A Nice Math Olympiad Exponential equation | How to Simplify Olympiad problem?
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- Опубліковано 31 гру 2024
- A beautiful ❤️ Math Olympiad Exponential equation
Secret of Olympiad mathematics
"Unlock the secrets of exponential equations with this deep dive into a challenging Math Olympiad problem! Whether you're a math enthusiast or prepping for your next competition, join us as we break down this complex equation step by step. Learn the strategies, tips, and tricks that will help you solve exponential problems with ease. Perfect for students aiming to ace their exams and for anyone who loves the beauty of mathematics. Don’t miss out on this mathematical adventure!"
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3(27^x) = 27, 27^x = 9, 3^3x = 3^2, 3x = 2; x = 2/3
3(3^3x) = 3^3, 3^(3x + 1) = 3^3, 3x + 1 = 3, 3x = 2, x = 2/3.
3.27^x=27
27^x=9
3^3x=3^2
3x=2
x=2/3
Solution:
27^x+27^x+27^x = 27 ⟹
3*27^x = 27 |/3 ⟹
27^x = 9 ⟹
3^(3x) = 3² |because of the same base: 3x = 2 |/3 ⟹ x = 2/3
You did for 3 minutes in more steps.but requires 3 steps 30 seconds time.
27^x = 9
3^3x = 3^2
3x = 2 ( powers are same
when bases are same)
x = 2/3 is the answer.
x=2/3
2/3
27ⁿ+27ⁿ+27ⁿ=27
3(27ⁿ)=27
27ⁿ=9
3³ⁿ=3²
3n=2
n=⅔ ❤
Too easy, I did it in my head,
Very long-winded method
2/3
X=2/3
x=2/3
2/3
X=2/3