Solubility Curves - Saturated, Unsaturated, Supersaturated Solutions

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  • Опубліковано 31 лип 2024
  • CLEAR & SIMPLE Solubility Curves - Saturated, Unsaturated, Supersaturated Solutions - This video explains how to interpret solubility curves and read solubility curves. It discusses saturated, unsaturated and supersaturated solutions. This is an essential component of the unit on solutions/mixtures of substances. In a nutshell, unsaturated solutions have points below the line on the graph, saturated is on the line and supersaturated is above the line on the graph.

КОМЕНТАРІ • 156

  • @jessicabrown7984
    @jessicabrown7984 7 років тому +97

    this was a great video. He taught me more in 14 minutes than my teacher does in an hour

  • @diljotkaur1315
    @diljotkaur1315 8 років тому +150

    I was so confused at first, but this video made it crystal clear. Like if you agree. Thanks for putting this video up for struggling students

    • @Fleeb-pb7zo
      @Fleeb-pb7zo 5 років тому +2

      Chrystal clear, is that because crystals are left over🤣

    • @katiealexandra6347
      @katiealexandra6347 4 роки тому

      100000000 subscribers without making a video STOP

  • @1noxaj
    @1noxaj 5 років тому +23

    You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual

  • @lelegemperle1965
    @lelegemperle1965 9 років тому +35

    You are my hero. My Chemistry teacher said I should just 'google it' because apparently I'm too 'daft' to understand. So thanks for helping.

  • @spooked-cowboy
    @spooked-cowboy Рік тому +2

    I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!

  • @franchesca_jf
    @franchesca_jf 3 роки тому +3

    I was so stressed because I didn't know how to determine solubility curve but when I watched this video I finally understand the solubility curves.

  • @vonh101
    @vonh101 10 років тому +132

    Can you please replace my braindead chemistry teacher, PLEASE?!?!?!?!?!?!?!?!?!?

    • @sciencepost
      @sciencepost  10 років тому +9

      Lol. Von, this is not easy to teach. It may be easier on video, less distractions :) Be awesome!

    • @vonh101
      @vonh101 10 років тому +9

      sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.

    • @sciencepost
      @sciencepost  10 років тому +9

      Hey bro, go BIG. That means STUDY. I can't stress that enough. Put the time into this Final and you will not regret it. Be awesome! Go Big!

    • @vonh101
      @vonh101 10 років тому +4

      sciencepost Thanks, that just me want you as my chem teacher even more. Wish my teacher said stuff like that.

    • @sciencepost
      @sciencepost  10 років тому +5

      Lol. Keep rocking the vids bro, and perhaps you'll be the chem teacher one day too. Be awesome bro! I look forward to hearing from you again.

  • @1713Fearless
    @1713Fearless 10 років тому +12

    YOU PEOPLE SAVE MY LIFE (well academic life)

  • @al50n_13
    @al50n_13 9 років тому +6

    Thanks a lot! I was finding a bit difficult understanding this, but I get it now because of you! Thanks a lot again, you really helped me! =D

  • @ryankohlman3329
    @ryankohlman3329 8 років тому +4

    thannnnkkkk youuuuu i have had sooo much trouble understanding these. this help me 1000000%

  • @KonanGuan
    @KonanGuan 9 років тому +14

    you saved my life

  • @JayzSuper
    @JayzSuper 8 років тому +2

    Thank soooo you. You have made me understand things my teacher never could 👏🏾👍🏾

  • @sciencepost
    @sciencepost  11 років тому

    Kym, thanks for tuning in. So happy it helped you. Keep up the the studies.

  • @kimdavis1378
    @kimdavis1378 7 років тому

    Wow! You just saved me I take my Final today in chemistry and physics! I love your teaching, you are amazing!

  • @lissabean3993
    @lissabean3993 4 роки тому +2

    Wow you are an amazing teacher! Thanks!!

  • @jovannadelatrinidad8986
    @jovannadelatrinidad8986 5 років тому +1

    This video is nice and clear. My chemistry teacher does not teach us anything so I appreciate the video.

  • @fedora9575
    @fedora9575 4 роки тому +6

    "So, if you're a fish, and you're swimming around that lake.." Oh wow😂😂

  • @aliciakranak6203
    @aliciakranak6203 6 років тому +5

    This was so helpful (as a teacher!)
    THANK YOU!

    • @sciencepost
      @sciencepost  6 років тому

      Glad to help. Tune back in when needed :)

  • @batmanrobin7326
    @batmanrobin7326 7 років тому +2

    this was very helpfull you are able to "dumb down" something that i was unable to get thank you

  • @laa4530
    @laa4530 7 років тому +2

    My chemistry teacher gave HW on solubility which she hasn't even taught so thanks for saving my chem grade

  • @whoamiseccf
    @whoamiseccf 7 років тому +1

    Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.

  • @tonygarcia6752
    @tonygarcia6752 10 років тому

    Very helpful. Thank you for posting this video. I now understand my homework better

  • @alexavillarreal5043
    @alexavillarreal5043 8 років тому

    eternally grateful for this video.

  • @terrencejones9890
    @terrencejones9890 7 років тому +2

    Thank you so much! This helped a lot!

