This video is great! I'll definately use it as a reference the next time I have to select a gate driver! Just one thing that I think you may have forgotten to mention. If you put a 0 Ohm resistor with a diode in parallel with the gate resistor, this would allow the gate to turn off much quicker by providing the current with a quicker path to ground.
Thanks for the considerations. I was going by damping spikes and thought 'uncle bully is yr uncle.' Found spikes cleaned @ 100 ohms. Now I have a better idea of why mosfets heating even though using driver. Saw capacitor leads glowing red hot literally with inductor circuit. Frequency too high.
Thank you bros ur awesome. one more thing sir please can you make a video on how to make a gate drive transformer coiling nd how to control an overheating mosfet thank sir
Unfortunately, I don't think you have quite grasped how the output of a gate driver works. The output side of a gate driver like the IR2110 when driving low-side utilises a ground (COM = pin 2) and a supply (Vcc = pin 3). There is no provision for a negative supply to drive the gate below the common ground on that chip. The on-state output voltage will be Vcc (which can be in the range 10V to 20V) and the off-state output voltage will be 0V, which is the common ground voltage between the gate driver and the switching mosfet/igbt. So in your example starting at 2:19 there is no "Vee" pin and there is no -10V relative to the mosfet/igbt ground to turn it off. The output swing is what you supply to Vcc and that determines the minimum gate resistor.
I have a big question can I use emitter follower to every igbt in and 15kw inverter to help increase current to the gate say 1.5 amp to each gate so I have 24 igbt so for everything igbt 1.5 to everyone so I would give 36 amp to the entire 4 channel is it possible
The explanation is very slow and steady with some thesis, very helpful, but I have a question, from gate driver, the MOSFET/IGBT is voltage driven switch and we don't expect any current (like 1A with voltage 10V) that is depicted in the video... some confusion about this, could you help with this?
So, if the gate driver has the capability of being short-circuited the lowest external gate resistor value is 0? I built a boost converter a few months ago which uses no external gate resistor with a 5A capable gate driver. At the mosfet gate there is a gate ringing of 11Vpeak ~200MHz at turn off. As I don't care about EMI on personal projects, are there any other concerns with this? (11Vpk is within the allowed +-20V at the gate). It already works flawlessly for >1000h of runtime with no problems and even achieves ~97% efficiency.
If the gate driver is rated for repetitive short circuit, then its internal resistance is enough to limit its drive to 5A and you can roughly estimate that from Ohm's Law. If it works okay for you and you don't carea bout EMI, then there are no other considerations for you. The ringing is a damped oscillation caused by the series LCR resonant circuit formed by the driver output, the connection to the mosfet, the mosfet's gate capacitance and the returm path from the mosfet source to the driver ground. Since it resonates at 200MHz and a mosfet has a typical gate capacitance of perhaps 2nF, that implies a parasitic inductance of around 0.3μH. To critically damp the oscillation you need a resistance of 2√(L/C) = 0.8Ω. I'd add that small amount just for piece of mind.
What do you mean by "let's say we need 10v to turn it on and -10v to turn it off efectively"? isn't the voltage at vee 0v or in other words ground, instead of -10v?
@@SanGon0703 You need to check the specification. Some mosfets have GS voltage +-12 Volt, some +-20 Volts. You only need to go below zero if a short duration of MOSFET on when it shall be off is a disaster.
Bro, Can you make a Setup with One High Voltage Power Supply, One Oscilloscope, And Half Bridge circuits with One Inductor as a Load..... Using this You can show Proper Results to us (Viewer's)
Your video is just speaking.in this video I expect to formula and all thing definitely to be expressed.but nothing.just speaking and two formula.?????!!!!
Thanks bro for taking your time to make this video . much appreciated
This video is great! I'll definately use it as a reference the next time I have to select a gate driver!
Just one thing that I think you may have forgotten to mention. If you put a 0 Ohm resistor with a diode in parallel with the gate resistor, this would allow the gate to turn off much quicker by providing the current with a quicker path to ground.
Excellent explanation. Thank you very much.
You are welcome!
Thanks for the considerations. I was going by damping spikes and thought 'uncle bully is yr uncle.' Found spikes cleaned @ 100 ohms. Now I have a better idea of why mosfets heating even though using driver. Saw capacitor leads glowing red hot literally with inductor circuit. Frequency too high.
It's not foolish engineering it's the most powerful engineering ❤
Thank you very much for the detailed answer!
You are welcome!
WAO..! Very Well And Number one for me..❤️❤️❤️👬👍👬❤️❤️❤️
Many many thanks
You follow Great Scott good
Hii sir Please Do one video on ferrite bead selection process for EMI suppression...
You can also calculate the dq/dt from the datasheet, you have dv/dt and the Gate capacitance
Great Video!
Great video and very well explained. Ill have to check out your other ones. Cheers
That’s great!
