Finding the Slant Asymptote
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- Опубліковано 2 лис 2011
- 👉 Learn how to find the slant/oblique asymptotes of a function. A slant (oblique) asymptote usually occurs when the degree of the polynomial in the numerator is higher than the degree of the polynomial in the denominator. To find the slant asymptote of a rational function, we divide the numerator by the denominator using either long division or synthetic division. The quotient obtained when the numerator is divided by the denominator is the slant asymptote of the function.
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Organized Videos:
✅ Find the Asymptotes of Rational Functions
• Find the Asymptotes of...
✅ Find the Vertical and Horizontal Asymptotes of a Rational Function y=0
• Find the Vertical and ...
✅ Asymptotes of Rational Functions | Learn About
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✅ Find the Asymptotes of a Rational Function with Trig
• Find the Asymptotes of...
✅ Find the Asymptotes and Holes of a Rational Function
• Find the Asymptotes an...
✅ Find the Slant Asymptotes of the Rational Function
• Find the Slant Asympto...
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Like all bald characters, this dude is also overpowered.
thanos, one punch man, *Brian McLogan*
😂 The internet remains undefeated...
😂
All Wraiths with the bald skin in Apex Legends.
Don't forget Johnny Sins, a man of many talents.
this 5 min vid is better for me than my whole hr long classes 😭
No disrespect to my teacher but this is factual
@@diegonunez3492 Real
@@BaseballsGoneYard REALLY real
8 years later, wonder if he's still looking good.
hopefully
still makes videos!! lol
its 9 now ➿
@@h3x4ry55 10 now !
@@michellewong3392 15 now!
turn on subtitles at 1:37
lol
I mean thats what it sounds like he said so
"those are two assholes that my crap is never going to touch" - Brian McLogan 2011
Thank you for this 😂😂
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I would not understand half of what I do now without people like you who make videos like this. Thank you
Hi Brian, almost 100k views on this one! Just shared it with a student of mine! You have videos on almost everything I've taught for the last 2 years! Thanks bud!
Absolutely! What you teaching these days
This really helps in quarantine times. Thank you!
Thank you! the only person who I could find who explained this in a way I really could understand🙏🏽
Man I remember you saving my ass back in highschool.
saved me during highscool, and still saving me in college
Most underrated teacher on youtube. I never thought I'd have to do long division again my whole life though haha. Guess I was wrong about that. Its back
Gosh why can't all teachers explain it like this? Thank you 🙏
Thank you! I have this problem for calc hw tonight, thank you for clarification! Love the vids
Weird flex but ok
Jesus i must be extra stupid if I cant even understand with you explaining like this 😔 rewatched it 3 times and that long division part still took me out
try finding his long division videos. I had to go back and practice long division too.
3:55 got me a stroke
I got mathematics board exam tomorrow and I found this video to be very helpful for curve sketching. Thank You Sir ❤❤
I’m studying for a test I have tomorrow, and this really helped me. Your awesome!
You’re*
Legit same
I love this channel, I got a test tomorrow and this is very useful because I missed one day that went over this.
So happy to help you out!!0
me too!
thank you Mr. Mclogan
This is so helpful.
Thank you for the help.
9 years later, wondering if he's still looking good.
Good refresher for what I have forgotten, thank you!
I understand everything that you say thank you very much you are the best teacher in the world 💙💙💙💙
Thank you soooo much, ur videos help me alottt
thank you sir
Watching this 15 mins before my pre cal test
1:51
Mr. McLogan: "I'll try to say them as slowly as possible"
Me watching on 1.5x speed:
Wow great video
Why did he add the 0 on top of the -1x during the Long division part
its because there was nothing but x cubed at the top, so (if you'll imagine a number line, that might help) when the x cubed was subtracted from the x cubed, you got 0. However, you still had the -1x, so it was effectively 0 - (-1x).
So the slant is x?
I did the limit method of f(x) - x and f(x) /x I got the wrong answer why?
cause u trash boi
@@attackdamage7105 lol
bro i love you
bro the Johnny sins of math
Thank you Mr brian sir, teaching me my stuff better than my teachers 🫡
f(x) = a(b)^x + c....... Horizontal asymptote is y=4........ 2 points of the function are(1, 0) and (2, -12)..... The function is decaying.... Find a, b and c
Pls help with this one sir
No
you literally are our school saviour
Hi there, I am hoping that someone will read this and help me!! lol ... I am taking the math cset next week and there is a practice problem that states which of the following is an equation for the slant asymptote of f(x)= x^3 -1 /(divided by) x^2 and the answer is y=x BUT I CANNOT FIGURE OUT WHY!!!! HEEEEEELP
do long division with the given rational function. You will get the answer x+1/x^2. As he said in the video, don't worry about the remainder just the divisor without it, which is x. Therefore the answer is y=x
0 minus negative 1 is positive x???
subtracting a negative creates a positive
AJ Kanakry yes!! haha, man thats basic division. this is why i got F in this lesson
You draw impressively straight line
Thanks but that horizontal line was something else
@3:25 I got cleared up some confusion that I got from the channel named: "The Organic Chemistry Tutor" I'm very impressed that you did this better than he did. This is exactly what I was hoping for, and why I'm here. 👍👍
My teacher barley explained this and expected us to know
Happy to help
You’re a saint, thank you :)
1:35 empty garbage task done
Among us?
Beautiful ❤️
How is a slant asymptote possible
You are very helpful, but dude, you must make your videos louder. I often times have to raise my computer volume all the way up just for your videos
Watching this exactly a decade later.
Ignacio Varga?
What if degree difference is 2....?
I'm pretty sure you still do the same thing
There won't be an asymptote.
There’s probably a hole
There's no asymptote because an asymptote must be linear by definition. But, the graph will always approach the function that is the quotient of the two polynomials (without the remainder). So, if the quotient is x^2, then the graph will approach the parabola x^2, but again, it's not an asymptote, because it's not linear.
This guy is doing our teacher's job for free
10 years later me struggling in pre calculus hmmm help?
This video is 12 years old today
I don't understand the slant at all. You should do more examples instead of one.
so like math
Thank you Tyson Fury
Lol forgot how to do long division 😂
Why is the residual not important?
hi thank you so much i understood but i have realized something weird like Americans and europeans have very strange last name i mean what is McLogan oh my god
Haha not sure
this make no sense the stutter is real
Why don’t you use standard terminology for numerator, denominator, dividend, etc.? I find that using standard terminology and pronunciation increases student understanding?
I thought that it was 1x and not 0x I’ve never seen 0x Oml I’m terrible at math
my prof took 4 hours to explain thing topic
does anyone else hear him say asympTOPE instead of asympTOTE
Brain playing tricks on you! 🤣
IF YOU ARE READING THIS, YOUR ATTENTION SPAN IS WAYYY TOO SHORT. GO BACK TO WATCHING MR. MCLOGAN 😀
haha
who else is here cuz they cant do their history homework?
10 years later, wonder if he's still looking good.