Functions & Graphs in less than 26 minutes • A-Level Maths, Pure Year 2, Chapter 2 📚

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  • Опубліковано 4 січ 2025

КОМЕНТАРІ • 13

  • @Ani321-xy
    @Ani321-xy Місяць тому +1

    THANK YOU !!!! I HAVE MY MATHS MOCK ON MONDAY

  • @Gherkin
    @Gherkin Місяць тому +1

    Hi sir! Just wondering for the last question, if needed in an exam or just in general, what would be the easiest way to sketch these types of graphs? I always find it difficult to find the horizontal asymptotes in comparison to the vertical ones, sometimes there is also more than one horizontal asymptote and it just trips me up

    • @BicenMaths
      @BicenMaths  Місяць тому +1

      These kinds of graphs are actually very hard to sketch, and in an exam situation, I wouldn't confidently sketch this without my graphics calculator - you should make sure you can sketch the standard reciprocal type (1/x type). But this one is definitely more complicated!
      If you want to get better at graph sketching, there are probably some good UA-cam videos on it, but it is a very sophisticated topic that often comes up a lot in entrance exams for top universities!

  • @theopticalmaoam4938
    @theopticalmaoam4938 Місяць тому +3

    Jawad says thanks

  • @jefking2158
    @jefking2158 Місяць тому

    Sir if i have a modulus function and it has a y-intercept. Should i set x=0 for the negated or normal modulus to find that y intercept?

    • @BicenMaths
      @BicenMaths  Місяць тому

      It will depend on the particular function - so the best advice is just to sub x=0 into the modulus function, and if the part inside the modulus lines is negative, just make it positive and keep working it out! That'll then certainly give you the y-intercept. Hope that makes sense :)

  • @narutoedits4411
    @narutoedits4411 9 днів тому

    hello sir, in part c of the final question i got a different inverse function, x-1/3. However it also gave me the right answer of -2.. i was wondering can there be more than 1 inverse function?

    • @BicenMaths
      @BicenMaths  6 днів тому +1

      Hmm there can be different forms of the same inverse function, but they must be equivalent, and your function isn't equivalent to mine, so I think there must be an error there somewhere! (For example (1+x)/x is equivalent to 1/x + 1, so these could both be inverses for a different function, even though they look different!)

  • @belizerdogdu4825
    @belizerdogdu4825 15 днів тому

    Hi sir, sorry if I’m being a bit dumb but could you explain where the ‘-2’ came from? Thank you so much!

    • @BicenMaths
      @BicenMaths  13 днів тому

      I'm sorry, I'm not sure which part of the video you are referring to! Any chance you could share a timestamp to help me?

  • @MercGoBrrr
    @MercGoBrrr Місяць тому

    does this cover all types of questions they can offer, or should I go through the playlist? Thanks a lot for these videos, they really help

    • @BicenMaths
      @BicenMaths  27 днів тому +1

      It covers most, but definitely not all. It also doesn't really 'teach' all of these things, it is more designed to recap. So I would advise the playlist as your first approach, and then using these videos as a refresher! :)