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If you divide by 2 5 times you get an odd number which tells you that 2^{a-5}=1 or 2^{b-5}=1. This means either a=5 or b=5. Computing 2^5=32 makes it obvious that a=5 cannot work as 32
Excellent approach 👏
2^a - 2^b. = 2⁵ . 63On simplifie par 2⁵2^(a-5) - 2^(b-5). = 63 = 64 - 1 =. 2⁶ - 2⁰D' où a-5 = 6, donc a = 11b-5 = 0, donc b = 5
Nice one 👏
If you divide by 2 5 times you get an odd number which tells you that 2^{a-5}=1 or 2^{b-5}=1. This means either a=5 or b=5. Computing 2^5=32 makes it obvious that a=5 cannot work as 32
Excellent approach 👏
2^a - 2^b. = 2⁵ . 63
On simplifie par 2⁵
2^(a-5) - 2^(b-5). = 63 = 64 - 1
=. 2⁶ - 2⁰
D' où a-5 = 6, donc a = 11
b-5 = 0, donc b = 5
Nice one 👏