Spectrophotometry | Beer-Lambert Law.

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  • Опубліковано 22 лип 2024
  • This video is about Spectrophotometry, and discusses in details the Spectrophotometer and Beer-Lambert's law.
    In this video I discuss the relationship between the absorbance and the concentration:
    - A=epsilon x l x c
    - how to determine experimentally the molar absorptivity
    - find the concentration of an unknown solution.
    You can also watch an experiment using the Beer-Lambert law:
    • AP Chemistry Investiga...
    Students studying Chemistry at different levels could highly benefit from this video.

КОМЕНТАРІ • 95

  • @AliHayek
    @AliHayek  6 років тому +50

    I hope you find this video helpful. Please note that the answer at 5:25 is 5.0 x 10^(-3) and not 5.0 x 10^(-2) as it is shown in the video. The preparation for such videos takes lots of time and sometimes small mistakes like this slip easily. Enjoy!

  • @jackyllerena5336
    @jackyllerena5336 6 років тому +30

    Woah, everything was so clear. This video is those kinds of videos where you can pause on a certain time and have all the information you need neatly placed with explanations and everything.
    Thanks man :D

  • @1babyflix
    @1babyflix 6 років тому +5

    Really clear and easy to follow explanation. Good job.

  • @dr.pratikk8930
    @dr.pratikk8930 4 роки тому

    Best video on Beer lamberts law...
    Thanks
    And keep making such videos

  • @md.ibrahimkhalil6011
    @md.ibrahimkhalil6011 6 років тому +1

    Nice informative video. Thank you very much for sharing with us.

  • @michaelseraphim1056
    @michaelseraphim1056 2 роки тому

    You really saved my life. God bless your heart . Thank you so much for sharing your brilliant knowledge 😊 🙏

  • @marzenasemaj7204
    @marzenasemaj7204 Рік тому +1

    You explained it really fast and clear. Thank you for this video it will help me in a labolatory!

  • @karanmakwana5129
    @karanmakwana5129 5 років тому +2

    Thank you so much I was facing problems in this topic but now all is clear

  • @EJ-qs6qh
    @EJ-qs6qh 5 років тому

    fantastic!! thank you. very clear and perfect pacing.

  • @MrAbdalla1996
    @MrAbdalla1996 6 років тому +1

    THANK U VERY MUCH
    THE DIAGRAM WITH DESCRIBTION IS VERY USEFUL

  • @SquatBenchDeadliftz
    @SquatBenchDeadliftz 5 років тому +1

    Very helpful video. Easy to understand. Thanks.

  • @Isaac-ru5jb
    @Isaac-ru5jb 6 років тому +1

    Really good video! helpful and informative and easy to understand, really good job! thank you so much!:)

  • @sajamas5766
    @sajamas5766 7 років тому +1

    راااائع جد..نريد المزيد من الفيديو

  • @jeevaniroyal8407
    @jeevaniroyal8407 5 років тому +1

    Gud lecture sir gathered more information

  • @aayataltamimi9325
    @aayataltamimi9325 6 років тому +1

    Amazing explanation. Thanks a lot!

  • @shivammkhare
    @shivammkhare 5 років тому +5

    I am watching this in 2018, you are really great Sir, Good explanation, you deserve million subscribers but it's sad nowadays people wants to watch only Crap, youth is destroying their Time & Career.

  • @khinmyatthu9289
    @khinmyatthu9289 Рік тому

    Thank you very much. It is really appreciated.🙏

  • @KulbirAhluwalia
    @KulbirAhluwalia 6 років тому +2

    Awesome video sir! Thank you!

  • @shrishantroy2494
    @shrishantroy2494 3 роки тому +1

    Wow. Great explanation

  • @niranjanavadivel7388
    @niranjanavadivel7388 6 років тому

    Nice explanation Ali Hayek

  • @dancemabu6341
    @dancemabu6341 7 років тому +1

    very good my man,u explain nicely

  • @shubhambhosale4723
    @shubhambhosale4723 6 років тому +2

    Good one bro

  • @tiibrahim5714
    @tiibrahim5714 6 років тому +1

    Wow! I really appreciate it Sir

  • @jamespandiannaraj5744
    @jamespandiannaraj5744 5 місяців тому

    Excellent lecture

  • @mohammedabdalla8077
    @mohammedabdalla8077 Рік тому

    Nice and very useful

  • @adanalvarez6830
    @adanalvarez6830 4 роки тому

    dude please make more chemistry videos.... every second of the video had a purpose.

  • @ramamukumbi5566
    @ramamukumbi5566 7 років тому +3

    man you do a good job thx
    keep up good work ;)

  • @rabiadegia4361
    @rabiadegia4361 6 років тому +1

    lovely explanation thank you!

