Derivative of Logarithmic Functions

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  • Опубліковано 29 гру 2024

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  Рік тому +37

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  • @leovolont
    @leovolont 5 років тому +23

    Hi Everybody. Time mark 8:47 the answer 2 / X LN(4) can be simplified. Remember that 4 is the same as 2^2 and so LN(4) is the same as LN(2^2) which is the same as 2LN(2) and so 2 / X LN(4) is equal to 1 / X LN(2). Graph them and they overlap.

    • @menyepy
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      waw

    • @ShiroKage-h8v
      @ShiroKage-h8v Рік тому

      wont it be 2x/xln4 ? I thought it is u'/ulna

    • @isaiahwalton2820
      @isaiahwalton2820 2 місяці тому

      @@ShiroKage-h8vno, you can pull out the 2 as its a property of logarithms, and the derivative if x is just 1

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    @georgesadler7830 3 роки тому +1

    Thank you for a fantastic video/lecture on the Derivative of Logarithmic Functions in Calculus. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.

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    @landonlee5536 2 роки тому +5

    at 4:57 why don't you subtract ^1/7 - 1 ?

    • @jeffreygoddard638
      @jeffreygoddard638 2 місяці тому +1

      I wondered the same, it’s because he’s using the property of logs that says: log(a^b) = b*log(a)

    • @landonlee5536
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  • @omari2292
    @omari2292 2 роки тому +4

    At 5:03, why didn't you subtract the exponent (1/7) by 1

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      @Mythos_XVI Рік тому

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  • @MauxX
    @MauxX 2 роки тому +2

    8:46 if I did not move the ^2 to the front of the ln, I would get a different answer since x^2 will be in the denominator. Am I missing something?
    THANKS FOR ALL OF YOUR VIDEOS

    • @JKMath
      @JKMath 2 роки тому +1

      If you did not move the ^2 to the front, then you would have had to use the chain rule and take the derivative of x^2, which is 2x, and multiply it by 1/(x^2*ln(4)). Notice that an x would cancel from the top and bottom and you would still get the same answer. Hope this helps!

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