1:40 I don't understand why the dirac delta function's height can be understood as "1 divided by epsilon", in the case when epsilon is not the width, but instead the width divided by 2 (or the width on just one side of the y axis). If epsilon were to be 1, even if it is to ideally approach zero, 1 / 1 would be 1 (great, normal dirac), but in reality the width of the visual would extend 1 (epsilon) in the +x direction and 1 in the -x direction, making the width 2, making the integral of the dirac delta into 2. Just a little confused about why the visual is the way it is that accompanies the "1 divided by epsilon" definition.
From the playlist, watch the Laplace Transform videos in a sequence, it will get clear to you. Here is the link: ua-cam.com/play/PLwjK_iyK4LLD8Cdj0SKiMZFoK2d3eE6v2.html&si=A_uMAlNmubeqC9AX
For more videos on Network Analysis, check this playlist : Network Analysis
ua-cam.com/play/PLwjK_iyK4LLBN9RIDQfl9YB4caBYyD_uo.html
You are the Best you really explain things in understandable way
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Amazing ...
1:40 I don't understand why the dirac delta function's height can be understood as "1 divided by epsilon", in the case when epsilon is not the width, but instead the width divided by 2 (or the width on just one side of the y axis). If epsilon were to be 1, even if it is to ideally approach zero, 1 / 1 would be 1 (great, normal dirac), but in reality the width of the visual would extend 1 (epsilon) in the +x direction and 1 in the -x direction, making the width 2, making the integral of the dirac delta into 2.
Just a little confused about why the visual is the way it is that accompanies the "1 divided by epsilon" definition.
Which software you use to make the presentation ?
Electrical engineering 1st year.. Suffering from Laplace 😢
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Explanation is not clear!
From the playlist, watch the Laplace Transform videos in a sequence, it will get clear to you.
Here is the link: ua-cam.com/play/PLwjK_iyK4LLD8Cdj0SKiMZFoK2d3eE6v2.html&si=A_uMAlNmubeqC9AX