Any time you come across this kind of question were it ask us to solve for X but our X is power always make the base equal so that you can equate the power and solve for X.
As I see there is a misprinting of equation. If only the √ is moved to the right hand side of the equation with the greater number, then by replacing the value of x with 9 we can get both sides equal. As 2^9 =512 and √9 is 3. Hence, 8^3 =512.
An alternate solution for final answer once you have X = 9 * (X ^ 2) X / 9 = X ^ 2 (X / 9) / X = (X ^ 2)/X divide both sides by X 1/9 = X X = 0 second value assumed by inspection
Very nice but it would have been best if he had verified the answer 1/9 because the square root of an exponent is a little unusual. v1/9 = 1/3 2^1/3 = (2^3)^1/9 2^1/3 = 2^3/9 2^1/3 = 2^1/3
You do know though that everytime you square an unknown you lose a solution? This also the same reason why we don't "cancel out " unknowns. the solution we lose from squatng the unknown is -1/9 . if we let y = x^0.5 instead, we solve this as a quadratic equation without losing the solution. Forgive me I'm a purist I mean no harm.
Before watching: First and foremost, x=0 gives us 2^0=8^0 -> 1=1, so x=0 is a solution. Are there others? Well, 8 =2^3, so the right hand side can be written as 2^(3x). We now have the same base raised to two different powers equal to one another; this can only work if the powers are equal. Thus we have Sqrt x = 3x. Square both sides... X = 9x^2 Divide each side by 9x to get... 1/9 = x Our solutions thus, are x=0 and x=1/9.
Explaination:First better you (X^√X).have on LHS. By squaring this LHS you have 2 becoming 4. Then √X becomes X. So on LHS you have 4^X. Now take the RzHS. RHS is 8×X. If you square this it becomes 64X^2. Now in RHS you can write 64 as 2×2×2×2×22.=64. So RHS is 2^6×X^2. Now both LHS and RHS have the same base as 2. So you 2X=6X^2. Cancelling one X on both sides You get 2=6X. So Xus 2/6.
I have liked it sir thanks.
Good explanation sir , keep it up, thanks 👍👍👍
Any time you come across this kind of question were it ask us to solve for X but our X is power always make the base equal so that you can equate the power and solve for X.
Please can you be my teacher
thanks for teaching sir
Fantastic! I suggest if possible do for us long videos such like question in collections
Try taking the natural log of both sides: √x*ln2=x*ln8; x=(ln2/ln8)^2=1/9
Check: 2^(1/3)=8^(1/9)=∛2
As I see there is a misprinting of equation. If only the √ is moved to the right hand side of the equation with the greater number, then by replacing the value of x with 9 we can get both sides equal. As 2^9 =512 and √9 is 3. Hence, 8^3 =512.
Simple...Excellent
You're a good teacher sir
Always you are the best teacher ❤
Excellent presentation
❤well done 👍
3x = √x
9x² = x
9x² - x = 0
x(9x - 1) = 0
x = 0 or
x = 1/9
Full support from India 🇮🇳
Clear information sir thank you 😊
An alternate solution for final answer once you have X = 9 * (X ^ 2)
X / 9 = X ^ 2
(X / 9) / X = (X ^ 2)/X divide both sides by X
1/9 = X
X = 0 second value assumed by inspection
I think you should divide by two both sides to end them and then continue that makes more sense
I really enjoyed it... Thank you so much
Thanks sir for teach
Thanks you sir
Good evening sir,I have worked out x= 0,1/9answer sharing
Sir there is a quicker and easier method
3x=√x
3= √x/√x×√x
3=1/√x
3√x=1
9x=1
X=1/9
Thank you for teaching me
Nice explanation 👌 👍 👏
I'm understanding
Very nice but it would have been best if he had verified the answer 1/9 because the square root of an exponent is a little unusual.
v1/9 = 1/3
2^1/3 = (2^3)^1/9
2^1/3 = 2^3/9
2^1/3 = 2^1/3
Thanks sir, it came at the right time
Thanks sir , keep up
Thanks.....I understand
Thank you so much easy and understandable
I do appreciate sir
Or just take log base 2 on both sides
1/9, 0
Easy but genius thanks
Excellent work
Correct sir👍
Thank you very much sir 🙏
Good one sir❤❤
Exponent and Power are two different things.