  • @loyalty6495
    @loyalty6495 3 роки тому +1

    The explanation was helpful, thank you

  • @dannyjean-noeluppiah8270
    @dannyjean-noeluppiah8270 3 роки тому

    Great explanation! 👍🙏🙏

  • @TemeraireBjartskula
    @TemeraireBjartskula 6 років тому +1

    I have a test about this next week and truth to be told, I did not understood a thing about it, this video helped me to clear it all up so thank you for taking the time to make this. It was really helpful!

    • @AliHayek
      @AliHayek  6 років тому +1

      +LuciferHasPinkSparklyWings you are more than welcome.

  • @debasishmajhi687
    @debasishmajhi687 6 років тому +1

    Video was very helpful sir thx a lot

  • @manuelperezruizdiaz9418
    @manuelperezruizdiaz9418 6 років тому +1

    thanks, that's was great it was very helpful

  • @anastaciamodo8273
    @anastaciamodo8273 5 років тому +1

    well presented Shukran

  • @tarkeshkandregula6559
    @tarkeshkandregula6559 7 років тому +2

    thank u so muchh.. such a good video :)

  • @adeelbashir5847
    @adeelbashir5847 6 років тому +1

    nice work sir

  • @oumarshah1335
    @oumarshah1335 2 роки тому

    Outstanding

  • @TheDina132
    @TheDina132 3 роки тому +1

    Thank you! It s so easier!

  • @samscience444
    @samscience444 5 років тому

    helpful video thaaaaaank you so much

  • @edusmart1126
    @edusmart1126 5 років тому

    thanks, you are really great sir

  • @Starwave...3821
    @Starwave...3821 6 років тому +1

    Very good video

  • @sylviaemejuru1956
    @sylviaemejuru1956 4 роки тому

    Thank you very much Sir

  • @binteabdul6107
    @binteabdul6107 5 років тому

    tx for uploading very helpful

  • @piyushsen7502
    @piyushsen7502 5 років тому

    Thanx bro it really helpful

  • @domlehane2819
    @domlehane2819 7 років тому +1

    thank you very much mate!

  • @fatimasaleh9301
    @fatimasaleh9301 5 років тому

    Love this video

  • @pseudomonas69
    @pseudomonas69 6 років тому +1

    bruh you deserve an emmy for this vid

  • @shadowwhitehart9190
    @shadowwhitehart9190 6 років тому +5

    Time point 5:33, I think there is a mistake: 0.5 and not 5.0

  • @aashnagurjar2477
    @aashnagurjar2477 6 років тому +2

    thnq so much sir

  • @lamp1215
    @lamp1215 6 років тому +1

    JazakALLAH

  • @noorikhan2974
    @noorikhan2974 5 років тому

    Thank u so much sir

  • @mustaphaaliyumuhammad4656
    @mustaphaaliyumuhammad4656 2 роки тому

    thank you sir

  • @jeevaniroyal8407
    @jeevaniroyal8407 5 років тому +1

    Gud lecture sir and I have few queries regarding biotechnology

  • @khinmyatthu9289
    @khinmyatthu9289 Рік тому +1

    Hello Dr. Hayek,
    Thank you very much for this video. The explanation is clear, well-organized, and getting on point, which helps me a lot. I have a few questions. Is there any chemical relation between the concentration of the samples and the incident light emitting or absorbing? I am getting unstable absorbance values with measurements at low concentrations but not at high concentrations. This finding is also beyond the understanding of Absorbance = logarithms of transmission though my values are at 0.1% of T. or could you please enlighten me on the keywords I could find for the articles? Thanks a lot.

    • @AliHayek
      @AliHayek  Рік тому

      Hi there,
      Light-matter interaction is a known phenomenon. Sometimes it does not affect the structure of the matter, but some other times light can be aggressive and provides enough energy to break weak bonds. If the absorbance is not stable or keeps changing, it could be that the light is transforming the matter into something that interacts less/more with light. It is a broad topic. I hope this will allow you to start your search. Best of luck.

  • @nick1f
    @nick1f 6 років тому

    Is I0 actually the intensity of light as read by detector when a sample of pure solvent (water) is placed in the cuvette?

    • @AliHayek
      @AliHayek  6 років тому

      Nick F yes it is indeed. And this is called the blank and it is used for the background noise correction.

  • @abdullahshahnawaz6585
    @abdullahshahnawaz6585 5 років тому

    Thank you

  • @esraatarek953
    @esraatarek953 3 роки тому

    Thanks very much for this helpful video.
    But I wanna ask about the references, please?

