STATICS OF RIGID BODIES : NORMAL AND TANGENTIAL COMPONENT OF FORCE:X & Y COMPONENT OF FORCE | PART 2

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  • Опубліковано 17 гру 2024

КОМЕНТАРІ • 15

  • @adaywithmay_01
    @adaywithmay_01 2 роки тому +4

    I think there's a mistake in the answer, in the first load(P), Pt should be 976.16lb not 966.19lb and also in the second load(F), the Ft should be 379.64 lb not 382.46lb.

  • @jhonathanduran1018
    @jhonathanduran1018 2 роки тому +1

    why is at 7:09 Pt= 966.19lb instead of 976.16lb
    ?

    • @casipecatherine8811
      @casipecatherine8811 2 роки тому

      whyy? have you answer it?

    • @adaywithmay_01
      @adaywithmay_01 2 роки тому +1

      Yes it should be 976.16lb not 966.19lb and also in the second load(F), the Ft should be 379.64 lb not 382.46lb

  • @isit.1264
    @isit.1264 3 роки тому +1

    the block shown in fig. p.223 is acted upon by its weight w= 200lb, a horizontal force Q = 600lb, and the pressure P exerted by inclined plane the resultant R of these forces is our and parallel to the incline thereby sliding the block up it. determine P and R hint. take one axis parallel to the incline....... thank you from the book of ferdinand singer 2nd ed. page 223 if okay for you can you please make a video for these to understand thank you

    • @abetutorials
      @abetutorials  3 роки тому +1

      Sure 🙂 I'll try uploading it tomorrow 🙂

  • @3110-l6n
    @3110-l6n 2 роки тому

    Why was the angle for solving load F same as the angle theta 49.4? Can you pleas explain how they are the same?

  • @nateman_
    @nateman_ Рік тому

    May playlist po kayo?

  • @ericagracesanchez2414
    @ericagracesanchez2414 2 роки тому +1

    Thank you!

  • @isit.1264
    @isit.1264 3 роки тому +3

    nakaka bilib yung way ng pag explaine pati way ng pag edit thanks for this nahirapan aku dito ehh sa topic na to pero nung napanood ku dito madali lang pala intindihin.