves a positive remainder of +3 and negative remainder of (-6)i.e. 3+(-9) =(-6)
If you are still confused, please check part 1 of remainders, chapter negative remainders
@@supriyas97 thanks
Where is the QUIZZE!!! 🤨
Help me to find out them... 🥺
Plz let me know if u got☺
@@kanchanchoudhary3001 no.. I've not got yet.
legends are still searching for it
@@rajeevbaishya1991 🤭🤭
TQ ...sir providing such a nice and nice vedio
shivam kamat (19)
10-8-2021
thank you sir 🙏
32^32/6 cannot be solved by Euler theorem . As 32 and 6 is not co-prime. [ condition to apply Euler theorem: numerator and denominator has to be Co prime to each other ].
But can we solve this by +1 or -1 basic ?
32^32/6 is being solved by Chinese remainder theorem which is possible because denominator is being split into product of co-primes, whereas Euler's theorem is being used to simplify 32^32/3 which is a part of the process and is possible because 32 is co-prime to 3.
Just need to be understand that by splitting the denominator, they should be co-prime with eachother
Sir has used Euler's theorem for 32³² /3 and not for 32³² / 6
cancellation factor =2 and then reminder is ultimately rem. is -1 multiple by 2 = -2 or 1 is final remainder
If you do the first question with the Cancellation Factor method then you get the remainder as 2 since you have to Multiply 1 with the C.f in the end.
But I dont think the answer should differ with the method so I am confused.
Come again
Sir, the first question that you have done in the beginning of this video with the Chinese remainder method, if I try to solve the same sum with Cancellation Factor method then I get a different answer I.e remainder as 2 Which shouldn't be the case i guess. With both the methods, I am supposed to get the same answer (4) na?
Hey mate, we directly cannot cancel 6 with 32^32. You first take one 32 out of 32^32. See, 32^32/6 = (32x32^31/6) = (16x32^31/3) with cancellation factor being 2. Now we get remainder as 1x -1^31 which is -1. Multiply this -1 with 2. So -2 is the remainder. But we know negative cannot be a remainder. So we'll subtract this is -2 from 6 which gives 4 as the final remainder.
@@deepshikhadas8545 thankyou
@@deepshikhadas8545 your equation in the end is divided by 3 not 6..so 3-2 gives 1 as answer.
I was going 1st qstn by cancellation factor...ansr is coming 2..why?
same doubt'
How?
32^32/6 = 16 * 32^31/3 (CF-2)
Remainder - 1 * (-1)^32 /3 = 1*(-1) /3
= -1/3 = -1
-1*CF = (-1)*2 = -2
Initial/real divisor = 6 so
6-2= 4 Ans.
@@kajalsingh3906 .
32^32/6 by euler is giving answer as 1
32^32 / 6 = 2^160/ 6 = 2^159/3 i.e the cancellation factor is 2. 2^2k/3 will give a remainder of 1, therefore 2^158 will also leave a remainder of 1. so we are left with only 2^1. 2^1 divided by 3 will give remainder 2. now multiply this 2 with cancellation factor. 2*2 = 4.
On question. 347^347/100 why can’t we take 100 as 20x5
Because they are not co prime
32^32÷2 how the remainder is 0
socho ek baari
Can anyone solve this using this method
4^160 is divided by 187
find the reminder
Ans : 1 how?
if you apply Eulers theorem, since 4 and 187 are co-prime, you get, " (4/187) ^ (160/160) " (euler of 187 is 160), therefore, 4/187 ^ 0 = 1
chinese remainder - 2
2 ^5600/153 you did this question solution is wrong because 9 is odd number and its euler number is
8
At 12:50 , How we got to know that we have to take 6. I didn't get thay point. Can anyone explain that?
Watch previous videos
5:00 9:00 14:00 15:00 23:00
Please solve 123^31^102 divided by 17 remainder?
Is the answer -1?
13
@@saptarshidas488 converting to positive remainder it becomes 17-1 = 16 ans:16
@@sjsthomasnick3002 ok 👍
@@saptarshidas488 hey, are you preparing for CAT'21?
Quizzes ka link pata hai kisi ko toh de do🙏