  • @bharathibharathisekar484
    @bharathibharathisekar484 3 роки тому +1

    Tq,sir

  • @tharunstar1554
    @tharunstar1554 5 років тому

    Super

  • @yogitavarshney3268
    @yogitavarshney3268 6 років тому

    Please upload beer law for mixture

  • @isaiaharchibald4438
    @isaiaharchibald4438 7 років тому +7

    great video but the answer is 5.0 x 10-3 not 5.0 x 10-2. the video really help me thanks btw.

    • @debasishmajhi687
      @debasishmajhi687 6 років тому

      WATCHDATFREE u know right that calculators of different types gives different value if u don't know then Google it

    • @kelw5787
      @kelw5787 6 років тому +1

      Yeah I calculated this as well and when I heard it was 5.0 x 10-2 I was confused about what I did wrong xD

    • @rahullovesthepayne8690
      @rahullovesthepayne8690 6 років тому +1

      i thought i was the only one lol

  • @vicentesayson2990
    @vicentesayson2990 4 роки тому

    Good day sir, is the molar coefficient is a constant given per chemical substance or it's something that we can compute too?
    I am wondering how am I be able to get the Molar Coefficient of unknown Species and Unknown Concentration, that is present in the water for example lake. This is for spectrophotometer experiment, I can only get the Absorbance and Transmittance but not the
    Concentration and Molar Coefficient

    • @AliHayek
      @AliHayek  4 роки тому

      In your case you will not be able to determine the concentration or molar extinction coefficient. You will need one of them known to determine the other.

  • @ericmanso7355
    @ericmanso7355 7 років тому +1

    nice

  • @Edmerls
    @Edmerls 5 років тому +1

    Nice

  • @alokneet
    @alokneet 6 років тому +1

    You are doing excellent job. A little humor will make it perfect.
    Can you tell me what software you are using for making these videos.

    • @AliHayek
      @AliHayek  6 років тому

      +BioMania thank you. I use screenflow

  • @sanaafreen1937
    @sanaafreen1937 6 років тому

    At 2:54 % transmittance is denoted as %T and also in last line as A. Didn't get it. Please explain

    • @AliHayek
      @AliHayek  6 років тому

      If you read carefully the last line says that the absorbance (A) can be given in terms of (%T) and the expression is given. I hope this helps.

  • @ipekkocaoglu9482
    @ipekkocaoglu9482 4 роки тому

    Hello the video is wonderful.
    I can not understand one thing which is when we look the transmittance vs wavelenght graph, why do we observe this shape or when we look the absorption vs wavelenght graph, why do we observe this shape?
    Thank you so much

    • @AliHayek
      @AliHayek  4 роки тому +1

      The best way to think about it is that for the absorption spectrum, the higher the intensity of the peak, the more the light is being absorbed by the solution. Now if you think about it in terms of transmittance. The more the light is absorbed, the less of it will transmit. So transmittance measures how much light is going through the solution. So the lower the peak, the lower the percentage of light transmitted. In a simpler way, the transmittance spectrum is the opposite of the absorption spectrum. I hope it is clear now.

  • @knowledgejunction1643
    @knowledgejunction1643 5 років тому

    Suuuupppppeerrrrr

  • @whats1983
    @whats1983 2 роки тому

    I am watching from Uzbekistan. How can I contact you?

    • @AliHayek
      @AliHayek  Рік тому

      Go to www.alihayek.com. 👍

  • @v.c.jayaramaiah4815
    @v.c.jayaramaiah4815 2 роки тому

    more simple calculation of perceent transmittance or OD vaalues in to Percentage will be more useful for basic chemistry students, videos explainigncalculations msy not be available

  • @premalathagattu907
    @premalathagattu907 3 роки тому

    Sir how find (£)coficiant value
    Please reply

    • @AliHayek
      @AliHayek  3 роки тому

      This is explained in details by the end of the video. This is the only way to find epsilon. Good luck.

    • @premalathagattu907
      @premalathagattu907 3 роки тому

      @@AliHayek thank you sir it is very useful video

  • @kourosh61
    @kourosh61 7 років тому +1

    Answer is 5 x 10^-3

  • @PHYSICSINSIGHT
    @PHYSICSINSIGHT 4 роки тому

    watch this uv visible spectroscopy is explained very briefly...
    @

  • @nouralrefahi6000
    @nouralrefahi6000 5 років тому +1

    بس لو بالعربي كان فهمت

  • @alysonbechtum6999
    @alysonbechtum6999 5 років тому

    :)

  • @binteabdul6107
    @binteabdul6107 5 років тому

    tx for uploading very helpful