For those confused between property 1 and 3: These are essentially the same results. In the first property, we take definitive integral from -inf to +inf. In the second property, we take indefinite integral. Let's pretend we also take definitive integral in the second case, therefore: [u(t)] from -inf to +inf. u(+inf) - u(-inf) = 1 - 0 = 1 So the difference is that in the first property we take definite integral, in second - indefinite.
Sir, this video is very helpful for me. The way you have mentioned the impulse function, why the magnitude of impulse in discrete time is 1 at n=0 , whereas in continuous time it is infinite. Waiting for your valuable reply sir
I don't buy property 3. Yes the integral of the delta function is equal to 1, I concede that. However when you look at u(t), that is not always equal to 1, it's only equal to 1 for t > 0.
Sir can you upload the videos on opamps , oscilators and different timers circuit. Please sir read this comment and reply what you think on this. I really want this.
Doubt: At 4:40, Shouldn't the value of x(t) for t not equal to 0 be some value less the infinite? As per the waveform, we could see some value of x(t) for other values of t also.
Doubt plz respond ::::::: Sir as you said area=base×height(magnitude) At finnally that impulse becomes on x axis is zero so base is= 0 and respectively height ( magnitude) = infinete Then area =o×infinite=1( in case of impulse function ) how it is possible sir
Bro it does not zero its approching to zero and when it approches to zero as you see previously when decrease ę to half height increase by 2 times. Similarly when aproches to zero, width become so so small, height approches to infinity but we know when we integrate from -α to +α the area comes to be unity. Still not clear watch it again, he explained it very well. And example Width= 0.0000000000000000000000000000000000008 Than height will be 10^37 that almost infinity Multiply these two and get the answer
These are essentially the same results. In the first property, we take definitive integral from -inf to +inf. In the second property, we take indefinite integral. Let's pretend we also take definitive integral in the second case, therefore: [u(t)] from -inf to +inf. u(+inf) - u(-inf) = 1 - 0 = 1 So the difference is that in the first property we take definite integral, in second - indefinite.
Hello sir as per the definition we have Delta (t) =1for t=0 and it's value is 0 for other values of t, then in example you have taken a unit signal which has a value for t#0...please explain...
ramana polireddy hey when height of the pulse reaches at infinity our width tends to 0 so when we integrate our signal so we take limit from 0 to 0 as widht tends to 0 and consequently we know that when upper and lower limit are equal the resultant will be UNITY (1) . Hope you understand this .
If we time reversal the signal of impulse.. The time changes to -0. We don't have -0 and +0.so.. The signal present at zero itself. So.. There is no effect in doing time reversal
I dont understand the use of time scaling of impulse signal? and How can you create an impulse signal of certain area as you said strength because it changes the very meaning of impluse function?
For those confused between property 1 and 3:
These are essentially the same results. In the first property, we take definitive integral from -inf to +inf.
In the second property, we take indefinite integral.
Let's pretend we also take definitive integral in the second case, therefore: [u(t)] from -inf to +inf.
u(+inf) - u(-inf) = 1 - 0 = 1
So the difference is that in the first property we take definite integral, in second - indefinite.
Sir, this video is very helpful for me. The way you have mentioned the impulse function, why the magnitude of impulse in discrete time is 1 at n=0 , whereas in continuous time it is infinite. Waiting for your valuable reply sir
You didn't tell how you got the result in property 7 - the time scaling property. Please explain how you got that.
I don't buy property 3. Yes the integral of the delta function is equal to 1, I concede that. However when you look at u(t), that is not always equal to 1, it's only equal to 1 for t > 0.
Sir can you upload the videos on opamps , oscilators and different timers circuit. Please sir read this comment and reply what you think on this. I really want this.
ty for explaining the last property.
Thank you sir👍👍
thank you sir....
Thanks
thank you sir
Thank you
Doubt: At 4:40, Shouldn't the value of x(t) for t not equal to 0 be some value less the infinite? As per the waveform, we could see some value of x(t) for other values of t also.
Even I have this doubt. If you find, please reply here..
Doubt plz respond ::::::: Sir as you said area=base×height(magnitude)
At finnally that impulse becomes on x axis is zero so base is= 0 and respectively height ( magnitude) = infinete
Then area =o×infinite=1( in case of impulse function ) how it is possible sir
Bro it does not zero its approching to zero and when it approches to zero as you see previously when decrease ę to half height increase by 2 times. Similarly when aproches to zero, width become so so small, height approches to infinity but we know when we integrate from -α to +α the area comes to be unity. Still not clear watch it again, he explained it very well.
And example
Width= 0.0000000000000000000000000000000000008
Than height will be 10^37 that almost infinity
Multiply these two and get the answer
Hi, Please explain why property #1 and property #3 not having the same result. Thanks!
These are essentially the same results. In the first property, we take definitive integral from -inf to +inf.
In the second property, we take indefinite integral.
Let's pretend we also take definitive integral in the second case, therefore: [u(t)] from -inf to +inf.
u(+inf) - u(-inf) = 1 - 0 = 1
So the difference is that in the first property we take definite integral, in second - indefinite.
Thanks Sir🙏🙏
Hello sir as per the definition we have Delta (t) =1for t=0 and it's value is 0 for other values of t, then in example you have taken a unit signal which has a value for t#0...please explain...
Both Prop#1 and #3 are integration of impulse signal. #1 --> 1 while #3 --> u(t) ......????
the prop#3 used for Graphical Differentiation only ,while prop#1 used 4 mathematical calculation like integral stuff like dat
Thanks 😍
What is the derivative of impulse functions ??
Superb 😃
Sir how the amplitude scaling happened by doing time scaling in the last property
Nice
wouldn't be more practical if d[t] was defined to have 1 at 0 since is sampling?!
When signal height reaches to Infinity the width of that signal is 0 then area =∞ *0=0 then how area of impulse signal 1?
ramana polireddy hey when height of the pulse reaches at infinity our width tends to 0 so when we integrate our signal so we take limit from 0 to 0 as widht tends to 0 and consequently we know that when upper and lower limit are equal the resultant will be UNITY (1) .
Hope you understand this .
yes
What is the limit 0 to 0 does it make sense...
forget all,understand 1/infinity(that is the width ,very small)*infinity=1
The width tends to zero but exactly zero
Didn't get property 7
how the prop#5 can be true while the area are equal to 1
Sir impulse signals are nenp but unit impulse signals are what?
Sir please upload all the videos quickly
there is no effect of time reversal on impulse signal
, why?
because the signal is only present at 0. And there is no reversal of time at t=0
If we time reversal the signal of impulse.. The time changes to -0. We don't have -0 and +0.so.. The signal present at zero itself. So.. There is no effect in doing time reversal
@@gouthamivaligonda what happens if the signal is time shifted and then time reversed?
@@Lucky-wi6or there is effect
@@gouthamivaligonda can U also explain the 3rd property and 7th property graphically?
I dont understand the use of time scaling of impulse signal? and How can you create an impulse signal of certain area as you said strength because it changes the very meaning of impluse function?
Can we say 0 × ∞ = 1
Nope.. Actually 0×infinity is an intermediate form. So, the resulting value may be zero or ♾️
🙏🙏
who studies in INELEC and came to watch this video like my comment
broooooo xd
9:20 why not A.[u(t)-u(-t)] ??
thanks