Easy and understandable
Instead of using quadratic equations, we can also use indices to arrive at the same answer.
I would like to know how x=9x² can be solved by indices
Talk about complicating life . How do u use Indices with quadratic equations!?
Think you, it's helpful
Top. Excelente aula.
.
Thank you so much Sir
That's great thanks
Great job
Well done 👍✅
It's understandable
Thanks alot sir that was great. May you please solve for me this: 4X^3 -X^2 -58X +60=0
x=
4
1
−
3
(
64
9801
+
16
3
1766271
i
)
1/3
−
16(
64
9801
+
16
3
1766271
i
)
1/3
235
Please use factor theorem to solve for x its much easier that way.
I get yo point sir
I like this equation
Bom vídeo.
Thank you sir l can now do it my self thanks again ❤
Nice 👍 solution
Thank you very much
3 determines how many times 2 multiply by itself to get 8
Thank you sir
Well understood
x-9x^2=0 is a 2nd order equation and needs 2 answers, x=0 and x=1/9.
2^√x = 8^x = 2^(3*x)
√x = 3*x
√x*(1 - 3*√x) = 0
√x = 0, 1 = 3*√x
x = 0, 1/9
Wonderful
Thank you
Correct sir
Very very nice
X=0 etX=1/9
negative 8 =o it's not easy to solve without a specific domain.
We're young just suppose to square root 3x then cancel out in both sides🤨🤨🤨
Pls sir l need a video on modular arithmetics
You do know though that everytime you square an unknown you lose a solution? This also the same reason why we don't "cancel out " unknowns. the solution we lose from squatng the unknown is -1/9 . if we let y = x^0.5 instead, we solve this as a quadratic equation without losing the solution. Forgive me I'm a purist I mean no harm.
The solution is okay
Take log on both the sides , and enjoy .
This three in equation where come from?😮
It's good 😅
Greatest
X=0 and X =1/9
After solving,x=0,1/9
Thanks ❤❤
Great
Mathematics is good 😊😊
I am from India but I like a video ❤❤❤❤
Neden beğenmeyesin ki? Matematik dünyanın her yerinde aynı ve senin milliyetinle bir alakası yok. Ucube😂
Sir thank but my sir solve this in 10 second and in easy way 😅😅
THIS WAS TOO MUCH EASY!
Yeah I solved it in my head in 5 seconds 😅
I dont understand because you multiplied 3x to the power of 2 but after getting the answer the power still remains why
Before watching:
First and foremost, x=0 gives us 2^0=8^0 -> 1=1, so x=0 is a solution. Are there others?
Well, 8 =2^3, so the right hand side can be written as 2^(3x). We now have the same base raised to two different powers equal to one another; this can only work if the powers are equal. Thus we have
Sqrt x = 3x.
Square both sides...
X = 9x^2
Divide each side by 9x to get...
1/9 = x
Our solutions thus, are x=0 and x=1/9.
Thank you best ❤❤❤
Explaination:First better you (X^√X).have on LHS. By squaring this LHS you have 2 becoming 4. Then √X becomes X. So on LHS you have 4^X. Now take the RzHS. RHS is 8×X. If you square this it becomes 64X^2. Now in RHS you can write 64 as 2×2×2×2×22.=64. So RHS is 2^6×X^2. Now both LHS and RHS have the same base as 2. So you 2X=6X^2. Cancelling one X on both sides You get 2=6X. So Xus 2/6.
Am enjoying ba sir❤❤❤
❤
Existe alguna aplicación práctica de estas ecuaciones?
Ó solo son teorías complicadas?
X= 1/9 or X=0
You are ✅️
@@AjaysahSahu your teaching is good 👍
Nice
i am watching it right now
It clear
Getting the square root doesn't mean you square a number but instead raise it to one half
OBRIGADO TEACHER. ENTENDI!
Thanks
2 cube =8 and when we shift root symbol from one side to the another it turns to square
Thanks
👍🏻
9x^2
Terima kasih
otjiperi means thats it
Thanks you sir I will appreciate