  • @memjaym
    @memjaym 10 років тому

    Thanks! I have my exams tomorrow and you explained this very clearly.

  • @vivalaelsa
    @vivalaelsa 8 років тому

    You seem like such a cool guy that's great at chemistry. Thanks for the video :) much appreciated and needed

  • @Elusive0101
    @Elusive0101 8 років тому +2

    You're awesome. Thank you!

  • @itzelt.4130
    @itzelt.4130 2 роки тому

    Thank you so much! i hope you have a great day and a great life

  • @georgekiadii45
    @georgekiadii45 10 місяців тому

    Thanks, a lot. This video gives a clear understanding of the solubility curve.

  • @saidkhamidjanov5406
    @saidkhamidjanov5406 8 років тому +3

    Very USEFULL THANK YOU SO MUCH!

  • @anna_kcx
    @anna_kcx 4 роки тому

    it all makes sense now. THANK YOU.

  • @mnbvcxzz27
    @mnbvcxzz27 10 років тому

    your videos are really helpful, and I love how your voice is so chill!
    you sound like a total bro

    • @sciencepost
      @sciencepost  10 років тому

      Thanks for the sweet feedback amigo. Not sure if I'm that chill, because I get pretty amped up to teach. Best wishes learning. Keep being awesome!

  • @shashankrockerboi
    @shashankrockerboi 8 років тому +2

    thanks a lot this video has really benefited me :)

  • @preranaoli3724
    @preranaoli3724 5 років тому

    Thank you so much for this video. It is so helpful.

  • @bal5429
    @bal5429 7 років тому +1

    THANKS SO MUCH MY CHEMISTRY TEACHERS A THICK HEAD AND IM ALWAYS ASKING QUESTIONS THXS :)

  • @walidalbarazi2
    @walidalbarazi2 9 років тому +1

    Thank you! That helped!

  • @chat1967
    @chat1967 10 років тому +2

    I am not going to fail my Chem test today!!!! :D

  • @alexisderrico2426
    @alexisderrico2426 11 років тому

    This video helped me so much. Thank you!!!

  • @ayeshanaeem9847
    @ayeshanaeem9847 6 років тому

    Thank you so much .
    You save my GCCEs

  • @J.Y_
    @J.Y_ 4 роки тому

    @sciencepost Is it ok if you explain how in a prac you would test how much of the solid dissolves in the given temperature until the saturation point has been reached. I understand the picture and the graph show a correlation (to make it easier to understand), but they don't directly refer to each other which what makes me confused on how they gathered the data for the graph. And also, that method of seeing how much dissolves in the pictures is a bit dodgy (eg.parralax error.etc)

  • @cia_di
    @cia_di 5 років тому

    Thanks you're a lifesaver!!!

  • @TheCaliBeaches
    @TheCaliBeaches 10 років тому +1

    Thank you. Feel much better for my solutions test tomorrow.

  • @andrewn621_2
    @andrewn621_2 5 років тому

    Dude i have a quiz on this tmrw and you literally just cleared my brain if you wanna be my chemistry teacher let me know

  • @FunkyFreshFong
    @FunkyFreshFong 10 років тому +2

    Thank yu sir! Now I can do my homework :D

  • @melaniejones9400
    @melaniejones9400 10 років тому +1

    Very helpful!! You made everything so simple.

    • @sciencepost
      @sciencepost  10 років тому

      That's great to hear. Now it's time to ace your test. Be awesome!

  • @sciencepost
    @sciencepost  11 років тому

    Thanks for watching Oneday04. I'm stoked you learned it. Tune back in again if you need help in other areas of chem. Peace..

  • @frznxcviiieb230
    @frznxcviiieb230 5 років тому

    Thank you it was very helpful.

  • @kweenlewis4277
    @kweenlewis4277 6 років тому +2

    thanks for diss video it help mi a lot

  • @funbigmama
    @funbigmama 10 років тому

    this is SOOOOOOOOOOOOOO easy THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  • @barbaracesar6520
    @barbaracesar6520 4 роки тому

    thank you so much. I finally understand 😊

  • @madamemianna
    @madamemianna 8 років тому +2

    Very Helpful

  • @maryssaharper9257
    @maryssaharper9257 9 років тому +2

    I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem:
    ...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.

    • @jainachhokar
      @jainachhokar 4 роки тому

      KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation:
      40 + x = 50
      Your end result would be x = 10, thus you need 10 more grams of solute.

  • @kymsingh5883
    @kymsingh5883 11 років тому

    so helpful!! thank you!

  • @sciencepost
    @sciencepost  11 років тому +1

    You are welcome!

  • @diegojoaquin4708
    @diegojoaquin4708 8 років тому +1

    i love your vids

  • @DotTheFallen
    @DotTheFallen 11 років тому

    Thanks for you're help.

  • @alexnordahl2000
    @alexnordahl2000 8 років тому

    Thanks! so helpful

  • @toastedtits2596
    @toastedtits2596 6 років тому +5

    Damn please be my teacher my teacher make everything seem so simple complicated

  • @celestepineda4380
    @celestepineda4380 10 років тому +1

    thank you so much! i can pass my test now :D

  • @alankimbrel46
    @alankimbrel46 10 років тому

    thank you very much!

