Ouch, that's not a simplification of the rational expression, it is an unacceptable corruption of the expression - suddenly you can use c=0.2 without running into division by zero! What a shame. Where is the discussion about continuity and removable discontinuity??
30years out of high school and i have never implemented factoring in the real world... these complex math equations are solely for other countries not to think we are so poorly in math
@@garyalabama Both of my brothers are mechanicals and i am a power plant electrician so the only equation that makes sense to me is: (brother 1 salary) + (brother 2 salary) < brother 3 salary - c. Where “c” equals no college degree.
This was a good one. The only thing I'd suggest is swapping it round, show us the factoring technique with the simpler example. I factored the other way and when you showed us the method I paused and tried it on the denominator, and was a bit disappointed that it was so much simpler. If you'd showed us the technique on the easy one then I could trial it out on the more complicated one and see how I go.
Why not solving it with the quadratic equation ? You will get : c=4/3 and c=1/5 By further calculation you will see that c=1/5 is not possible, because you can't divide by zero. So the only possible answer for c=4/3. When you substitute c by 4/3, the nominator becomes zero, then the solution is zero. 0/number = 0
I had a very thick spoken German teacher for math. and not easy to here her, with some students who jabbered, between each other, and then the disruption of her asking them to be quiet. So many of us who had such classes like this, did not learn to take and interest in Math, but far worse for students who try, do well , but then there are the "IEP'S " students that do NOT have to do any work, and get a "C". If they apply themselves half way , they get an "A". TODAYS college now take more without really passing the SAT, but because they meat the WHAT"S NOW" ACCEPENCE, verses students who do not, but did well WITHOUT AN Y SPECIAL ADDVANTAGES GIVEN. do not get accepted, or get the jobs.
Greetings. The simplified result of the expression is ((3C-4)/(2C+1). We determine the result as follows, 15 times C raised to the 2nd power minus 23C plus 4 equals (3C-4)(5C-1) all divided by (5C-1)(2C+1). Thereafter (5C-1) in the numerator will cancel (5C-1) in the denominator leaving us with (3C-4)/(2C+1).
This brought back traumatic highschool homework memories from the late 80s🙂 I could get how to do the simpler stuff explained in class, then the homework that night would start throwing in the curve balls and I would be like ah daaaaaamn😐 Thanks for the good times Mr. Cole.
I don't remember learning the gcf technique where you split the middle term and factor. Very interesting. I was extensively tested on knowing primes and composites of numbers and could do this in my head.
First: the way you perform the factoring can only be applied in very special cases. In most of the situations you will not find the factors in this way. Second: the original expresion is undefined for c=1/5. Your answer has a well defined value for c=1/5 So without talking about dividing by zero (what you do if c=1/5). the method is incomplete, as is the answer. Please stop teaching these kind of incorrect, incomplete methods.
What in the world is “cross cancel”?????? When I taught high school math, I made sure that the students knew what was really happening - having the same factor in the numerator and denominator makes a “1.” For heaven’s sake, call it what it is!! Lose the nonsense words!!!!!
I have struggled with maths but the way TCM thoroughly explains problems makes perfect sense to me and I am now able to understand concepts I previously was dumbfounded by. Both explanations makes sense to me now but previously I might have got confused.
23:24 Aren't the two expressions different here? I believe the left expression has a hole at c = 1/5. The right expression does not.
Trying first without looking.
3C-4/2C+1
Ouch, that's not a simplification of the rational expression, it is an unacceptable corruption of the expression - suddenly you can use c=0.2 without running into division by zero! What a shame. Where is the discussion about continuity and removable discontinuity??
This is a good one.
30years out of high school and i have never implemented factoring in the real world... these complex math equations are solely for other countries not to think we are so poorly in math
Possibly, but there's a structure of the mind being created. Thinking can't be useless.
You must not be an engineer.
@@garyalabama Both of my brothers are mechanicals and i am a power plant electrician so the only equation that makes sense to me is: (brother 1 salary) + (brother 2 salary) < brother 3 salary - c. Where “c” equals no college degree.
@@borg590There are uTube "influencers" who make way more than you just for doing dumb things. Who needs knowledge?
Problem solving skills be dammed
I think it’s (3C-4)/(2C+1)
This was a good one. The only thing I'd suggest is swapping it round, show us the factoring technique with the simpler example. I factored the other way and when you showed us the method I paused and tried it on the denominator, and was a bit disappointed that it was so much simpler. If you'd showed us the technique on the easy one then I could trial it out on the more complicated one and see how I go.