Beautiful explanation. Thank you
Sir, your explanations are very useful for my project & animation is very impressive. from which software do you make animation.
Thank you bros ur awesome. one more thing sir please can you make a video on how to make a gate drive transformer coiling nd how to control an overheating mosfet thank sir
Look up double pulse testing! It's a test to find out all sorts of useful switching characteristics for switching devices
Unfortunately, I don't think you have quite grasped how the output of a gate driver works. The output side of a gate driver like the IR2110 when driving low-side utilises a ground (COM = pin 2) and a supply (Vcc = pin 3). There is no provision for a negative supply to drive the gate below the common ground on that chip. The on-state output voltage will be Vcc (which can be in the range 10V to 20V) and the off-state output voltage will be 0V, which is the common ground voltage between the gate driver and the switching mosfet/igbt. So in your example starting at 2:19 there is no "Vee" pin and there is no -10V relative to the mosfet/igbt ground to turn it off. The output swing is what you supply to Vcc and that determines the minimum gate resistor.
What are the tool you are using for circuit representation?
I have a big question can I use emitter follower to every igbt in and 15kw inverter to help increase current to the gate say 1.5 amp to each gate so I have 24 igbt so for everything igbt 1.5 to everyone so I would give 36 amp to the entire 4 channel is it possible
Your every videos are very informative. Kind make a video on snubber design in SMPS supply.
Sure I will
Hi ,I have 2x faulty 90n33 igbt,is it possible I change with 2x 40n60 igbt only ones I got...ta Steven , 4:52 png.
Great informative video
Exillent sir
Please make a video on feedback circuit to measure and control output voltage and current
Thank you so much
The explanation is very slow and steady with some thesis, very helpful, but I have a question, from gate driver, the MOSFET/IGBT is voltage driven switch and we don't expect any current (like 1A with voltage 10V) that is depicted in the video... some confusion about this, could you help with this?
due to the charging of input capacitor very high amount of current can flow for short time
So, if the gate driver has the capability of being short-circuited the lowest external gate resistor value is 0?
I built a boost converter a few months ago which uses no external gate resistor with a 5A capable gate driver. At the mosfet gate there is a gate ringing of 11Vpeak ~200MHz at turn off. As I don't care about EMI on personal projects, are there any other concerns with this? (11Vpk is within the allowed +-20V at the gate). It already works flawlessly for >1000h of runtime with no problems and even achieves ~97% efficiency.
If the gate driver is rated for repetitive short circuit, then its internal resistance is enough to limit its drive to 5A and you can roughly estimate that from Ohm's Law. If it works okay for you and you don't carea bout EMI, then there are no other considerations for you.
The ringing is a damped oscillation caused by the series LCR resonant circuit formed by the driver output, the connection to the mosfet, the mosfet's gate capacitance and the returm path from the mosfet source to the driver ground. Since it resonates at 200MHz and a mosfet has a typical gate capacitance of perhaps 2nF, that implies a parasitic inductance of around 0.3μH. To critically damp the oscillation you need a resistance of 2√(L/C) = 0.8Ω. I'd add that small amount just for piece of mind.
@FoolishEngineer, first link from references doesn't work. Could You fix it ?
I have updated the link. Please check now
Please upload how to make input emi emc circuit
Sir you teach electronics i want
Sir your video is top but make video two tipes Hindi and English thankyou sir ji
We will try
@@FoolishEngineer thankyou sir ji
Tq sir ❤
What do you mean by "let's say we need 10v to turn it on and -10v to turn it off efectively"? isn't the voltage at vee 0v or in other words ground, instead of -10v?
It depends, its of at 0 but there may be noisy signals and other issues. Sometimes it will not matter. If you want to be sure drive it below zero.
@@xehpuk Thanks for your reply! Sorry for my ignorance, I have a +12v battery how can I drive the MOSFET with, for example, -12v?
@@SanGon0703 You need to check the specification. Some mosfets have GS voltage +-12 Volt, some +-20 Volts. You only need to go below zero if a short duration of MOSFET on when it shall be off is a disaster.
How drive two pic igbt module circuit dayagram for h brize run for 5kw sinewave inverter transformer
Bro, Can you make a Setup with One High Voltage Power Supply, One Oscilloscope, And Half Bridge circuits with One Inductor as a Load.....
Using this You can show Proper Results to us (Viewer's)
Working on it!!!
Why would we use a gate resistor as opposed to a pull down resistor from gate to drain?
Nice
Thanks
Subtitles cover the background words ....so irritating 😵
Calculate? Just put 10R and continue.
😂 right
sir. bleeder.rasister.value.calculation.sir
Hindi bhi aati h ya nhi bhai
Ati bhi hoto tuze kyu batau?
Your video is just speaking.in this video I expect to formula and all thing definitely to be expressed.but nothing.just speaking and two formula.?????!!!!