  • @areebea
    @areebea 11 років тому

    Thank you so much!!!

  • @lexicadena7723
    @lexicadena7723 Рік тому

    this was actually so good

  • @_yellowlove
    @_yellowlove 4 роки тому +1

    Thank you!!!!

  • @Onedayo4
    @Onedayo4 11 років тому

    Thank's this really helped

  • @isisbinns5863
    @isisbinns5863 8 років тому +2

    I was really struggling with this, but this video really made it click. Thank you!

  • @loiseacosta6832
    @loiseacosta6832 11 років тому

    Thank you very much!!!!!

  • @anantkadam1684
    @anantkadam1684 6 років тому

    thanks a lot you have helped me a lot

  • @epicmoku6160
    @epicmoku6160 10 років тому

    THANKS MAN!!!!!!!!! You, sir, are AWSOME

    • @sciencepost
      @sciencepost  10 років тому

      Wow, I thought you were Awesomeness! Keep up the sweet effort. Do your best! Be Awesome!

  • @christopherpeter4444
    @christopherpeter4444 6 років тому

    U r a life saver

  • @mcamaro7
    @mcamaro7 9 років тому

    Thank you

  • @preciousimemesi2472
    @preciousimemesi2472 Рік тому

    Thanks very much it's was very helpful

  • @nishanthapa7930
    @nishanthapa7930 7 років тому

    does a solubility curve of anhydrous solid always necessarily be continuous ?

  • @xpexcellent6165
    @xpexcellent6165 6 років тому

    If only all teachers were like this..

  • @sciencepost
    @sciencepost  11 років тому +1

    Vas, thanks for the feedback. Sooooo stoked they are helping you.

  • @Gamebot000
    @Gamebot000 7 років тому

    thank you so much

  • @kharerit888
    @kharerit888 10 років тому

    great vid!!

  • @tarviyaroyal
    @tarviyaroyal 10 років тому

    clear an simple, thanks!

    • @sciencepost
      @sciencepost  10 років тому

      Yeah! So cool to hear that the video worked for you. Be Awesome!

  • @maxweinstock729
    @maxweinstock729 8 років тому +1

    Thanks helped on Hw

  • @18pluss-teamuno
    @18pluss-teamuno 4 роки тому

    Great video for chemistry students.

  • @tatyelpana
    @tatyelpana 9 років тому

    Thank you now I will share with my students!

    • @sciencepost
      @sciencepost  9 років тому

      Eduardo Miranda Thanks bro. I hope that it helps them. Best wishes.

  • @mavic5784
    @mavic5784 3 роки тому

    Excellent video. Super helpful bro. Subscribed

  • @oliverzwiftzbiggeztfan
    @oliverzwiftzbiggeztfan 4 роки тому +2

    why he sound like Patton Sanders-
    (not in a bad way of course your voice is great)

  • @spencerirons3172
    @spencerirons3172 5 років тому

    Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.

  • @thornhillcrew
    @thornhillcrew 11 років тому

    thanks helped alot

  • @user-pz4ot6wn9w
    @user-pz4ot6wn9w 11 років тому

    thank you

  • @oyster9
    @oyster9 5 років тому

    thanks for help

  • @moe_sh9390
    @moe_sh9390 6 років тому +9

    I have a test on monday

  • @genivergarcia80
    @genivergarcia80 10 років тому

    Thanks this helped a lot! :)))

  • @123456asassin
    @123456asassin 9 років тому +1

    Subtitles would be awesome if you could start putting them on your videos.

  • @palgandhi5153
    @palgandhi5153 4 роки тому

    What if you were asked to a solution which is the least saturated at 20 degrees celsius with 20g of solute dissolved in 100g of water

  • @sciencepost
    @sciencepost  11 років тому

    You are welcome dude. Please share it if it helped. Peace out.

  • @sciencepost
    @sciencepost  11 років тому

    So stoked it worked for you! Tune back again.

  • @alexnervo
    @alexnervo 10 років тому +1

    i like how at 4:44 the amounts of solution are different. one is 33ml and one is 35ml.

  • @beezerwashingbeard2165
    @beezerwashingbeard2165 11 років тому

    ty

  • @clipsfan1996
    @clipsfan1996 11 років тому

    Well did

  • @tinatran4746
    @tinatran4746 7 років тому

    you're awesome

  • @J.Y_
    @J.Y_ 4 роки тому

    Btw, im not sure how legit the graphs are, but is it saying when water is 0 degrees Celsius (frozen into ice), it can still dissolve 175 grams of sugar???

  • @marxhamakhan1
    @marxhamakhan1 10 років тому

    Great Video!! =]

    • @sciencepost
      @sciencepost  10 років тому

      Thanks for tuning in and leaving feedback! Keep up the good work!

  • @zip9267
    @zip9267 7 років тому +1

    amazing video thanks alot

  • @dakshbrar565
    @dakshbrar565 5 років тому

    You didn't do any of the question my grade 11 teacher needs, but i understand a little better now