Time to see how I did. I got (3c - 4 ) / (2c + 1) where c can NOT equal negative 1/2.
C also can NOT equal 1/5th. (I missed that one).
@andrewm6424 It also can not equal 4/3.
@@TheSimCaptainIt can. The term would equal 0 then. But you are not allowed to divide by 0.
@johanneschristopherstahle3395 That's why it can't equal 4/3.
you need a plumber, carpenter, electrician?????
Why not solving it with the quadratic equation ?
You will get : c=4/3 and c=1/5
By further calculation you will see that c=1/5 is not possible, because you can't divide by zero.
So the only possible answer for c=4/3.
When you substitute c by 4/3, the nominator becomes zero, then the solution is zero.
0/number = 0
UR hurting My brain; but I trust the Eval.
Because it is just a term. The goal is to simplify. No one said you should check for roots.
Some textbooks csll polynomials with 1 as leading coefficient monic polynomials.
Well, I need some factoring practice for sure. Not there yet but I don't give up. ;)
I was good until I got to 28*28. Couldn’t do it in my head but could do it in a calculator to get 8*784 = 6272
A great example. Made me think. Loved it. Thank You
Oh it helped me to realize how much I need to learn. Lmao
Well for a start remove the Alpha from it make sense then
I had a very thick spoken German teacher for math. and not easy to here her, with some students who jabbered, between each other, and then the disruption of her asking them to be quiet. So many of us who had such classes like this, did not learn to take and interest in Math, but far worse for students who try, do well , but then there are the "IEP'S " students that do NOT have to do any work, and get a "C". If they apply themselves half way , they get an "A". TODAYS college now take more without really passing the SAT, but because they meat the WHAT"S NOW" ACCEPENCE, verses students who do not, but did well WITHOUT AN Y SPECIAL ADDVANTAGES GIVEN. do not get accepted, or get the jobs.
Greetings. The simplified result of the expression is ((3C-4)/(2C+1). We determine the result as follows, 15 times C raised to the 2nd power minus 23C plus 4 equals (3C-4)(5C-1) all divided by (5C-1)(2C+1). Thereafter (5C-1) in the numerator will cancel (5C-1) in the denominator leaving us with (3C-4)/(2C+1).
Very nice and good to know
This brought back traumatic highschool homework memories from the late 80s🙂 I could get how to do the simpler stuff explained in class, then the homework that night would start throwing in the curve balls and I would be like ah daaaaaamn😐 Thanks for the good times Mr. Cole.
I don't remember learning the gcf technique where you split the middle term and factor. Very interesting. I was extensively tested on knowing primes and composites of numbers and could do this in my head.
I would have used the box method to factor those trinomials quickly.
Got it. Haven't had a class in over 20 years. Except these.
Too confusing
26 minutes
(c+1c-3) (c+1c-2)
3C-4 /2C+1
3C-4/2C+1
Thanks!
Ty for the refresh i saw the 5 right away from the get go.....
Ans. 3c-4/2c+1
41
✌😂✌C= 1/5 , c = 5✌ 😂✌
Got it!
First: the way you perform the factoring can only be applied in very special cases. In most of the situations you will not find the factors in this way.
Second: the original expresion is undefined for c=1/5. Your answer has a well defined value for c=1/5
So without talking about dividing by zero (what you do if c=1/5). the method is incomplete, as is the answer.
Please stop teaching these kind of incorrect, incomplete methods.
It took him 20 minutes to do one problem. How can he expect students to handle 8 or 10 of these problems in a thirty-minute exam??
FR THATS WHAT I SAY
@@aquaticanimations9789 Likely, one prob for homework. Certainly not 9 probs on a test.
@@aquaticanimations9789That's how teaching works. It takes a lot longer to explain than to do.
If you do this in an exam, be sure to mark that c is not allowed to be 1/5, because you would run into a division by 0.
Never did the multiplication step before. (15*4) - thanks for the tip!
What in the world is “cross cancel”?????? When I taught high school math, I made sure that the students knew what was really happening - having the same factor in the numerator and denominator makes a “1.” For heaven’s sake, call it what it is!! Lose the nonsense words!!!!!
What is an ex High School math teacher doing here? A lot of us are trying to get away from you clowns via the Net. The damage y'all caused...
I have struggled with maths but the way TCM thoroughly explains problems makes perfect sense to me and I am now able to understand concepts I previously was dumbfounded by. Both explanations makes sense to me now but previously I might have got confused.