jake jensen If you only have 50mL of water which is half of the 100mL of water that is on the Y axis then you will need to cut the solubility at 100mL in half. For example if 30 grams of a salt are soluble per 100 mL of water at a given temp. then 15 grams of that salt will be soluble in 50mL of water. If you had 200mL of water then 60 grams of the salt would be soluble. Does that make sense?
It is not true that gram amounts above the curve are supersaturated. They are simply saturated. The more solid that is dissolved beyond the saturation point DOES NOT change the concentration of the solution and therefore, despite more solids on the bottom, the concentration of the solution is still simply - saturated. A supersaturated solution is a rare circumstance where a heated solution is saturated and allowed to cool so that more solids are dissolved than would normally remain in solution at that cooler temp. So in fact, a supersaturated solution will appear to be completely dissolved with no cloudiness or solids visible. But any agitation will quickly precipitate those solids out. Please stop teaching people that gram amounts above the line are supersaturated. They are not.
Im not exaggerating when I say my chemistry teacher won't teach me, so thanks for the video.
That’s most teachers these days
American education system be like
This helped me pass my chemistry test. Thanks for the help.
Glad it helped!
Your videos just get better and better! I am your biggest fan! Thank you Chem Academy!!! :)
THANK THANK YOU SO MUCH FOR CREATING THIS VIDEO!!!!!!!
thank you too much i have a test today
Same
Thanks so much, so much better than my teacher
Thank you!! I wish you were my teacher. My teacher goes super fast, you made this so easy!
FREAKING LEGEND YESSS NOW I CAN WRITE THE HONORS PART FOR MY TEST THANK YOU SO MUCH :)
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ANYONE 2020😂😂😂???
same
Moon Wolf same🤣
same moon wolf same
It's been 2 years already d4mn :(
wow, well understood thank you very much for the super chem teacher well done.
Learnt a lot thx
You should watch some grammar videos next 🤡
Very Helpful. Thanks for the Video
This video is very helpful.Thank you guys
Thank u sooooooooo much cause I was not understanding how the saturated, unsaturated n supersaturated work
Thank you for this video I have a test Tomorrow and this really help sense i was confused on this topic!
Cool, Thank you sir for such a comprehensive explanation.
This really really helped me do my assignment. Thankyou for the video sir
Thanks man u are a legend!
New video on Solubility Curves. SUBSCRIBE to my UA-cam channel if you like it.
This helped a lot! Thanks!! Happy Thanksgiving 🦃🍁
Life saver
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wonderful
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corona :(
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The symbol for cesium is Cs not Ce. The compound containig cerium is cerium (III) sulfate.
So let's say the solution is over saturated by 22 grams. Could you also add 22 mL of water to make it saturated?
why cerium sulphate solubility decreases with increase in temperature
It is a gas-liquid not a liquid-liquid or solid-liquid so it has to have a decrease in temp to increase solubility 😊
I am still having trouble on solubility in 50g. Could you please elaborate on that?
*mL
jake jensen If you only have 50mL of water which is half of the 100mL of water that is on the Y axis then you will need to cut the solubility at 100mL in half. For example if 30 grams of a salt are soluble per 100 mL of water at a given temp. then 15 grams of that salt will be soluble in 50mL of water. If you had 200mL of water then 60 grams of the salt would be soluble. Does that make sense?
Yes. Thank you.
I have a test right now
It is not true that gram amounts above the curve are supersaturated. They are simply saturated. The more solid that is dissolved beyond the saturation point DOES NOT change the concentration of the solution and therefore, despite more solids on the bottom, the concentration of the solution is still simply - saturated. A supersaturated solution is a rare circumstance where a heated solution is saturated and allowed to cool so that more solids are dissolved than would normally remain in solution at that cooler temp. So in fact, a supersaturated solution will appear to be completely dissolved with no cloudiness or solids visible. But any agitation will quickly precipitate those solids out. Please stop teaching people that gram amounts above the line are supersaturated. They are not.
Is it just me or does this guy sound a bit like technoblade??
Woah he kinda does
video se pehlay add bhoot boring......
Play fortnite
No
N-no
Thank you
thank you