Pemdas says -15(c²+2c+1)=-20/3 c²+2c+1=4/9 c²+2c+5/9=0 1 1 1 5 3 3 factoring so (c+1/3)(c+5/3)=0 c=-1/3 or -5/3 okay ... I forgot the square root of both sides But this took me forever because I made mistakes and had to backtrack.
I did mostly the same, but got to (c+1)² = 4/9 much easier. Any time I see any equation that is basically -a = -b I know that a = b. Dealing with negatives throughout is just asking to make mistakes, so if you can remove them it'll make the process much simpler. So starting with multiplying both sides by -3 gives 45(c+1)² = 20 straight off the bat, then dividing both sides by 45 gives (c+1)² = 4/9 I did the rest the same way.
I completely missed the fact that this was a quadratic equation. I wasn't quite clear on what one was. I think I now have a better idea, thanks to this problem.
20/45 = (c+1) squared c + 1 = root (4/9) c = 2/3 - 1 or - 2/3 - 1 c = -1/3 or -5/3 I will say that the comments sections are annoying me as in forcing ppl to go one way as opposed to a blank page essentially how much space do i have to or is it ... you show steps i can squish it all together.... And as a side note how long would the previous be if the problem was more complex.....
A supplemental comment I will show an example like this x= ? so top down would x=? x=? x=? and so forth down (that is) a bulky page with lots of space..... so a compromise would be x=? x=? x=? x=? x=? x=? and so forth carry up So in the above manner it is easier to go sideways unless you paper solve it first......
Divide both sides of the equation by - 15 and then take the square root of (c + 1)^2 = sqr. rt. 4/9 = c + 1 = +/-- 2/3 = c = - 1/3 and c = - 1 2/3.
Pemdas says
-15(c²+2c+1)=-20/3
c²+2c+1=4/9
c²+2c+5/9=0
1 1 1 5
3 3
factoring so
(c+1/3)(c+5/3)=0
c=-1/3 or -5/3
okay ... I forgot the square root of both sides
But this took me forever because I made mistakes and had to backtrack.
I did mostly the same, but got to (c+1)² = 4/9 much easier.
Any time I see any equation that is basically -a = -b I know that a = b. Dealing with negatives throughout is just asking to make mistakes, so if you can remove them it'll make the process much simpler.
So starting with multiplying both sides by -3 gives 45(c+1)² = 20 straight off the bat, then dividing both sides by 45 gives (c+1)² = 4/9
I did the rest the same way.
so close... Simplified, took sqrt of both sides but forgot -(2/3)
I completely missed the fact that this was a quadratic equation. I wasn't quite clear on what one was. I think I now have a better idea, thanks to this problem.
(c+1)^2 = 20/45
(c+1)^2 = 4/9
Taking square roots we get:
Absolute value of (c+1) = 2/3
So, c = -1/3, or c = -5/3
20/45 = (c+1) squared c + 1 = root (4/9) c = 2/3 - 1 or - 2/3 - 1 c = -1/3 or -5/3 I will say that the comments sections are annoying me as in forcing ppl to go one way as opposed to a blank page essentially how much space do i have to or is it ... you show steps i can squish it all together.... And as a side note how long would the previous be if the problem was more complex.....
Wouldn't it have been quicker to divide both sides by-15 instead of Multiplying by 3 then having to move -45 over?
Got it right but had trouble checking it by putting solutions back into original equation.
I divided both sides with -15
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A supplemental comment I will show an example like this x= ? so top down would
x=?
x=?
x=? and so forth down
(that is) a bulky page with lots of space.....
so a compromise would be
x=? x=?
x=? x=?
x=? x=? and so forth
carry up
So in the above manner it is easier to go sideways unless you paper solve it first......
C = - 1/3.
+-2/4-1
+-2/3
👍☕✌️☕👍