41 - Proof: Gamma prior is conjugate to Poisson likelihood

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  • Опубліковано 7 вер 2014
  • This video provides a proof of the fact that a Gamma prior distribution is conjugate to a Poisson likelihood function.
    If you are interested in seeing more of the material on Bayesian statistics, arranged into a playlist, please visit: • Bayesian statistics: a... Unfortunately, Ox Educ is no more. Don't fret however as a whole load of new youtube videos are coming soon, along with a book that accompanies the series: www.amazon.co.uk/gp/product/1... Alternatively, for more information on this video series and Bayesian inference in general, visit: ben-lambert.com/bayesian-lect... For more information on econometrics and Bayesian statistics, see: ben-lambert.com/

КОМЕНТАРІ • 14

  • @xochdt
    @xochdt 2 роки тому +1

    This was uploaded 7 years ago, yet it's still saving carees. Thank you so much.

  • @toishiki
    @toishiki 8 років тому +1

    Thank you sooo much!! Very clear!

  • @isyakumuhammad6982
    @isyakumuhammad6982 4 роки тому +1

    thank you very much , this is a very clear video.
    could you please provide me a link the explain an inverse Gaussian distribution with power normal prior.
    thanks.

  • @marlonkakurira9931
    @marlonkakurira9931 4 роки тому

    Well understood. Many thanks!!!

  • @alessandro64484
    @alessandro64484 9 років тому

    hi, i have a question: is it possible to compute the joint distribution of the poisson? π(lambda,X1,...,Xn)?

  • @S4N0I1
    @S4N0I1 5 років тому +2

    i love you for this

  • @danielmburu6936
    @danielmburu6936 8 років тому

    wow thanks so much for the info

  • @RobertoMartin1
    @RobertoMartin1 9 років тому +1

    That was excellent

  • @jemimanamale4447
    @jemimanamale4447 2 роки тому

    At 1:23 should the it be x^a-1? I’m seeing different resources using either x or lambda

  • @ediltonbrandao8407
    @ediltonbrandao8407 Рік тому

    thnks from Brazil

  • @lemyul
    @lemyul 4 роки тому

    thakns for sketching out

  • @mashhoodahmad6101
    @mashhoodahmad6101 3 роки тому

    Dear Sir Please tell how we will deal with if summation (1 to N)(theta -x) as you told summation (1 to N)(X)=N.Xbar

    • @choendenkyirong8313
      @choendenkyirong8313 3 роки тому

      I think you'd just simplify as such:
      sum( theta - x_i ) = sum(theta) - sum(x_i) = n*theta - n*xbar = n(theta - xbar)

    • @mashhoodahmad6101
      @mashhoodahmad6101 3 роки тому

      @@choendenkyirong8313 Thankyou so much Sir