A Fun Functional Equation

[@surendrakverma555]

Very good. Thanks 🙏

[@MathTrick-t7v]

Amazing

[@dsamaey]

x/(x-1) is an involution (its own inverse)

[@ronbannon]

A novel twist is to find all integers that satisfy this functional equation. Both f and x must be integers. The only solutions are (2, 2) and (0, 0).

[@Speak22wastaken]

I think you may have misunderstood the question

[@maherom1]

I propose this équation
[6x^2 + 5x] = 6x ^ 2 + 6x + 1

[@tunistick8044]

tu blagues là?

[@mircoceccarelli6689]

f( x ) = ( 1/3 )( 2x - 1 ) g( x )
g( x ) = x/( x - 1 ) , x =/= 1
👍😁👋